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a) \(\dfrac{8}{9}< 1;\dfrac{13}{7}>1\Rightarrow\dfrac{8}{9}< \dfrac{13}{7}\)
b) \(\dfrac{16}{27}>\dfrac{15}{27}>\dfrac{15}{29}\Rightarrow\dfrac{16}{27}>\dfrac{15}{29}\)
C1: 6/7<1<7/6
C2: 6/7=36/42
7/6=49/42
mà 36<49
nên 6/7<7/6
a)
\(\dfrac{6}{12}=\dfrac{6:6}{12:6}=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2}=\dfrac{1\times2}{2\times2}=\dfrac{2}{4}\)
Mà \(\dfrac{2}{4}< \dfrac{3}{4}\)
Vậy \(\dfrac{6}{12}< \dfrac{3}{4}\).
b)
\(\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\)
Mà \(\dfrac{2}{5}< \dfrac{4}{5}\)
Vậy \(\dfrac{2}{5}< \dfrac{8}{10}\).
c)
\(\dfrac{40}{35}=\dfrac{40:5}{35:5}=\dfrac{8}{7}\)
Mà \(\dfrac{8}{7}>\dfrac{6}{7}\)
Vậy \(\dfrac{40}{35}>\dfrac{6}{7}\).
d)
\(\dfrac{8}{16}=\dfrac{8:8}{16:8}=\dfrac{1}{2}\)
Mà \(\dfrac{1}{2}< \dfrac{5}{2}\)
Vậy \(\dfrac{8}{16}< \dfrac{5}{2}\).
232323/434343=23/43=161/301
6/7=258/301
mà 161<258
nên 232323/434343<6/7