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Ta có:
\(\dfrac{1}{2}=0,5\)
\(\dfrac{2}{3}=0,666...\)
\(\dfrac{3}{4}=0,75\)
\(\dfrac{5}{4}=1,25\)
Sắp xếp theo thứ tự từ lớn đến bé là:
\(\dfrac{5}{4};\dfrac{3}{4};\dfrac{2}{3};\dfrac{1}{2}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(1\frac{1}{2};1\frac{1}{3};1\frac{1}{4};1\frac{1}{5};1\frac{1}{6};1\frac{1}{7};1\frac{1}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
Vì \(\frac{1}{2}>\frac{1}{3}>\frac{1}{4}>\frac{1}{5}>\frac{1}{6}>\frac{1}{7}>\frac{1}{8}\)
=> \(1\frac{1}{2}>1\frac{1}{3}>1\frac{1}{4}>1\frac{1}{5}>1\frac{1}{6}>1\frac{1}{7}>1\frac{1}{8}\)
Hay \(\frac{3}{2}>\frac{4}{3}>\frac{5}{4}>\frac{6}{5}>\frac{7}{6}>\frac{8}{7}>\frac{9}{8}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)\(\frac{3}{2};\frac{4}{3};\frac{5}{4};\frac{6}{5};\frac{7}{6};\frac{8}{7};\frac{9}{8}\)
\(\frac{3}{4}< \frac{3}{2}< \frac{5}{3}< \frac{5}{2}< \frac{6}{1}< \frac{29}{4}\)
`MSC:12`
`1/3 = (1xx4)/(3xx4)= 4/12`
`3/2=(3xx6)/(2xx6)=18/12`
`5/6=(5xx2)/(6xx2)=10/12`
`3/4=(3xx3)/(4xx3)=9/12`
`-> 4/12; 9/12; 10/12;18/12`
`->1/3; 3/4;5/6;3/2`
có `1/3=4/12`
`3/2=18/12`
`5/6=10/12`
`3/4=9/12`
vì `4<9<10<18`
`=>4/12<9/12<10/12<18/12`
`=>1/3<3/4<5/6<3/2`
`=>` sắp xếp: `1/3;3/4;5/6;3/2`
\(\dfrac{8}{9};\dfrac{7}{8};\dfrac{6}{7};\dfrac{5}{6};\dfrac{4}{5};\dfrac{3}{4};\dfrac{2}{3};\dfrac{1}{2}\)