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a) Ta có: \(14-\left(5-8\right)^3+\left(-3\right)\cdot5\)
\(=14+27-15=26\)
b) Ta có: \(-7\cdot15+7\cdot\left(-35\right)+\left(-1\right)^{2019}\)
\(=-7\left(15+35\right)-1=-350-1=-351\)
c) Ta có: \(-18\cdot32+\left(-18\right)\cdot45+77\cdot\left(-32\right)-77\cdot50\)
\(=-18\left(32+45\right)+77\left(-32-50\right)\)
\(=-18\cdot77+77\cdot\left(-82\right)=77\left(-18-82\right)=77\cdot\left(-100\right)=-7700\)
d) Ta có: \(104-4\cdot\left[-5\cdot8+\left(7-10\right)^3\right]\)
\(=104-4\left[-40-27\right]=104-4\cdot\left(-67\right)=104+268=372\)
a) $3^8:3^6=3^{8-6}=3^2$
$19^7:19^3=19^{7-3}=19^4$
$2^{10}:8^3=2^{10}:(2^3)^3=2^{10}:2^9=2^{10-9}=2^1$
$12^7:6^7=(12:6)^7=2^7$
$27^5:81^3=(3^3)^5:(3^4)^3=3^{15}:3^{12}=3^{15-12}=3^3$
b) $10^6:10=10^{6-1}=10^5$
$5^8:25^2=5^8:(5^2)^2=5^8:5^4=5^{8-4}=5^4$
$4^9:64^2=4^9:(4^3)^2=4^9:4^6=4^{9-6}=4^3$
$2^25:32^4=2^{25}:(2^5)^4=2^{25}:2^{20}=2^{25-20}=2^5$
$18^3:9^3=(18:9)^3=2^3$
\(\cdot3^8:3^6=3^{8-6}=3^2\)
\(\cdot19^7:19^3=19^{7-3}=19^4\)
\(\cdot2^{10}:8^3=2^{10}:\left(2^3\right)^3=2^{10}:2^9=2\)
\(\cdot12^7:6^7=\left(12:6\right)^7=2^7\)
\(\cdot27^5:81^3=\left(3^3\right)^5:\left(3^4\right)^3=3^{15}:3^{12}=3^3\)
\(\cdot10^6:10=10^{6-1}=10^5\)
\(\cdot5^8:25^2=5^8:\left(5^2\right)^2=5^8:5^4=5^4\)
\(\cdot4^9:64^2=4^9:\left(4^3\right)^2=4^9:4^6=4^3\)
\(2^{25}:32^4=2^{25}:\left(2^5\right)^4=2^{25}:2^{20}=2^5\)
\(18^3:9^3=\left(18:9\right)^3=2^3\)
a/ \(\left(-19\right)+5+\left(-8\right)+19+\left(-3\right).\left(-2\right)^3\)
\(\left(-19\right)+5+\left(-8\right)+19+\left(-3\right).\left(-8\right)\)
\(\left(-19\right)+5+\left(-8\right)+19+24\)
\(\left(-14\right)+11+24\)
\(\left(-3\right)+24=21\)
b/ \(\left(-5\right)^3-\left(3^3+4\right).\left(-2\right)+\left(3-27\right):4\)
\(\left(-125\right)-\left(27+4\right).\left(-2\right)+\left(3-27\right):4\)
\(\left(-125\right)-\left(31\right).\left(-2\right)+\left(-24\right):\text{4}\)
\(\left(-125\right)-\left(-62\right)+\left(-6\right)\)
\(\left(-63\right)+\left(-6\right)=-69\)
c/ \(\left[504-\left(5^2.8+70\right):3^2+6\right]:\left(-20\right)\)
\(\left[504-\left(25.8+70\right):9+6\right]:\left(-20\right)\)
\(\left[504-270:9+6\right]:\left(-20\right)\)
\(\left[504-30+6\right]:\left(-20\right)\)
\(480:\left(-20\right)=-24\)
d/ \(\left(-7\right)-\left[\left(-19\right)+21\right].\left(-3\right)-\left[32+\left(-7\right)\right]\)
\(\left(-7\right)-2.\left(-3\right)-25\)
\(\left(-7\right)-\left(-6\right)-25\)
\(\left(-1\right)-25=-26\)
\(\)
a) 57 . 53 : 510 = 510 : 510 = 1
b) 24 : 23 . 27 = 2 . 27 = 28
c) 93 : 33 . 272 = ( 32 ) 3 : 33 . ( 33 ) 2 = 36 : 33 . 36 = 33 . 36 = 39
d) 25 . 13 - 25 . 5 = 25 . ( 13 - 5 ) = 25 . 8 = 25 . 23 = 28
e) \(\frac{4^6.8^3}{4^8}=\frac{\left(2^2\right)^6.\left(2^3\right)^3}{\left(2^2\right)^8}=\frac{2^{12}.2^9}{2^{16}}=\frac{2^{21}}{2^{16}}=2^5\)
d , ( x : 7 + 15 ) . 23 + 391 => Đề thiếu
e , ( 19 . x + 2 . 52 ) : 14 = ( 13 - 8 ) 2 - 42
=> ( 19 . x + 2 . 52 ) : 14 = 52 - 16
=> ( 19 . x + 2 . 52 ) : 14 = 25 - 16 = 9
=> 19 . x + 2 . 52 = 9 x 14 = 126
=> 19 . x + 2 . 25 = 126
=> 19 . x + 50 = 126
=> 19 . x = 126 - 50 = 76
=> x = 76 : 19 = 4
a)9^5:3^7=27
b)4^7:2^7=128
c)2^5:4^7= ko có kết quả
d)5^4:125=5
e)8^5:4^7=2
g)8^3:4^4=2
nhớ **** cho mình nha
Từ sau bn ra ít thôi nha
Câu 1:
a) 52.49+48.38-52.20-48.11
=52.49-52.20+48.38-48.11
=52.(49-20)+28.(38-11)
=52.29+28.27
=2264
b)2.54.12+4.6.68-3.8.22
=24.(54+68-22)
=24.100
=2400
c)24+31.24.64+24.8
=24.(31+64+8)
=24.103
=1648
d)19:3+28:3+13:3
=(19+28+13):3
=60:3
=20
e)32.15-{[(102.15-15.90)-43.2)
=32.15-{[15.(102-90)-43.2)]}
=32.15-{[150-128]}
=32.15-22
=135-22
=113
a)32<2x<128
25<2x<27
Vì 25<26<27
Suy ra:2x=26
Vậy x=6
b)(x+1)2.3245:43-20(ko có nghĩa)
c)92-3(x-3)=157:156
92-3(x-3)=15
3(x-3)=66
x-3=22
x=25
Vậy x=25
d)3x.310=317
3x=317:310
3x=37
Vậy x=7
e)81.3x+1=315
\(3^{x+1}=\frac{35}{9}\)
\(3^{x+1}=3^{1,23621727}\)(cái này ko đổi ra được phân số)
x+1=1,23621727
Rồi tự tính nha
\(4^{19}=2^{2.19}=2^{38}\)
\(8^7=2^{3.7}=2^{21}\)
\(256^4=2^{8.4}=2^{32}\)
\(32^3=2^{5.3}=2^{15}\)
\(\Rightarrow E=\frac{2^{38}+2^{21}}{2^{32}+2^{15}}=\frac{2^{21}.\left(2^{17}+1\right)}{2^{15}.\left(2^{17}+1\right)}=\frac{2^{21}}{2^{15}}=2^6=64\)