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Câu 1:
MSC=60
7/10=7.6/10.6=42/60 5/-12=-5/12=-5.5/12.5=-25/60
Câu 2:
17/34=1/2; -12/22=-6/11; -25/35=-5/7; 125/75=5/3
Câu 3:
MSC=24
1/3=1.8/3.8=8/24 -3/8=-3.3/8.3=-9/24 17/24=17/24
a) Ta có: \(12 = 2^2 . 3; 15 = 3.5\)
\(BCNN(12, 15) = 2^2.3.5 = 60\) nên chọn mẫu chung là 60.
\(\begin{array}{l}\frac{9}{{12}} = \frac{{9.5}}{{12.5}} = \frac{{45}}{{60}}\\\frac{7}{{15}} = \frac{{7.4}}{{15.4}} = \frac{{28}}{{60}}\end{array}\)
b) Ta có: \(10 = 2.5; 4 = 2^2; 14=2.7\)
\(BCNN(10, 4, 14) =2^2.5.7= 140\) nên chọn mẫu chung là 140.
\(\begin{array}{l}\frac{7}{{10}} = \frac{{7.14}}{{10.14}} = \frac{{98}}{{140}}\\\frac{3}{4} = \frac{{3.35}}{{4.35}} = \frac{{105}}{{140}}\\\frac{9}{{14}} = \frac{{9.10}}{{14.10}} = \frac{{90}}{{140}}\end{array}\)
a; \(\dfrac{-12}{30}\) = \(\dfrac{-2}{5}\) = \(\dfrac{-2.4}{5.4}\) = \(\dfrac{-8}{20}\)
\(\dfrac{18}{-40}\) = \(\dfrac{9}{20}\)
b; \(\dfrac{-12}{81}\) = \(\dfrac{-4}{27}\); \(\dfrac{36}{64}\) = \(\dfrac{9}{16}\); \(\dfrac{25}{-10}\) = \(\dfrac{-5}{2}\)
27 = 33; 16 = 24; 2 = 2
BCNN(27; 16; 2) = 24.33= 432
\(\dfrac{-12}{81}\) = \(\dfrac{-4}{27}\) = \(\dfrac{-4.16}{27.16}\) = \(\dfrac{-64}{432}\)
\(\dfrac{36}{64}\) = \(\dfrac{9}{16}\) = \(\dfrac{9.27}{16.27}\) = \(\dfrac{243}{432}\)
\(\dfrac{25}{-10}\) = \(\dfrac{-5}{2}\)= \(\dfrac{-5.216}{2.216}\) = \(\dfrac{-1080}{432}\)
a/
Mẫu chung của các phân số trên là: 228
Ta có:
\(\frac{1}{2}=\frac{1.114}{2.114}=\frac{114}{228}\)
\(\frac{1}{3}=\frac{1.76}{3.76}=\frac{76}{228}\)
\(\frac{1}{38}=\frac{1.6}{38.6}=\frac{6}{228}\)
\(\frac{-1}{12}=\frac{-1.19}{12.19}\frac{-19}{228}\)
Vậy quy đồng mẫu 4 phân số \(\frac{1}{2};\frac{1}{3};\frac{1}{38};\frac{-1}{12}\)ta được: \(\frac{114}{228};\frac{76}{228};\frac{6}{228};\frac{-19}{228}\).
b/
Ta có:
\(\frac{9}{30}=\frac{9:3}{30:3}=\frac{3}{10}\)
\(\frac{98}{80}=\frac{98:2}{80:2}=\frac{49}{40}\)
\(\frac{15}{1000}=\frac{15:5}{1000:5}=\frac{3}{200}\)
Các phân số phải quy đồng là: \(\frac{3}{10};\frac{49}{40};\frac{3}{200}\)
Mẫu chung của 3 phân số trên là: 200
Ta có:
\(\frac{3}{10}=\frac{3.20}{10.20}=\frac{60}{200}\)
\(\frac{49}{40}=\frac{49.5}{40.5}=\frac{245}{200}\)
Giữ nguyên\(\frac{3}{200}\)
Vậy sau khi rút gọn và quy đồng mẫu 3 phân số \(\frac{9}{30};\frac{98}{80};\frac{15}{1000}\)ta được: \(\frac{60}{200};\frac{245}{200};\frac{3}{200}\).
#chúcbạnhọctốt#
a: \(\dfrac{-7}{15}=\dfrac{-7\cdot4}{15\cdot4}=\dfrac{-28}{60}\)
\(\dfrac{5}{12}=\dfrac{5\cdot5}{12\cdot5}=\dfrac{25}{60}\)
b: \(\dfrac{1}{5}=\dfrac{1\cdot6}{5\cdot6}=\dfrac{6}{30}\)
\(\dfrac{-2}{3}=\dfrac{-2\cdot10}{3\cdot10}=\dfrac{-20}{30}\)
\(\dfrac{7}{10}=\dfrac{7\cdot3}{10\cdot3}=\dfrac{21}{30}\)
c: \(\dfrac{-15}{50}=\dfrac{-15\cdot3}{50\cdot3}=\dfrac{-45}{150}\)
\(\dfrac{9}{10}=\dfrac{9\cdot15}{10\cdot15}=\dfrac{135}{150}\)
\(\dfrac{26}{-30}=\dfrac{-26}{30}=\dfrac{-26\cdot5}{30\cdot5}=\dfrac{-130}{150}\)
d: \(\dfrac{7}{10}=\dfrac{7\cdot51}{10\cdot51}=\dfrac{357}{510}\)
\(\dfrac{-5}{-15}=\dfrac{1}{3}=\dfrac{1\cdot170}{3\cdot170}=\dfrac{170}{510}\)
\(\dfrac{3}{17}=\dfrac{3\cdot30}{17\cdot30}=\dfrac{90}{510}\)
e: \(\dfrac{-4}{-75}=\dfrac{4}{75}=\dfrac{4}{75}\)
\(\dfrac{-3}{5}=\dfrac{-3\cdot15}{5\cdot15}=\dfrac{-45}{75}\)
\(\dfrac{8}{25}=\dfrac{8\cdot3}{25\cdot3}=\dfrac{24}{75}\)
f: \(-\dfrac{4}{5}=\dfrac{-4\cdot7}{5\cdot7}=\dfrac{-28}{35}\)
\(\dfrac{6}{7}=\dfrac{6\cdot5}{7\cdot5}=\dfrac{30}{35}\)
+)
\(\frac{1}{2}=\frac{6}{12};\frac{1}{3}=\frac{4}{12};-\frac{1}{12}\)
+)
\(\frac{9}{30}=\frac{3}{10}=\frac{12}{40};\frac{98}{80}=\frac{49}{40}\)
1/2=6/12 1/3=4/12 -1/12=-1/12
9/30=3/10 98/80=49/40
3/10=12/40 49/40=49/40
\(\frac{-9}{12}+\left(-10\right)\)
\(=\frac{-9}{12}-\frac{10}{1}=\frac{-9}{12}-\frac{120}{12}=\frac{-9-120}{12}\)
\(=\frac{-129}{12}\)