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1) \(2x^4+5x^2+2=0\)
\(\Leftrightarrow\left(2x^2+1\right)\left(x^2+2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x^2+1=0\\x^2+2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x^2=-\frac{1}{2}\\x^2=-2\end{cases}}\) (vô lý)
=> pt vô nghiệm
2) \(2x^4-7x^2-4=0\)
\(\Leftrightarrow\left(x^2-4\right)\left(2x^2+1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^2-4=0\\2x^2+1=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x^2=4\\x^2=-\frac{1}{2}\left(vl\right)\end{cases}\Rightarrow}\orbr{\begin{cases}x=2\\x=-2\end{cases}}\)
3) \(x^4-5x^2+4=0\)
\(\Leftrightarrow\left(x^2-1\right)\left(x^2-4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^2-1=0\\x^2-4=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x^2=1\\x^2=4\end{cases}\Rightarrow}\orbr{\begin{cases}x=\pm1\\x=\pm2\end{cases}}\)
4) \(2x^4-20x^2+18=0\)
\(\Leftrightarrow x^4-10x^2+9=0\)
\(\Leftrightarrow\left(x^2-1\right)\left(x^2-9\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^2-1=0\\x^2-9=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x^2=1\\x^2=9\end{cases}\Rightarrow}\orbr{\begin{cases}x=\pm1\\x=\pm3\end{cases}}\)
1. \(2x^4+5x^2+2=0\)
Vì \(2x^4+5x^2+2\ge2\)
=> Pt trên vô nghiệm
2. \(2x^4-7x^2-4=0\)
\(\Leftrightarrow2x^4+x^2-8x^2-4=0\)
\(\Leftrightarrow x^2\left(2x^2+1\right)-4\left(2x^2+1\right)=0\)
\(\Leftrightarrow\left(x^2-4\right)\left(2x^2+1\right)=0\)
\(\Leftrightarrow\left(2x^2+1\right)\left(x+2\right)\left(x-2\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}2x^2+1=0\left(vo-ly\right)\\x+2=0\\x-2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-2\\x=2\end{cases}}\)
a) \(\left(x-2\right)^2-\left(x+3\right)^2-4\left(x+1\right)=5\)
\(\Leftrightarrow x^2-4x+4-\left(x^2+6x+9\right)-4x-4=5\)
\(\Leftrightarrow x^2-4x+4-x^2-6x-9-4x-4=5\)
\(\Leftrightarrow-14x=14\)
\(\Leftrightarrow x=-1\)
b) \(\left(2x-3\right)\left(2x+3\right)-\left(x-1\right)^2-3x\left(x-5\right)=-44\)
\(\Leftrightarrow4x^2-9-x^2+2x-1-3x^2+15x=-44\)
\(\Leftrightarrow17x=-34\Rightarrow x=-2\)