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Ta có (7+x)/12=2/3
suy ra 3(7+x)=24
suy ra 7+x=8
x=1
Ta có (25-x)/18=1/2
suy ra 2(25-x)=18
suy ra 25-x=9
x=16
1.\(7+\frac{x}{12}=\frac{2}{3}\)
\(\frac{x}{12}=\frac{2}{3}-7=-\frac{19}{3}\)
\(x=-\frac{19}{3}.12=-76\)
Vậy x=-76
2.\(25-\frac{x}{18}=\frac{1}{2}\)
\(\frac{x}{18}=25-\frac{1}{2}=\frac{49}{2}\)
\(x=\frac{49}{2}.18=441\)
Vậy x=441
a) \(7+\frac{x}{12}=\frac{2}{3}\)
\(\frac{x}{12}=\frac{2}{3}-7\)
\(\frac{x}{12}=\frac{2}{3}-\frac{21}{3}\)
\(\frac{x}{12}=\frac{-19}{3}=\frac{-76}{12}\)
\(\Rightarrow x=-76\)
b) \(25-\frac{x}{18}=\frac{1}{2}\)
\(\frac{x}{18}=25-\frac{1}{2}\)
\(\frac{x}{18}=\frac{50}{2}-\frac{1}{2}\)
\(\frac{x}{18}=\frac{49}{2}=\frac{441}{18}\)
\(\Rightarrow x=441\)
mk ko biết đúng hay ko nha
a) \(\frac{7+x}{12}=\frac{2}{3}\)
\(\frac{7+x}{12}=\frac{8}{12}\)
\(\Rightarrow7+x=8\)
\(\Rightarrow x=8-7\)
\(\Rightarrow x=1\)
b) \(\frac{25-x}{18}=\frac{1}{2}\)
\(\frac{25-x}{18}=\frac{9}{18}\)
\(\Rightarrow25-x=9\)
\(\Rightarrow x=25-9\)
\(\Rightarrow x=16\)
\(\frac{7+x}{12}=\frac{2}{3}\)
\(=>\left(7+x\right).3=2.12\)
\(=>21+3x=24\)
\(=>3x=3\)
\(=>x=1\)
vay \(x=1\)
\(\frac{25-x}{18}=\frac{1}{2}\)
\(=>\left(25-x\right).2=18\)
\(=>50-2x=18\)
\(=>-2x=32\)
\(=>x=-16\)
vay \(x=-16\)
a, \(\frac{7+x}{12}=\frac{2}{3}\)
\(\frac{7+x}{12}=\frac{8}{12}\)
\(x=8-7\)
\(x=1\)
a) 7- x/12=1/2
x/12=7-1/2
x/12 =14/2-1/2
x/12=13/2
x/12=78/12
x=78
vậy x=78
mình nhân cả tử và mẫu với 13/2 nên mới ra 78/12
câu 1 = 0
câu 2 : X=\(\frac{16}{105}\)
X =\(\frac{180}{77}\)
X = 63
(18\(\dfrac{1}{2}+5\dfrac{3}{8}-7\dfrac{5}{24}\)) - 16\(\dfrac{2}{3}\)
=( \(\dfrac{37}{2}\) + \(\dfrac{43}{8}\) - \(\dfrac{171}{24}\) ) - \(\dfrac{50}{3}\)
= \(\dfrac{50}{3}\) - \(\dfrac{50}{3}\)
=0
7+x/12=2/3
x/12=7-2/3
x/12=19/3
19/3=76/12
=>x=76
25-x/18=1/2
x/18=25-1/2
x/18=49/2
49/2=441/18
=>x=441
7+x/12=2/3
x/12=7-2/3
x/12=19/3
19/3=76/12
=>x=76
25-x/18=1/2
x/18=25-1/2
x/18=49/2
49/2=441/18
=>x=441