Question

[Đào Đức Mạnh]

Tính:   4^2,5, 3^3,5, 5^2,1 (Cách làm cụ thể?)

Answer 1

[Mr Lazy]

\(4^{2,5}=\left(2^2\right)^{2,5}=2^{2.2,5}=2^5=32\)

\(3^{3,5}=\sqrt{\left(3^{3,5}\right)^2}=\sqrt{3^{3,5.2}}=\sqrt{3^7}=27\sqrt{3}\)

\(5^{2,1}=\sqrt[10]{\left(5^{2,1}\right)^{10}}=\sqrt[10]{5^{21}}=\sqrt[10]{5^{20}}.\sqrt[10]{5}=5^2\sqrt[10]{5}=25\sqrt[10]{5}\)

Answer 2

[Mr Lazy]

\(\left(4^{2,5}\right)^2=4^{2,5.2}=4^5=1024\Rightarrow4^{2,5}=\sqrt{1024}=32\)