Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(\frac{161616}{212121}+\frac{2022}{3033}\right)\times7=\left(\frac{16.10101}{21.10101}+\frac{1011.2}{1011.3}\right)\times7=\left(\frac{16}{21}+\frac{2}{3}\right)\times7\)
\(=\frac{10}{7}\times7=10\)
Bài làm
\(\left(\frac{161616}{212121}+\frac{2022}{3033}\right)x7\)
= \(\left(\frac{16}{21}+\frac{2}{3}\right)x7\)
= \(\left(\frac{16}{21}+\frac{14}{21}\right)x7\)
= \(\frac{30}{21}x7\)
= \(\frac{30}{3}\)
= \(10\)
# Chúc bạn học tốt #
`2022 \times 123 \times 12 - 2022 \times 11`
`= 2022 \times (123 \times 12 - 11)`
`= 2022 \times (1476 - 11)`
`= 2022 \times 1465`
`= 2962230`
\(2022\times2005-2000\times2022+15\times2022-20\times2021\)
\(=2022\times\left(2005-2000+15\right)-20\times2021\)
\(=2022\times20-20\times2021\)
\(=20\times\left(2022-2021\right)\)
\(=20\times1\)
\(=20\)
a, 2022 \(\times\) 2005 - 2000 \(\times\) 2022 + 15 \(\times\) 2022 - 20 \(\times\) 2021
= (2022 \(\times\) 2005 - 2000 \(\times\) 2022 + 15 \(\times\) 2022 )- 20 \(\times\) 2021
= 2022 \(\times\) (2005 - 2000 + 15) - 20 \(\times\) 2021
= 2022 \(\times\) (5 +15) - 20 \(\times\) 2021
= 2022 \(\times\) 20 - 20 \(\times\) 2021
= 20 \(\times\) (2022 - 2021)
= 20 \(\times\) 1
= 20
bài 7:a thực hiện phép tính .81 x 2022 + 25 x 2022 - 6 x 2022 .B Tìm x biết ( x - 1 ) 2/3 - 1/5= 2/5
\(a,81\cdot2022+25\cdot2022-6\cdot2022=2022\cdot\left(81+25-6\right)=2022\cdot100=202200\)
\(b,\left(x-1\right)\cdot\frac{2}{3}-\frac{1}{5}=\frac{2}{5}\)
\(\left(x-1\right)\cdot\frac{2}{3}=\frac{3}{5}\)
\(x-1=\frac{9}{10}\)
\(x=\frac{19}{10}\)
Vậy \(x=\frac{19}{10}\)
( Nếu phần b là hỗn số thì mình làm thế kia , còn nếu là nhân thì bạn tham khảo Câu hỏi của lương bảo ngọc - Toán lớp 5 - Học trực tuyến OLM nhé )
81 x 2022 + 25 x 2022 - 6 x 2022
= ( 81 + 25 - 6 ) x 2022
= 100 x 2022
= 202 200
b) \(\left(\text{x - 1}\right)\frac{\text{2}}{\text{3}}-\frac{\text{1}}{\text{5}}=\frac{\text{2}}{\text{5}}\)
\(\frac{\text{3 x }\text{( x - 1 ) }+\text{2}}{\text{3}}=\frac{\text{1}}{\text{5}}+\frac{\text{2}}{\text{5}}=\frac{\text{3}}{\text{5}}\)
=> \(\text{3 x ( x - 1 ) }+\text{2}=\frac{\text{3}}{\text{5}}\text{ x 3 = }\frac{\text{9}}{\text{5}}\)
=> \(\text{3 x ( x - 1 ) }=\frac{\text{9}}{\text{5}}-\text{2}=\frac{\text{-1}}{\text{5}}\)
=> \(\text{ x-1}=\frac{\text{-1}}{\text{5}}:3=\frac{\text{-1}}{\text{15}}\)
=> \(\text{x}=\frac{\text{-1}}{\text{15}}+\text{1 = }\frac{\text{14}}{\text{15}}\)
A = ( 2022 x 0,75 + 2022 : 4) - ( 2021 : 0,1 : 10)
= (2022 x 0,75 + 2022 x 0,25) - ( 2021 : 1/10 : 10)
= 2022 x(0,75+0,25) - 2021x 10 : 10
= 2022x 1 - 2021
= 2022 - 2021
=1
\(x+x:0,5+x:0,25+x:0,125=2022\)
\(x\text{×}1+x\text{×}2+x\text{×}4+x\text{×8}=2022\)
\(x\text{×}\left(1+2+4+8\right)=2022\)
\(x\text{×}15=2022\)
\(x=2022:15\)
\(x=134,8\)
a. \(\dfrac{2021+2020.2022}{2021.2022-1}\)
\(\dfrac{2021.2022-2022+2021}{2021.2022-1}=\dfrac{2021.2022-1}{2021.2022-1}=1\)
\(b.\dfrac{2022+2021.2023}{2022.2023-1}=\dfrac{2021.2023-2023+2022}{2022.2023-1}\)
\(=\dfrac{2021.2023-1}{2022.2023-1}\)
2022 x 4 + 2022 x 5 + 2022
= 2022 x ( 4 + 5 + 1 )
= 2022 x 10
= 20 220
2022 x 4 + 2022 x 5 + 2022
= 2022 x (4 + 5 + 1)
= 2022 x 10
= 20 220