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A.\(=\frac{17}{25}\times\left(\frac{13}{19}+\frac{6}{19}\right)\)
\(=\frac{17}{25}\times1\)
\(=\frac{17}{25}\)
B\(=\frac{47}{19}:\left(\frac{15}{32}-\frac{15}{17}\right)\)
\(=\frac{47}{19}:1\)
\(=\frac{47}{19}\)
a: =17/25(13/19+6/19)=17/25
b: \(=\dfrac{47}{19}\cdot\dfrac{32}{15}-\dfrac{47}{19}\cdot\dfrac{17}{15}=\dfrac{47}{19}\)
a, \(\frac{2}{5}\)x ( \(\frac{3}{7}\)+\(\frac{4}{7}\))
= \(\frac{2}{5}\)x \(\frac{7}{7}\)
= \(\frac{2}{5}\)x 1
= \(\frac{2}{5}\)
b, \(\frac{47}{19}\) :\(\frac{15}{32}\) - \(\frac{47}{19}\) :\(\frac{15}{17}\)
= \(\frac{47}{19}\) × \(\frac{32}{15}\) - \(\frac{47}{19}\) × \(\frac{17}{15}\)
= \(\frac{47}{19}\) × (\(\frac{32}{15}\)-\(\frac{17}{15}\))
= \(\frac{47}{19}\) × 1
= \(\frac{47}{19}\)
a) \(\dfrac{3}{5}\times\dfrac{17}{21}+\dfrac{2}{5}\times\dfrac{17}{21}\)
\(=\dfrac{17}{21}\times\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\)
\(=\dfrac{17}{21}\times1\)
\(=\dfrac{17}{21}\)
b) \(\dfrac{11}{19}\times\dfrac{2}{7}+\dfrac{5}{7}\times\dfrac{11}{19}\)
\(=\dfrac{11}{19}\times\left(\dfrac{2}{7}+\dfrac{5}{7}\right)\)
\(=\dfrac{11}{19}\times1\)
\(=\dfrac{11}{19}\)
a: =17/21(3/5+2/5)
=17/21*5/5
=17/21
b: =11/19(2/7+5/7)
=11/19*1
=11/19
a) \(\dfrac{16}{15}+\dfrac{7}{15}+\dfrac{4}{15}=\left(\dfrac{16}{15}+\dfrac{4}{15}\right)+\dfrac{7}{15}=\dfrac{20}{15}+\dfrac{7}{15}=\dfrac{27}{15}\)
b) \(\dfrac{5}{17}+\dfrac{7}{17}+\dfrac{13}{17}=\dfrac{5}{17}+\left(\dfrac{7}{17}+\dfrac{13}{17}\right)=\dfrac{5}{17}+\dfrac{20}{17}=\dfrac{25}{17}\)
1) Chiều cao hình bình hành là:65*3/5=39 (cm)
S của hình bình hành là: 65*39=2535(cm2)
2)a)3/4*3/2+3/4*1/2
=(3/2+1/2)*3/4
=2*3/4
=3/2
Câu 1: Chiều cao là:
65*3/5=39[cm]
S là:
65*39=2535[cm]
Câu 2: a,3/4*[3/2+1/2]=3/2 b,47/19:[15/32-15/32]=0
\(\dfrac{47}{19}:\dfrac{15}{32}-\dfrac{47}{19}:\dfrac{15}{17}\\ =\dfrac{47}{19}\times\dfrac{32}{15}-\dfrac{47}{19}\times\dfrac{17}{15}\\ =\dfrac{47}{19}\times\left(\dfrac{32}{15}-\dfrac{17}{35}\right)\\ =\dfrac{47}{19}\times1\\ =\dfrac{47}{19}\)
`@An`