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a)<=>2/7:(13/24+5/24) b)<=>15/24-9/24-4/24 c)=7.5.39/13.14.15
<=>2/7:3/4 <=>2/24=1/12 =3/2.3
<=>2/7x4/3 =1/2
<=>8/21
a. \(\frac{2}{7}:\frac{13}{24}+\frac{2}{7}:\frac{5}{24}\)
= \(\frac{2}{7}:\left(\frac{13}{24}+\frac{5}{24}\right)\)
= \(\frac{2}{7}:\frac{3}{4}\)
= \(\frac{8}{21}\)
b. \(\frac{15}{24}-\frac{3}{8}-\frac{1}{6}\)
= \(\frac{15}{24}-\frac{9}{24}-\frac{4}{24}\)
= \(\frac{2}{24}=\frac{1}{12}\)
c. \(\frac{7}{13}.\frac{5}{14}.\frac{39}{15}\)
= \(\frac{7.5.3.13}{13.2.7.3.5}\)
= \(\frac{1}{2}\)
\(S=\frac{1}{2.4}+\frac{1}{4.6}+...+\frac{1}{20.22}\)
\(2S=\frac{2}{2.4}+\frac{2}{4.6}+...+\frac{2}{20.22}\)
\(2S=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{20}-\frac{1}{22}\)
\(2S=1-\frac{1}{22}=\frac{21}{22}\)
\(S=\frac{21}{22}:2=\frac{21}{44}\)
Đặt biểu thức trên là A ta có:
A = \(\frac{1}{3}\)+ \(\frac{1}{6}\)+ \(\frac{1}{12}\)+ \(\frac{1}{24}\)+ \(\frac{1}{48}\)+ \(\frac{1}{96}\)
A x 3 = \(1\)+ \(\frac{1}{2}\)+ \(\frac{1}{4}\)+ \(\frac{1}{8}\)+ \(\frac{1}{16}\)+ \(\frac{1}{32}\)
A x 3 = \(1\)+ \(1\)- \(\frac{1}{2}\)+ \(\frac{1}{2}\)- \(\frac{1}{4}\)+ \(\frac{1}{4}\)- \(\frac{1}{8}\)+ \(\frac{1}{8}\)- \(\frac{1}{16}\)+ \(\frac{1}{16}\)- \(\frac{1}{32}\)
A x 3 = 2 - \(\frac{1}{32}\)= \(\frac{63}{32}\)
A = \(\frac{63}{32}\): 3 = \(\frac{63}{96}\)
a) \(\frac{15}{16}:\frac{25}{24}=\frac{15}{16}.\frac{24}{25}=\frac{9}{10}\)
b) \(10:\frac{5}{3}=10.\frac{3}{5}=6\)
c) \(\frac{5}{3}:10=\frac{5}{3}.\frac{1}{10}=\frac{5}{30}=\frac{1}{6}\)
a. \(\frac{15}{16}:\frac{25}{24}=\frac{15}{16}.\frac{24}{25}=\frac{9}{10}\)
b. \(10:\frac{5}{3}=10.\frac{3}{5}=6\)
c. \(\frac{5}{3}:10=\frac{5}{3}.\frac{1}{10}=\frac{1}{6}\)
\(\frac{24.27-23}{24+47.23}=\frac{648-23}{24+1081}=\frac{625}{1105}=\frac{125}{221}\)
_Học_tốt_
=^.^=
\(\frac{24.27-23}{24+47.23}\\ =\frac{\left(23+1\right).27-23}{23+1+47.23}\\ =\frac{23.27+27-23}{23.\left(47+1\right)+1}\\ \)