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\(A=x+\left\{\left(x+5\right)-\left[\left(5-x\right)-\left(-x-3\right)\right]\right\}\)
\(=x+\left\{\left(x+5\right)-\left[5-x+x+3\right]\right\}\)
\(=x+\left\{\left(x+5\right)-\left(5+3\right)\right\}\)
\(=x+\left\{\left(x+5\right)-8\right\}\)
\(=x+\left\{x+5-8\right\}=x+\left\{x-3\right\}\)
\(=x+x-3=2x-3\)
\(B=x.\left\{\left[-x-2-\left[x+\left(3-x\right)-\left(x+3\right)\right]\right]\right\}\)
\(=x.\left\{\left[-x-2-\left[x+3x-x-x-3\right]\right]\right\}\)
\(=x\left\{\left[-x-2-\left(4x-2x-3\right)\right]\right\}\)
\(=x\left\{\left[-x-2-\left(2x-3\right)\right]\right\}\)
\(=x\left\{-x-2-2x+3\right\}\)
\(=x\left(1-3x\right)=x-3x^2\)
1.
Ix+1I + I2x+2I =3
Ix+1I và I2x+2I thuộc N
=> x thuộc N
x+1+2x+2=3
3x+1+2=3
3x = 3-1-2
3x = 0
x = 0:3
x = 0
a)A = |x| + x=x+x=2x
b)B=|x|-x=x-x=0
a) TH1: x < 0 ; ta có:
\(A=\left|x\right|+x=\left(-x\right)+x=0\)
TH2: \(x\ge0\); ta có:
\(A=\left|x\right|+x=x+x=2x\)
b)TH1: x < 0 ; ta có:
\(B=\left|x\right|-x=\left(-x\right)-x=-2x\)
TH2: \(x\ge0\); ta có:
\(B=\left|x\right|-x=x-x=0\)
c) TH1: x < 3 ; ta có:
\(C=3\left(x-1\right)-2\left|x-3\right|=3x-3-2\left(3-x\right)\)
\(=3x-3-6+2x=5x-9\)
TH2: \(x\ge3\); ta có:
\(C=3x-3-2\left(x-3\right)=3x-3-2x+6=x+3\)