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49\(\frac{8}{23}\) - (5\(\frac{7}{32}\) + 14\(\frac{8}{23}\) )
= \(\frac{1135}{23}\) - (\(\frac{167}{32}\) +\(\frac{330}{23}\) )
= \(\frac{1135}{23}\) - \(\frac{14401}{736}\)
=\(\frac{953}{32}\)
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(=\frac{1135}{23}\left(\frac{135}{32}+\frac{330}{23}\right)\)
\(=\frac{1135}{23}.\frac{13665}{736}\)
\(=916,2201678\)
\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)
\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)
\(=35\frac{0}{23}-5\frac{7}{32}\)
\(=\frac{805}{23}-\frac{167}{32}\)
\(\frac{25760}{736}-\frac{3841}{736}\)
\(=\frac{21919}{736}=\frac{953}{32}\)
1135/23-167/32+330/23
=(1135/23-330/23)+167/32
=805/23+167/32
=35+167/32
=1120/32+167/32
=1287/32
\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)
\(=49\frac{8}{23}-14\frac{8}{23}-5\frac{7}{12}\)
\(=35-5\frac{7}{32}\)
\(=35-\frac{167}{32}\)
\(=\frac{1120}{32}-\frac{167}{32}\)
\(=\frac{935}{32}\)
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)
\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)
\(=35-5\frac{7}{32}\)
\(=35-\frac{167}{32}\)
\(=\frac{953}{32}\)
Bài 1:
5/16:0,125-(2 1/4-0,6).10/11
=5/16:5/4-(9/4-3/5).10/11
=1/4-33/20.10/11
=1/4-3/2
=-5/4
\(\frac{5}{16}:0,125-\left(2\frac{1}{4}-0,6\right).\frac{10}{11}\)
\(=\frac{5}{16}.8-\frac{33}{20}.\frac{10}{11}\)
\(=\frac{5}{2}-\frac{3}{2}=\frac{2}{2}=1\)
<br class="Apple-interchange-newline"><div></div>49823 −(5732 +14823 )
\(49\frac{8}{23}-19\frac{417}{736}\)
\(=\frac{953}{12}\)
Study well
a) \(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{23}\right)=\frac{31}{23}-\frac{7}{32}-\frac{8}{23}=1-\frac{7}{32}=\frac{25}{32}\)
b) \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)
\(=\frac{1}{3}-\left(\frac{79}{67}-\frac{12}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)
\(=\frac{1}{3}-1+1=\frac{1}{3}\)
d) \(\frac{1}{7}.\frac{1}{3}+\frac{1}{7}.\frac{-1}{3}+\frac{17}{19}=\frac{1}{7}.\left(\frac{1}{3}-\frac{1}{3}\right)+\frac{17}{19}=\frac{17}{19}\)
e) \(\frac{3}{5}.\frac{7}{9}+\frac{7}{5}.\frac{2}{9}=\frac{7}{5}.\left(\frac{3}{9}+\frac{2}{9}\right)=\frac{7}{5}.\frac{5}{9}=\frac{7}{9}\)
\(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(A=49\frac{8}{23}-5\frac{7}{32}+14\frac{8}{23}\)
\(A= \left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)
\(A=\left[\left(49-14\right)-\left(\frac{8}{23}-\frac{8}{23}\right)\right]-5\frac{7}{32}\)
\(A=\left[35-0\right]-5\frac{7}{32}\)
\(A=35-5\frac{7}{32}\)
\(A=\frac{953}{32}\)
\(B=71\frac{38}{45}-\left(43\frac{38}{45}-1\frac{17}{57}\right)\)
\(B=71\frac{38}{45}-\frac{36377}{855}\)
\(B=\frac{1670}{57}\)
\(C=\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right):\frac{4}{5}\)
\(C=\left[\left(19\frac{5}{8}-13\frac{1}{4}\right):\frac{7}{12}\right]:\frac{4}{5}\)
\(C=\left[\frac{51}{8}:\frac{7}{12}\right]:\frac{4}{5}\)
\(C=\frac{153}{14}:\frac{4}{5}\)
\(C=\frac{765}{56}\)
\(D=\left[\left(\frac{10}{15}-\frac{2}{3}\right):\frac{1}{7}\right]\cdot0,15-\frac{1}{4}\)
\(D=\left[0:\frac{1}{7}\right]\cdot\frac{3}{20}-\frac{1}{4}\)
\(D=0\cdot\frac{3}{20}-\frac{1}{4}\)
\(D=0-\frac{1}{4}\)
\(D=-\frac{1}{4}\)
\(E=\frac{13}{30}+\frac{28}{45}\cdot2\frac{1}{2}-\left[\left(\frac{1}{2}+\frac{1}{3}\right):\frac{53}{90}\right]:\frac{50}{53}\)
\(E=\frac{13}{30}+\frac{28}{45}\cdot\frac{5}{2}-\left[\frac{5}{6}:\frac{53}{90}\right]:\frac{50}{53}\)
\(E=\frac{13}{30}+\frac{28}{45}\cdot\frac{5}{2}-\frac{75}{53}:\frac{50}{53}\)
\(E=\frac{13}{30}+\frac{14}{9}-\frac{3}{2}\)
\(\)\(E=\frac{22}{45}\)
CHUC BAN HOC TOT >.<
A= \(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
=\(\frac{1135}{32}-\left(\frac{167}{32}+\frac{330}{23}\right)\)
=\(\frac{1135}{23}-\frac{167}{32}-\frac{330}{23}\)
=\(\left(\frac{1135}{23}-\frac{330}{23}\right)-\frac{167}{32}\)
=\(\frac{805}{23}-\frac{167}{32}\)
=\(\frac{953}{32}\)
\(A=35-\frac{167}{32}\)
\(A=\frac{953}{32}\)