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\(a,50\%+\dfrac{7}{12}-\dfrac{1}{2}\\ =\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}\\ =\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}\\ =\dfrac{7}{12}\\ b,2022\times67+2022\times43-2022\times10\\ =2022\times\left(67+43-10\right)\\ =2022\times100\\ =202200.\\ c,125-25:3\times12\)
\(=25\times5-25:3\times12\\ =25\times\left(5-\dfrac{1}{3}\right)\times12\\ =25\times\dfrac{14}{3}\times12\\ =1400\)
a,50%+127−21=21+127−21=(21−21)+127=127b,2022×67+2022×43−2022×10=2022×(67+43−10)=2022×100=202200.c,125−25:3×12
=25×5−25:3×12=25×(5−13)×12=25×143×12=1400=25×5−25:3×12=25×(5−31)×12=25×314×12=1400
a)(33,76+6,24)+19,52
=40+19,52
=59,52
b) (\(\frac{38}{11}\)+\(\frac{6}{11}\)) +\(\frac{13}{16}\)
=4+\(\frac{13}{16}\)
=\(\frac{77}{16}\)
\(\frac{2006\times125+1000}{126\times2006-1006}=\frac{2006\times125+1000}{\left(125+1\right)\times2006-1006}=\frac{2006\times125+1000}{2006\times125+2006\times1-1006}\)
\(=\frac{2006\times125+1000}{2006\times125+1000}=1\)
\(\frac{2006.125+1000}{126.2006-1006}=\frac{2006.125+1000}{\left(125+1\right).2006-1006}=\frac{2006.125+1000}{125.2006+1.2006-1006}=\frac{2006.125+1000}{125.2006+1000}=1\)
a)=384:(25*4)=384:100=3,84.
b)37/25:5/4:74/25=37/25*4/5*25/74=37*4*25/5*25*74=2/5.
c)380:(38*2)=(380:38):2=10:2=5.
d)6/11:4/3:5/11:4/3=6/11*3/4*11/5*3/4=6*3*11*3/11*4*5*4=27/40.
k nha
\(17\cdot\frac{3}{4}-17\cdot0,25+17\cdot\frac{1}{2}\)
\(=17\cdot0,75-17\cdot0,25+17\cdot0,5\)
\(=17\cdot\left(0,75-0,25+0,5\right)\)
\(=17\cdot1\)
\(=17\)
\(17\times\frac{3}{4}-17\times0,25+17\times\frac{1}{2}\)\(=17\times\frac{3}{4}-17\times\frac{1}{4}+17\times\frac{1}{2}\)\(=17\times\left(\frac{3}{4}-\frac{1}{4}+\frac{1}{2}\right)\)
\(=17\times\left(1\right)\)\(=17\)
0,1-0,2+0,3-0,4+0,5-0,6+0,7-0,8+0,9-1+1,1
=0,1+(-0,2+0,3)+(-0,4+0,5)+(-0,6+0,7)+(-0,8+0,9)+(-1+1,1)
=0,1+0,1+0,1+0,1+0,1+0,1
=0,6 :))
c) 25