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\(77^2+23+77.46\)
\(=77.77+23+77.46\)
\(=77.\left(77+46\right)+23\)
\(=77.123+23\)
\(=9471+23=9494\)
\(77^2+23+77.46\)
\(=77.77+23+77.46\)
\(=77.\left(77+46\right)+23\)
\(=77.123+23\)
\(=9471+23\)
\(=9494\)
B=\(3^{24}-\left(27^4+1\right)\left(9^6+1\right)=-1062883\)A=123(123+154)+772=123.277+772=34843
C=\(85^2+75^2+65^2+55^2-45^2-35^2-25^2-15^2=16000\)
a) \(A=123\left(123+154\right)+77^2\)
\(A=123^2+\left(123.154\right)+77^2=\left(123+77\right)^2=200^2=400\)
b) \(B=3^{24}-\left(2^{47}+1\right)\left(9^6-1\right)\)
\(B=3^{24}-\left(3^{12}-1\right)\left(3^{12}+1\right)\)
\(B=3^{24}-3^{24}+1=1\)
c) \(C=85^2+75^2+65^2+55^2-45^2-35^2-25^2-15^2\)
\(C=\left(85^2-15^2\right)+\left(75^2-25^2\right)+\left(65^2-35^2\right)+\left(55^2-45^2\right)\)
\(C=\left(85+15\right)\left(85-15\right)+\left(75+25\right)\left(75-25\right)+\left(65+35\right)\left(65-35\right)\left(55+45\right)\left(55-45\right)\)
\(C=100\left(60+50+40+30+20+10\right)\)
\(C=100.210=21000\)
a)
\(A=177^2+23^2+177.46\)
\(A=177^2+177.46+23^2\)
\(A=177^2+2.177.23+23^2\)
\(A=\left(177+23\right)^2\)
\(A=200^2\)
\(A=40000.\)
Vậy \(A=40000.\)
b)
\(B=x^3+9x^2+27x+27\)
\(B=x^3+3.x^2.3+3.x.3^2+3^3\)
\(B=\left(x+3\right)^3.\)
+ Thay \(x=-23\) vào B ta được:
\(B=\left[\left(-23\right)+3\right]^3\)
\(B=\left(-20\right)^3\)
\(B=-8000.\)
Vậy giá trị của B tại \(x=-23\) là: \(-8000.\)
Chúc bạn học tốt!
a) \(A=177^2+23^2+2.177.23=\left(177+23\right)^2=200^2=40000\)
b) \(B=x^3+9x^2+27x+27=\left(x+3\right)^3\)
Với \(x=-23\Rightarrow B=\left(-23+3\right)^3=\left(-20\right)^3=-8000\)
(1/2+2/5+7/3+5/9+123/159).((252-2.25.15+152)-100)
=(1/2+2/5+7/3+5/9+123/159).((25-15)2-100)
=(1/2+2/5+7/3+5/9+123/159).(102-100)
=(1/2+2/5+7/3+5/9+123/159).(100-100)
=(1/2+2/5+7/3+5/9+123/159).0=0
772 + 232 + 77.46 = 772 + 232 + 2.77.23
= (77 + 23)2 = 1002 = 10000
Ta có: 1232-246.23+232 = 1232-2.123.23+232
= (123-23)2 = 1002
= 10000