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15 x 5 x 3 x ( 18 x 32 - 8 x 32 - 10 x 32 )
= 15 x 5 x 3 x { 18 - 8 - 10 } x 32 }
= 15 x 5 x 3 x 0
= 0
Vì số nào nhân với 0 cx bằng 0
15 x 5 x 3 x ( 32 x (18-8-10)
15 x 5 x 3 x(32 x 0 )
15 x 5 x 3 0 = 0
h nha
\(32\times25+18\times100-50\times12\)
\(=800+1800-600\)
\(=2000\)
\(56\times45+28\times98+56\times6\)
\(=2520+2744+336\)
\(=5600\)
32 x 25 + 18 x 100 - 50 x 12 = 32 x 25 + 18 x 4 x 25 - 25 x 2 x 12
= 32 x 25 + 72 x 25 - 25 x 24
= ( 32 + 72 - 24 ) x 25
= 80 x 25
= 2000
56 x 45 + 28 x 98 + 56 x 6 = 56 x 45 + 28 x 2 x 49 + 56 x 6
= 56 x 45 + 56 x 49 + 56 x 6
= 56 x ( 45 + 49 + 6 )
= 56 x 100
= 5600
B)x+36=98
X=98-36
X=62
C)58-x+32=45
58-x=45-32
58-x=13
X=58-13
X=45
a) 36x - 54 = 18
36x = 18 + 54
36x = 72
x = 2
b) x + 36 = 98
x = 98 - 36
x = 62
c) 58 - x + 32 = 45
58 - x = 45 - 32
58 - x = 13
x = 58 - 13
x = 45
d, X/8*32+X/3*18-X/5*10=120
X*32/8+X*18/3-X*10/5=120
32X/8+18X/3-10X/5=120
4X+6X-2X=120
8X=120
X=120/8
X=15
a: \(=\dfrac{18}{51}\cdot\dfrac{34}{9}\cdot\dfrac{17}{18}=\dfrac{17}{51}\cdot\dfrac{34}{9}=\dfrac{1}{3}\cdot\dfrac{34}{9}=\dfrac{34}{27}\)
b: \(=\dfrac{21}{32}\cdot\dfrac{4}{7}\cdot25\cdot\dfrac{4}{5}=\dfrac{21}{7}\cdot\dfrac{4}{32}\cdot20=60\cdot\dfrac{1}{8}=\dfrac{15}{2}\)
Ta có:\(x.\frac{1}{5}+x.\frac{4}{5}=2\)
=>\(x.\frac{1}{5}+\frac{4}{5}=2\)
=>\(x.\frac{5}{5}=2\)
=>\(x.1=2\)
=>\(x=2:1\)
=>\(x=2\)
Bài giải
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
a, \(\frac{4}{5}-\frac{2}{3}+\frac{1}{5}-\frac{1}{3}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)-\left(\frac{2}{3}+\frac{1}{3}\right)=1-1=0\)
b, \(\frac{2}{5}\text{ x }\frac{7}{4}-\frac{2}{5}\text{ x }\frac{3}{7}\)
\(=\frac{2}{5}\text{ x }\left(\frac{7}{4}-\frac{3}{7}\right)=\frac{2}{5}\text{ x }\frac{37}{28}=\frac{37}{70}\)
c, \(\frac{13}{4}\text{ x }\frac{2}{3}\text{ x }\frac{4}{13}\text{ x }\frac{3}{12}=\frac{13\text{ x }2\text{ x }4\text{ x }3}{4\text{ x }3\text{ x }13\text{ x }12}=\frac{1}{6}\)
d, \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\frac{3}{4}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}\)
\(=\left(\frac{3}{4}+\frac{1}{4}\right)+\left(\frac{18}{21}+\frac{3}{21}\right)+\left(\frac{19}{32}+\frac{13}{32}\right)\)
\(=1+1+1\)
\(=3\)
e, \(\frac{2}{5}+\frac{6}{9}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{2}{5}+\frac{2}{3}+\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1}{5}\left(2+3\right)+\frac{1}{3}\left(2+1\right)+\frac{1}{4}\left(3+1\right)\)
\(=\frac{1}{5}\cdot5+\frac{1}{3}\cdot3+\frac{1}{4}\cdot4\)
\(=1+1+1\)
\(=3\)
1 ) 3 x ( 4 + ? ) = 18
<=> 4 + ? = 18 : 3
<=> 4 + ? = 6
<=> ? = 6 - 4
=> ? = 2
2 ) 32 x 78 + 32 x 22
= 32 x ( 78 + 22 )
= 32 x 100
= 3200
3 x ( 4 + ? ) = 18
4 + ? = 18 : 3
4 + ? = 6
? = 6 - 4
? = 2
tính nhanh
32 x 78 + 32 x 22
= 78 x ( 32 + 22 )
= 78 x 54
= 4212
=9/4x2/3+16/9x4/3
=18/12+64/36
=54/36+64/36=118/36=59/18
x*32+x+x*18=4539
<=>x*(32+1+18)=4539
<=>x*51=4539
<=> x=89
Vậy x=89
\(x\times32+x+x\times18=4539\)
\(x\times32+x\times18+x=4539\)
\(x\times32+x\times18+x\times1=4539\)
\(x\times\left(32+18+1\right)=4539\)
\(x\times51=4539\)
\(\Rightarrow x=4539:51=89\)