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a,
\(3\frac{28}{32}=3+\frac{28}{32}=3+\frac{7}{8}=3+0,875=3,875\)
\(7\frac{15}{75}=7+\frac{15}{75}=7+\frac{1}{5}=7+0,2=7,2\)
b,
\(\frac{37}{8}=\frac{8+8+8+8+5}{8}=\frac{8\times4+5}{8}=\frac{8\times4}{8}+\frac{5}{8}=4+\frac{5}{8}=4\frac{5}{8}\)
\(\frac{149}{25}=\frac{100+25+24}{25}=\frac{100}{25}+\frac{25}{25}+\frac{24}{25}=4+1+\frac{24}{25}=5+\frac{24}{25}=5\frac{24}{25}\)
\(\frac{257}{41}=\frac{246+11}{41}=\frac{246}{41}+\frac{11}{41}=6+\frac{11}{41}=6\frac{11}{41}\)
1) \(4\frac{3}{10}=\frac{43}{10};21\frac{7}{100}=\frac{2107}{100};7\frac{39}{100}=\frac{739}{100};6\frac{123}{1000}=\frac{6123}{1000}\)
2)\(a,5\frac{2}{10}+7\frac{1}{10}=\frac{52}{10}+\frac{71}{10}=\frac{123}{10}\)
\(b,5\frac{6}{7}-3\frac{5}{7}=\frac{41}{7}-\frac{26}{7}=\frac{15}{7}\)
\(c,8\frac{3}{5}x2\frac{6}{7}=\frac{43}{5}x\frac{20}{7}=\frac{172}{7}\)
\(d,1\frac{3}{10}:5\frac{7}{8}=\frac{13}{10}:\frac{47}{8}=\frac{13}{10}x\frac{47}{8}=\frac{611}{80}\)
3) \(7\frac{9}{10}và4\frac{9}{10}\)
Ta có: \(7\frac{9}{10}=\frac{79}{10};4\frac{9}{10}=\frac{49}{10}\)
Suy ra: \(\frac{79}{10}>\frac{49}{10}hay7\frac{9}{10}>4\frac{9}{10}\)
\(6\frac{3}{10}và6\frac{5}{9}\)
Ta có: \(6\frac{3}{10}=\frac{63}{10};6\frac{5}{9}=\frac{59}{9}\)
Suy ra: \(\frac{63}{10}>\frac{59}{9}hay6\frac{3}{10}>6\frac{5}{9}\)
5\(\frac{3}{5}\)= \(\frac{28}{5}\)
4\(\frac{2}{3}\)= \(\frac{14}{3}\)
6\(\frac{6}{7}\)= \(\frac{48}{7}\)
\(5\frac{3}{5}=5.6\) \(4\frac{2}{3}=4\left(6\right)\) \(6\frac{5}{7}=6\left(714285\right)\)
6 5 7 = 6 × 7 + 5 7 = 47 7
Chọn B