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a, \(3^4\div3^2-\left[120-\left(2^6.2+5^2.2\right)\right]\)
\(=3^2-\left\{120-\text{[}2.\left(2^6+5^2\right)\text{]}\right\}\)
\(=3^2-\left(120-2\cdot89\right)\)
\(=9--58=9+58=67\)
1. \(a,3^4:3^2-\left[120-(2^6\cdot2+5^2\cdot2)\right]\)
\(=3^2-\left[120-\left\{(2^6+5^2)\cdot2\right\}\right]\)
\(=3^2-\left[120-\left\{(64+25)\cdot2\right\}\right]\)
\(=9-\left[120-89\cdot2\right]\)
\(=9-\left[120-178\right]=9-(-58)=67\)
b, Tương tự như bài a
2.a,\(4^x\cdot5+4^2\cdot2=2^3\cdot7+56\)
\(\Leftrightarrow4^x\cdot5+16\cdot2=8\cdot7+56\)
\(\Leftrightarrow4^x\cdot5+32=56+56\)
\(\Leftrightarrow4^x\cdot5+32=112\)
\(\Leftrightarrow4^x\cdot5=80\)
\(\Leftrightarrow4^x=16\Leftrightarrow4^x=4^2\Leftrightarrow x=2\)
\(b,24:(2x-1)^3-2=1\)
\(\Leftrightarrow24:(2x-1)^3=3\)
\(\Leftrightarrow(2x-1)^3=8\)
\(\Leftrightarrow(2x-1)^3=2^3\)
\(\Leftrightarrow2x-1=2\)
Làm nốt là xong thôi
a,\(3^3.3^2-3^5+5^8.1-5^{12}:5^4\)
=\(3^5-3^5+5^8-5^8\)
=0
9!-8!-7! :\(8^2\)
=8!.9-8!-8!.8
=8!.(9-1-8)
=8!.0
=0
a) 20 : 22 + 59 : 58
= 20 : 4 + 59-8
= 5 + 51
= 5 + 5
= 10
b) 100 : 52 + 7 . 32
= 102 : 52 + 7 . 9
= ( 10 : 5 )2 + 63
= 22 + 63
= 4 + 63
= 67
\(2011-5.5^2-\left(7^3:7+2012^0\right)\\ =2011-5^3-\left(7^2+1\right)\\ =2011-125-50=1836\)
\(120:520:\left(500-5^3+35.7\right)\\ =120:520:\left(500-125+245\right)\\ =120:520:620=\dfrac{3}{8060}\)
\(2011-5\times5^2-\left[7^3:7+2012^0\right]\\ =2011-5^3-\left(7^2+1\right)\\ =2011-125-50\\ =1836\\ 120:520:\left[500-5^3+35\times7\right]\\ =120:520:\left[500-125+35\times7\right]\\ =120:520:620\\ =\dfrac{3}{8060}\)