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\(G=\frac{18.123+9.4567.2+3.5310.6}{1+4+7+...+55+58-410}\)
\(\rightarrow G=\frac{18.123+18.4567+18.5310}{\left(58+1\right).20\div2-410}\)
\(\rightarrow G=\frac{18.\left(123+4567+5310\right)}{590-410}\)
\(\rightarrow G=\frac{18.10000}{180}\)
\(\rightarrow G=\frac{180000}{180}\)
\(\rightarrow G=\frac{180.1000}{180}\)
\(\rightarrow G=1000\)
\(G=\left(18\cdot123+9\cdot4567\cdot2+3\cdot5310\cdot6\right)\div\left(1+4+7+10+55+58-410\right)\)
\(\left(58-1\right)\div3+1=20\)
\(G=\left(18\cdot123+9\cdot4567\cdot2+3\cdot5310\cdot6\right)\div\left[\left(58+1\right)\times20\div2-410\right]\)
\(G=180000\div180\)
\(G=1000\)
tử số =18.123+9.4567.2+3.5310.6=18.123+18.4567+18.5310
=18(123+4567+5310)
=18.10000=180000
mẫu số = 1+4+7+....+49+52+55+58-490
=(1+58)+(4+55)+.....(28+31)-490
=59+59+59+...+59-490(10 so 59)
=100
suy ra A=180000:100=1800
a,D=1+2+4+8+16+32+64+128+256+512+1024
D=(1+2)+4+8+16+32+64+128+256+512+1024
D=(4+4)+8+16+32+64+128+256+512+1024
D=(8+8)+16+32+64+128+256+512+1024
D=(16+16)+32+64+128+256+512+1024
D=(32+32)+64+128+256+512+1024
D=(64+64)+128+256+512+1024
D=(128+128)+256+512+1024
D=(256+256)+512+1024
D=(512+512)+1024
D=1024+1024
D=2048
Dat tu la A, mau la B ta co
A=18*(123+4567+5310)
=18*10000=180000
B=(48+2)*24:2=600
=> A/b=180000/600=300
kl:
a,\(25-\left(-75\right)+32-\left(32+75\right)\))
=\(25+75+32-32-75\)
=\(\left(75-75\right)+\left(32-32\right)+25\)
=\(0+0+25=25\)
\(b,\left|-127\right|-18.\left(5-6\right)\)
\(=127-18.\left(-1\right)\)
\(=127-\left(-18\right)\)
\(=145\)
\(c,17-25+55-17\)
\(=\left(17-17\right)+\left(55-25\right)\)
\(=0+30\)
\(=30\)
a)
25 - (-75) + 32 - ( 32 + 75 )
= 25 + 75 + 32 - 107
=100+32 - 107
=132 - 107
=25