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Tình GT của bt (Tính nhanh nếu có thể)
1) 13 - 12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1
=13-(12+9-10-11)+(8+5-7-6)+(3+2-4-1)
=13+0+0+0=13
2) 49 - (-54) - 23
=49+54-23
=80
3) 100 + (-520) + 1140 + (-620)
=( 100+1140)+(-620)+-520)
= 100
a) 13 - 18 - (-42) - 15
=13-18+42-15
=22
TICK CHO
T
5.7.77-7.60+49.25-15.42
= 5.7.77-7.5.12+7.7.5.5-3.5-3.5.6.7
= 35.77-35.12+35.35-35.18
= 35.(77-12+35-18)
= 35.82
= 2870
Mik đọc công thức bạn tự làm nhé áp dụng công thức nhé:
b1: a)SCSH: ( 2017 - 13 ) : 3 + 1 = 669 ( số hạng )
b2: Tổng: ( 2017 + 13 ) . 669 : 2 = 679035
b) SCSH: ( 2000 - 2 ) : 2 + 1 = 1000 ( số hạng )
Tổng: ( 2000 + 2 ) . 1000 : 2 = 1001000
c)SCSH: ( 102 - 1 ) : 1 + 1 = 102 ( số hạng )
Tổng: ( 102 + 1 ) . 102 : 2 = 5253
1. ( -37 ) + 14 + 26 + 37
=(-37+37)+(14+26)
=0+30
=30
2. ( -24 )+ 6 + 10 + 24
=(-24+24)+(6+10)
=0+16
=16
3. 15 + 23 + ( -25 ) + ( -32 )
=[15+(-25)]+[23+(-32)]
=-10+(-9)
=-19
4. 60 + 33 + ( -50 ) + ( -33 )
=[60+(-50)]+[33+(-33)]
=10+0
=10
5. (- 16 ) + ( -209 ) + ( -14 ) + 209
=[-16+(-14)]+(-209+209)
=-30+0
=-30
6. (- 12 ) + ( -13 ) + 36 + ( -11 )
=[-12+(-11)]+(-13+36)
=-23+23
=0
7. - 16 + 24 - 16 - 34
=(24-34)-16-16
=-10-16-16
=-42
8. 25 + 37 - 48 - 25 - 37
=(25-25)+(37-37)-48
=0+0-48
=-48
9. 2575 + 37 - 48 - 25 - 37
=(2575-25)+(37-37)
=2550+0
=2550
10. 34 + 35 + 36 + 37 - 14 - 15 - 16 - 17
=(34-14)+(35-15)+(36-16)+(37-17)
=20+20+20+20
=20.4
=80
cái này giống BTVN của mk,nhưng dễ mak,tự làm đc mak
cố lên
Bài 1:
\(\frac{3}{5}+\frac{4}{15}=\frac{9}{15}+\frac{4}{15}=\frac{13}{15}\)
\(\frac{5}{6}:\frac{-7}{12}=\frac{5}{6}.\frac{-12}{7}=\frac{-60}{42}=\frac{-10}{7}\)
\(\frac{-21}{24}:\frac{-14}{8}=\frac{-21}{24}.\frac{-8}{14}=\frac{168}{336}=\frac{1}{2}\)
\(\frac{4}{5}:\frac{-8}{15}=\frac{4}{5}.\frac{-15}{8}=\frac{-60}{40}=\frac{-3}{2}\)
\(\frac{5}{12}-\frac{-7}{6}=\frac{5}{12}+\frac{7}{6}=\frac{5}{12}+\frac{14}{12}=\frac{19}{12}\)
\(\frac{-15}{16}.\frac{8}{25}=\frac{-120}{400}=\frac{-3}{10}\)
Bài 2 :
\(6\frac{4}{5}-\left(1\frac{2}{3}+3\frac{4}{5}\right)\)
\(=\frac{34}{5}-\left(\frac{5}{3}+\frac{19}{5}\right)\)
\(=\frac{34}{5}-\frac{5}{3}-\frac{19}{5}\)
\(=\left(\frac{34}{5}-\frac{19}{5}\right)-\frac{5}{3}\)
\(=3-\frac{5}{3}\)
\(=\frac{4}{3}\)
\(6\frac{5}{7}-\left(1\frac{2}{3}+2\frac{5}{7}\right)\)
\(=\frac{47}{7}-\left(\frac{5}{3}+\frac{19}{7}\right)\)
\(=\frac{47}{7}-\frac{5}{3}-\frac{19}{7}\)
\(=\left(\frac{47}{7}-\frac{19}{7}\right)-\frac{5}{3}\)
\(=4-\frac{5}{3}\)
\(=\frac{7}{3}\)
\(\frac{4}{19}.\frac{-3}{7}+\frac{-3}{7}.\frac{15}{19}+\frac{5}{7}\)
\(=\left(\frac{4}{19}+\frac{15}{19}\right).\frac{-3}{7}+\frac{5}{7}\)
\(=1.\frac{-3}{7}+\frac{5}{7}\)
\(=\frac{-3}{7}+\frac{5}{7}\)
\(=\frac{2}{7}\)
\(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.1\)
\(=\frac{5}{9}\)
a) \(\frac{3}{8}+\frac{7}{12}+\frac{10}{16}+\frac{10}{24}\)
= \(\frac{3}{8}+\frac{7}{12}+\frac{5}{8}+\frac{5}{12}\)
=\(\left(\frac{3}{8}+\frac{5}{8}\right)+\left(\frac{7}{12}+\frac{5}{12}\right)\)
= \(\frac{8}{8}+\frac{12}{12}\)
= \(1+1\)
=\(2\)
b) \(\frac{4}{6}+\frac{7}{13}+\frac{17}{9}+\frac{19}{13}+\frac{1}{9}+\frac{14}{6}\)
= \(\frac{2}{3}+\frac{7}{13}+\frac{17}{9}+\frac{19}{13}+\frac{1}{9}+\frac{7}{3}\)
= \(\left(\frac{2}{3}+\frac{7}{3}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{17}{9}+\frac{1}{9}\right)\)
= \(\frac{9}{3}+\frac{26}{13}+\frac{18}{9}\)
= \(3+2+2\)
= \(7\)
Chúc bạn học tốt
Tính nhanh:
a, 3/8 + 7/12 + 10/16 + 10/24
= (3/8 + 10/16) + (7/12 + 10/24)
= (6/16 + 10/16) + (14/24 + 10/24)
= 16/16 + 24/24
= 1 + 1 = 2.
b, 4/6 + 7/13 + 17/9 + 19/13 + 1/9 + 14/6
= (4/6 + 14/6) + (7/13 + 19/13) + (17/9 + 1/9)
= 18/6 + 26/13 + 18/9
= 3 + 2 + 2 = 7.
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tham khảo nha
\(\text{A= 2+(-4)+(-6)+8+10+(-12)+(-14)+16+...+2010}\)
\(\text{A=[2+(-4)+(-6)+8] + [10+(-12)+(-14)+16] + ... + [2007+(-2008)+(-2009)+2010]}\)
\(\text{A= 0 + 0 + ... + 0}\)
\(\text{A= 0}\)
\(\text{B=1+(-3)+(-5)+7+9+(-11)+(-13)+15+...+2009}\)
\(\text{B=[1+(-3)+(-5)+7]+[9+(-11)+(-13)+15]+...+[2003+(-2005)+(-2007)+2009]}\)
\(\text{B=0 + 0 + ... + 0}\)
\(b=0\)