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\(\left|x+2\right|=0\)
\(\Rightarrow x+2=0\)
\(\Rightarrow x=0-2\)
\(\Rightarrow x=-2\)
\(\left|x-5\right|=\left|-7\right|\)
\(\Rightarrow\left|x-5\right|=7\)
\(\Rightarrow\hept{\begin{cases}x-5=-7\\x-5=7\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-7+5\\x=7+5\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-2\\x=12\end{cases}}\)
\(\Rightarrow x\in\left\{-2;12\right\}\)
1/ 3(x - 2) = 9 => x - 2 = 3 => x = 5
2/ 3(x - 36) = 216 => x - 36 = 72 => x = 108
3/ (x - 3)3 = 33 => x - 3 = 3 => x = 6
4/ 2x = 32 => 2x = 25 => x = 5
5/ 3x - 16 = 2.74 : 73 = 14 => 3x = 30 => x = 10
6/ (6x - 39) : 3 = 201 => 6x - 39 = 603 => 6x = 642 => x = 107
7/ (3x - 15)2 = 81 => (3x - 15)2 = 92 => 3x - 15 = 9 => 3x = 24 => x = 8
8/ 3(x + 4) = 105 => x + 4 = 35 => x = 31
9/ 12x - 43 = 4.84 : 83 = 32 => 12x = 32 : 64 => 12x = 1/2 => x = 1/24
10/ 41 - (2x - 5) = 680 => 2x - 5 = -639 => 2x = -634 => x = - 317
a) 123 - 5 (x + 4) = 38
5 (x + 4) = 123 - 38
5 (x + 4) = 85
x + 4 = 85 : 5
x + 4 = 17
x = 17 - 4
x = 13
b) (3x - 24) . 73 = 2 . 74
3x - 24 = 2 . 74 : 73
3x - 24 = 2 . 7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
c) (x : 3 - 4) . 5 = 15
x : 3 - 4 = 15 : 5
x : 3 - 4 = 3
x : 3 = 3 + 4
x : 3 = 7
x = 7 . 3
x = 21
a; -2\(x\) - 3.(\(x-17\)) = 34 - 2.( - \(x\) + 25)
- 2\(x\) - 3\(x\) + 51 = 34 + 2\(x\) - 50
2\(x\) + 2\(x\) + 3\(x\) = - 34 + 50 + 51
7\(x\) = 67
\(x\) = 67 : 7
\(x\) = \(\dfrac{67}{7}\)
Vậy \(x\) = \(\dfrac{67}{7}\)
b; 17\(x\) + 3.(- 16\(x\) - 37) = 2\(x\) + 43 - 4\(x\)
17\(x\) - 48\(x\) - 111 = 2\(x\) - 4\(x\) + 43
- 31\(x\) - 2\(x\) + 4\(x\) = 111 + 43
- \(x\) x (31 + 2 - 4) = 154
- \(x\) x (33 - 4) = 154
- \(x\) x 29 = 154
- \(x\) = 154 : (-29)
\(x\) = - \(\dfrac{154}{29}\)
Vậy \(x=-\dfrac{154}{29}\)
Bài 2:a)<=>5(x+4) =125-38
<=>5(x+4)=87
<=>x+4=17,4
<=>x=17,4-4=13.4
b)<=> ( 3x – 24) . 73 = 2.74
<=> (3x – 16) = 2.74 : 73
<=> (3x – 16) =2.7
<=>3x – 16 = 14
<=> 3x = 30
<=> x = 10
c)=> xϵ ƯC (70, 84) và x > 8
Ta có: 70 = 2. 5. 7 => ƯCLN( 70,84) = 2. 7 = 14
84 = 22. 3. 7
=> ƯC (70, 84) = Ư(14) = { 1 ;2; 7; 14 }
Vì x > 8 => x = 14
d)=>xϵ BCNN (12, 25, 30) và 0 < x < 500
=>BC(12,25,30)=B(300) = { 0; 300; 600; …}
Vì 0 < x < 500
=> x = 300
giup minh nha cac ban . lam duoc minh se tick cho va ket ban . cam on cac ban
a) x - 7 = - 5
x = - 5 + 7
x = 2
b) 128 - 3 . ( x + 4 ) = 23
3 . ( x + 4 ) = 128 - 23
3 . ( x + 4 ) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
c) [ ( 6x - 39 ) : 7 ] . 4 = 12
( 6x - 39 ) : 7 = 12 : 4
( 6x - 39 ) : 7 = 3
6x - 39 = 3 . 7
6x - 39 = 21
6x = 60
x = 10
d) ( x : 3 - 4 ) . 5 = 15
x : 3 - 4 = 3
x : 3 = 7
x = 21
a) x - 7= -5
x= -5 +7
x= 2
b) 128 -3 .(x+4)=23
3.(x+4)=128-23
3.(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
c)[(6x-39):7].4=12
[(6x-39):7]=12:4
(6x-39):7=3
6x-39=7.3
6x-39=21
6x=21+39
6x=60
x=60:6
x=10
d) ( x :3 -4).5=15
x:3-4=15:5
x:3-4=3
x:3=4+3
x:3=7
x=7.3
x=21
e)(3x -2^4 ).7^3=2. 7^4
(3x-16).343=2.2401
(3x-16).343=4802
3x-16=4802:343
3x-16=14
3x=14+16
3x=30
x=30:3
x=10
g)x-[ 42+(-28)]=-8
x-14=-8
x=-8+14
x=6
i) 4-(7-x)=x -(13-4)
4-7+x=x-13+4
-3 + x= x-9
-3+x=-9+x
=> K có giá trị nào thỏa mãn -3+x=-9+x
=>x thuộc rỗng
\(1,2x+3x-4x=\left(-2\right)^3\)
<=>\(x=-8\)
\(2,x-2x=4^2+4^0\)
<=>\(-x=16+1\)
<=>\(-x=17\)
<=>\(x=-17\)
\(3,2^3x-3^2x=|12-21|\)
<=>\(-x=9\)
<=>\(x=-9\)
\(4,x-45=2x+54\)
<=>\(x-2x=54+45\)
<=>\(-x=99\)
<=>\(x=-99\)
\(5,5x-12+23=6^7:6^5\)
<=>\(5x+11=6^2\)
<=>\(5x+11=36\)
<=>\(5x=25\)
<=>\(x=5\)
a,71.2-6.(2x+5)=10^5:10^3
142-6.(2x+5)=10^2
142-6.(2x+5)=100
6.(2x+5)=142-100
6.(2x+5)=42
2x+5=42:6
2x+5=7
2x=7-5
2x=2
x=1
Vậy x=1