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x:2=y:(-5)
\(\Rightarrow\frac{x}{-5}=\frac{y}{2}\)và x-y=-7
Áp dụng tính chất của dãy tỉ số bằng nhau ta có :
\(\Rightarrow\frac{x}{-5}=\frac{y}{2}=\frac{x-y}{-5-2}=\frac{-7}{-7}=1\)
Suy ra:x=-5.1=-5
y=2.1=2
Vậy:x=-5;y=2
Tìm x biết:
\(\frac{-12}{13}x-5=\frac{79}{13}\Rightarrow\frac{-12}{13}x=\frac{79}{13}+5\Rightarrow\frac{-12}{13}x=\frac{79}{13}+\frac{65}{13}\Rightarrow\frac{-12}{13}x=\frac{144}{13}\Rightarrow x=\frac{144}{13}:\frac{-12}{13}\Rightarrow x=\frac{144}{13}.\frac{13}{-12}=\frac{12}{1}.\frac{1}{-1}=\frac{12}{-1}=-12\)
tính :
\(\frac{5^4.20^4}{25^5.4^5}=\frac{\left(5.20\right)^4}{\left(25.4\right)^5}=\frac{100^4}{100^5}=\frac{1}{100}\)
so sánh các số: \(2^{150}\)và \(3^{100}\)
\(2^{150}=\left(2^{50}\right)^{100}\)
\(3^{100}=\left(3\right)^{100}\)\(\Rightarrow2^{50}va3\Rightarrow2^{150}>3^{100}\)
a) \(\frac{1}{-2}< \frac{-1}{3}\)
b) \(-\frac{2}{3}< 0\)
c) \(-0,125=-\frac{1}{8}=\frac{1}{-8}\)
d) \(-\frac{1}{7}=-\frac{5.1}{5.7}=-\frac{5}{35}=-\frac{5}{35}\)
Ta có : \(\left(x-3\right)^2\ge0\forall x\)
\(\left|y^2-25\right|\ge0\forall x\)
Mà : \(\left(x-3\right)^2+\left|y^2-25\right|=0\)
Nên : \(\hept{\begin{cases}\left(x-3\right)^2=0\\\left|y^2-25\right|=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x-3=0\\y^2-25=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=3\\y^2=25\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=3\\y=-5;5\end{cases}}\)
Ta có : 3300 = (33)100 = 27100
5200 = (52)100 = 25100
Vì : 27100 > 25100
Nên : 3300 > 5200
\(x=\dfrac{2}{-5}=\dfrac{-2\times13}{5\times13}=\dfrac{-26}{65}\)
\(y=\dfrac{-3}{13}=\dfrac{-3\times5}{13\times5}=-\dfrac{15}{65}\)
Do \(\dfrac{26}{65}>\dfrac{15}{65}\) nên \(-\dfrac{26}{65}< -\dfrac{15}{65}\)
Vậy \(x< y\)
\(\dfrac{2}{-5}=\dfrac{-2}{5}=\dfrac{-26}{65}\)
\(\dfrac{-3}{13}=\dfrac{-15}{65}\)
mà -26<-15
nên x<y