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a. 1440 : [ 120 - (3x + 9 ) ] = 120
120 - (3x + 9) = 1440 : 120 = 12
3x + 9 = 120 - 12 = 108
3x = 108 - 9 = 99
x = 99 : 3 = 33
b. 120 + [ ( 999 - 9x ) : 60 ] . 24 = 480
[ ( 999 - 9x ) : 60 ] . 24 = 480 - 120 = 360
( 999 - 9x ) : 60 = 360 : 24 = 15
( 999 - 9x ) = 15 . 60 = 900
9x = 999 - 900 = 99
x = 99 : 9 = 11
a,3x+1 +3x+3x-1=30.(34)3
3x+1+3x+3x-1=20726199
3x.3+3x.1+3x:3=20726199
3x.3+3x.1+3x.\(\frac{1}{3}\)=20726199
3x(3+1+\(\frac{1}{3}\))=20726199
3x.\(\frac{13}{3}\)=20726199
3x=20726199:\(\frac{13}{3}\)
3x=4782969
3x=314
Vậy x:=14
1
3\(^5\).5\(^3\)-20.{300-[546-2\(^3\).(7\(^8\):7\(^6\)+7\(^0\))]}
= 243.125-20.{300-[546-8.(49+1)
= 243.125-20.[300-(546-8.50)
= 243.125-20.[300-(546-400)
= 243.125-20.(300-146)
= 243.125-20.154
= 30375-3080
= 27295
a) 2x - 2x + 3 = -56
<=> 2x(1 - 23) = -56
<=> 2x.(- 7) = -56
<=> 2x = 8
<=> 2x = 23
<=> x =3
Vậy x = 3
b) 3x + 1 + 3x = 108
<=> 3x(3 + 1) = 108
<=> 3x = 27
<=> 3x = 33
<=> x = 3
Vậy x = 3
c) 27.3x + 1 = 33x
<=> 33.3x + 1 = 33x
<=> 3x + 4 = 33x
<=> x + 4 = 3x
<=> 2x = 4
<=> x =2
Vậy x = 2
d) 3x + 2 - 3x = 72
<=> 3x(32 - 1) = 72
<=> 3x = 9
<=> 3x = 32
<=> x = 2
e) (x - 5)12 - (x - 5)10 = 0
<=> (x - 5)10[(x - 5)2 - 1] = 0
<=> \(\orbr{\begin{cases}\left(x-5\right)^{10}=0\\\left(x-5\right)^2-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}\left(x-5\right)^{10}=0\\\left(x-5\right)^2=1\end{cases}}\)
Khi (x - 5)10 = 0
<=> x - 5 = 0
<=> x = 5
Khi (x - 5)2 = 1
<=> \(\orbr{\begin{cases}x-5=1\\x-5=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=6\\x=4\end{cases}}\)
Vậy x \(\in\left\{4;5;6\right\}\)
Trả lời:
a. 2x - 2x+3 = - 56
<=> 2x - 2x . 23 = - 56
<=> 2x ( 1 - 23 ) = - 56
<=> 2x . ( - 7 ) = - 56
<=> 2x = 8
<=> 2x = 23
<=> x = 3
Vậy x = 3
b. 3x+1 + 3x = 108
<=> 3x . 3 + 3x = 108
<=> 3x ( 3 + 1 ) = 108
<=> 3x . 4 = 108
<=> 3x = 27
<=> 3x = 33
<=> x = 3
Vậy x = 3
c. 27 . 3x+1 = 33x
<=> 33 . 3x+1 = 33x
<=> 33+x+1 = 33x
<=> 3 + x + 1 = 3x
<=> 4 + x = 3x
<=> x - 3x = - 4
<=> - 2x = - 4
<=> x = 2
Vậy x = 2
d. 3x+2 - 3x = 72
<=> 3x . 32 - 3x = 72
<=> 3x ( 32 - 1 ) = 72
<=> 3x . 8 = 72
<=> 3x = 9
<=> 3x = 32
<=> x = 2
Vậy x = 2
e. (x - 5)12 - (x - 5)10 = 0
<=> ( x - 5 )10 [ ( x - 5 )2 - 1 ] = 0
<=> ( x - 5 )10 = 0 hoặc ( x - 5 )2 - 1 = 0
<=> x - 5 = 0 hoặc ( x - 5 )2 = 1
<=> x = 5 hoặc x - 5 = 1 hoặc x - 5 = - 1
<=> x = 5 hoặc x = 6 hoặc x = 4
Vậy x = 4; x = 5; x = 6
\(3^x+3^{x+2}+3^{x+3}=999\)
\(\Rightarrow3^x+3^x.3^2+3^x.3^3=999\)
\(\Rightarrow3^x.\left(1+3^2+3^3\right)=999\)
\(\Rightarrow3^x.37=999\)
\(\Rightarrow3^x=999:37\)
\(\Rightarrow3^x=27\)
\(\Rightarrow3^x=3^3\)
\(\Rightarrow x=3\)
\(3^x+3^{x+2}+3^{x+3}=999.\)
\(\Rightarrow3^x.\left(1+3^2+3^3\right)=999\)
\(\Rightarrow3^x.37=999\)
\(\Rightarrow3^x=999:37\)
\(\Rightarrow3^x=27\)
\(\Rightarrow3^x=3^3\)
\(\Rightarrow x=3\)