Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{49}{45}=\frac{45+4}{45}=\frac{45}{45}+\frac{4}{45}=1+\frac{4}{45}\)
\(\frac{61}{57}=\frac{57+4}{57}=\frac{57}{57}+\frac{4}{57}=1+\frac{4}{57}\)
Vì \(\frac{4}{45}>\frac{4}{57}\)
Nên \(1+\frac{4}{45}>1+\frac{4}{57}\)
Vậy \(\frac{49}{45}>\frac{61}{57}\)
\(\frac{49}{45}=1+\frac{4}{45}\)
\(\frac{61}{57}=1+\frac{4}{57}\)
\(\Rightarrow\frac{49}{45}>\frac{61}{57}\)
Ta có: 12/13 = 1 - 1/13
13/14 = 1 - 1/14
Vì 1/13 > 1/14 nên 12/13 < 13/14
23,45<34,99;102,567>102,49
99,78>99,12;78,56=78,560
Bài 2,
3,45;4,3;5,6;5,9;102,609
a) \(\dfrac{12}{14}=\dfrac{1200}{1400}=\dfrac{1400-200}{1400}=1-\dfrac{200}{1400}\)
\(\dfrac{1212}{1414}=\dfrac{1414-200}{1414}=1-\dfrac{200}{1414}\)
vì \(\dfrac{200}{1414}< \dfrac{200}{1400}\)
Nên \(1-\dfrac{200}{1400}< 1-\dfrac{200}{1414}\)
Vậy \(\dfrac{12}{14}< \dfrac{1212}{1414}\)
Các bài sau tương tự
\(\frac{11}{15}=\frac{15-4}{15}=1-\frac{4}{15}\)
\(\frac{145}{149}=\frac{149-4}{149}=1-\frac{4}{149}\)
Có \(\frac{4}{15}>\frac{4}{149}\)suy ra \(\frac{11}{15}< \frac{145}{149}\).
A , 34 - \(\dfrac{x}{30}\) = \(\dfrac{5}{6}\)
\(\dfrac{x}{30}\) = 34 - \(\dfrac{5}{6}\)
\(\dfrac{x}{30}=\) \(\dfrac{199}{6}\)
\(\dfrac{x}{30}=\) \(\dfrac{995}{30}\)
x = 995
B x +\(\dfrac{13}{34}\) = \(\dfrac{12}{17}\)
x = \(\dfrac{12}{17}-\dfrac{13}{34}\)
x = \(\dfrac{11}{34}\)
\(\dfrac{7}{9}=\dfrac{21}{27};\dfrac{7}{10}=\dfrac{21}{30}\)
hai số nằm giữa \(\dfrac{7}{9}\) và \(\dfrac{7}{10}\)
\(\dfrac{21}{27}>\dfrac{21}{28}>\dfrac{21}{29}>\dfrac{21}{30}\)
a)\(\frac{14}{15}\) < \(\frac{15}{21}\)
b)\(\frac{101}{200}\) < \(\frac{200}{404}\)
c)\(\frac{1995}{2011}\) >\(\frac{1993}{2012}\)
12/49=0,2444.........
14/45=0,31..........
=> 12/ 49< 14/45
Ta có: 12/49<12/45 mà 14/45>12/45
nên 12/49<14/45