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30 + x = 40 + 60
30 + x = 100
x = 100 - 30
x = 70
10 + 90 = 40 + x
100 = 40 + x
x = 100 - 40
x = 60
30+x=40+60
30+x=100
x=100-30
x=70
10+90=40+x
100 =40+x
100-40=x
60 =x
\(\frac{x+10}{90}+\frac{x+20}{80}+\frac{x+30}{70}+\frac{x+40}{60}+\frac{x+50}{50}=-5\)
<=> \(\frac{x+10}{90}+1+\frac{x+20}{80}+1+\frac{x+30}{70}+1+\frac{x+40}{60}+1+\frac{x+50}{50}+1=0\)
<=> \(\frac{x+100}{90}+\frac{x+100}{80}+\frac{x+100}{70}+\frac{x+100}{60}+\frac{x+100}{50}=0\)
<=> \(\left(x+100\right)\left(\frac{1}{90}+\frac{1}{80}+\frac{1}{70}+\frac{1}{60}+\frac{1}{50}\right)=0\)
<=> x + 100 = 0
<=> x = -100
Vậy x = -100
a)5+10=30-x
=>15=30-x
=>x=30-15
=>x=15
b)10+40=90-x
=>50=90-x
=>x=90-50
=>x=40
\(5+10=30-x\)
\(15=30-x\)
\(x=15\)
\(10+40=90-x\)
\(50=90-x\)
\(x=40\)
10 - x = -90
x = 10 - (-90)
x = 100
x + 60 = 20
x = 20 - 60
x = -40
x=5
x=0 nha bn
chuẩn ko cần chỉnh nếu các bạn nghĩ giống mik thì ủng hộ mik nha
a) 40 - x = 25
x = 40 - 25
x = 15
b) x - 1 = 10 + [ 90 - ( 17 - 8 ) 2 ]
x - 1 = 10 + [ 90 - 92 ]
x - 1 = 10 + [ 90 - 81 ]
x - 1 = 10 + 9
x - 1 = 19
x = 19 + 1
x = 20
a; \(x\) ⋮ 5; \(x\) ⋮ 6; \(x\) ⋮ 10;
\(x\) \(\in\) BC(5; 6; 10)
5 = 5; 6 = 2.3; 10 = 2.5
BCNN(5;6;10) = 2.3.5 = 30
\(x\in\) B(30) = {0; 30; 60; 90; 120; 150; 180;..}
Vì 0 < \(x\) < 140 nên \(x\) \(\in\) {0; 30; 60; 120}
Vậy \(x\) \(\in\) {0; 30; 60; 120}
b; \(x\) \(⋮\) 30; \(x\) ⋮ 45; \(x\) < 500
\(x\) \(⋮\) 30; \(x\) ⋮ 45 ⇒ \(x\) \(\in\) BC (30; 45)
30 = 2.3.5; 45 = 32.5; BCNN(30 ; 45) = 2.32.5 = 90
\(x\) \(\in\) B(90) = {0; 90; 180; 270; 360; 450; 540;...}
Vì 45 < \(x\) < 500 nên \(x\) \(\in\) {90; 180; 270; 360; 450}
Vậy \(x\) \(\in\) {90; 180; 270; 360; 450;...}
a) => x\(\in\)BC(5,6,10)
Ta có: 5=5
6=2.3
10=2.5
BCNN(5,6,10)=2.3.5=30
=> BC(5,6,10)={0,30,60,90,120,150,180,...}
Vì 0<x<140
Nên:x\(\in\){30,60,90,120}
b)=> x\(\in\)BC(30,45)
30=2.3.5
45=32.5
BCNN(30,45)=2.32.5=90
=> BC(30,45)={0,90,180,270,360,450,540,...}
Vì x<500 nên x\(\in\){0,90,270,360,450}
c) => x\(\in\)ƯC(40,60)
40=23.5
60=22.3.5
ƯCLN(40,60)=22.5=20
=>ƯC(40,60)={1,2,4,5,10,20}
Vì x>20 nên x\(\in\)\(\varnothing\)
20+x=40+60
\(\Rightarrow\)20+x=100
\(\Rightarrow\)x=100-20
\(\Rightarrow\)x=80
10+90=40+x
\(\Rightarrow\)100=x+40
\(\Rightarrow\)x=100-40
\(\Rightarrow\)x=60
20 + x = 40 + 60
=> 20 + x = 100
=> x = 100 - 20
=> x = 80
10 + 90 = 40 + x
=> 100 = 40 + x
=> x = 100 - 40
=> x = 60