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q = (1/99+12/999+123/999)*(1/2-1/3-1/6)
= (1/99+12/999+123/999) * 0
= 0
Q=(1/99+12/999+123/999)x(1/6-1/6)
Q=(1/99+12/999+123/999)x0
Q=0
học tốt!
Có: \(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(=\left(\frac{1}{2}+\frac{12}{999}+\frac{123}{999}\right).\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)
\(=\left(\frac{1}{2}+\frac{12}{999}+\frac{123}{999}\right).0=0\)
( 1/99 + 12/999 + 123/999 ) . ( 1/2 - 1/3 - 1/6 )
= ( 1/99 + 12/999 + 123/999 ) . 0
= 0 nha bn
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right)0=0\)
A=(1/99+12/999+123/999)x(1/2-1/3-1/6)
=(1/99+12/999+123/999)x(3/6-2/6-1/6)
=(1/99+12/999+123/999)x0
=0
Q=(1/99+12/999+123/999)x0
Q=0
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\))
\(Q=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).0=0\)