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\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^9.2^6.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^9.2^6.3^8}{2^9.2^6.3^6}=\frac{2^9.2^6.3^6.3^2}{2^9.2^6.3^6}=3^2=9\)
\(\frac{2^7\cdot9^3}{6^5\cdot8^2}\)
\(=\frac{2^7\cdot3^6}{3^5\cdot2^5\cdot2^6}\)
\(=\frac{3}{16}\)
\(\frac{2^5.9^4}{6^6.8^3}=\frac{2^5.3^8}{2^6.3^6.2^9}=\frac{3^2}{2.2^9}=\frac{9}{2^{10}}=\frac{9}{1024}\)
Hok tốt
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\(\dfrac{2^{15}.9^4}{6^6.8^3}=\dfrac{2^{15}.\left(3^2\right)^4}{2^6.3^6.\left(2^3\right)^3}=\dfrac{2^{15}.3^8}{2^6.3^6.2^9}=\dfrac{2^{15}.3^8}{2^{15}.3^6}=\dfrac{1.3^2}{1.1}=3^2=9\)
Chúc Bạn Học Tốt!!!
- Ta có:
\(\dfrac{2^{15}.9^4}{6^6.8^3}=\dfrac{2^{15}.\left(3^2\right)^4}{2^6.3^6.\left(2^3\right)^3}=\dfrac{2^{15}.3^8}{2^6.3^6.2^9}=\dfrac{2^{15}.3^8}{2^{15}.3^6}=3^2\)
- Vậy \(\dfrac{2^{15}.9^4}{6^6.8^3}=3^2\)
a) \(\frac{2^{11}.9^2}{3^5.16^2}=\frac{2^{11}.3^4}{3^5.2^8}=\frac{2^3}{3}=\frac{8}{3}\)
:V Làm sai hết rồi sai ngay từ bước đầu tiên.
\(\frac{1}{3.4}-\frac{1}{4.5}-\frac{1}{5.6}-....-\frac{1}{9.10}\)
\(=\frac{1}{3.4}-\left(\frac{1}{4.5}+\frac{1}{5.6}+....+\frac{1}{9.10}\right)\)
\(=\frac{1}{12}-\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=\frac{1}{12}-\left(\frac{1}{4}-\frac{1}{10}\right)\)
\(=\frac{1}{12}-\frac{3}{20}\)
\(=\frac{-11}{12}\)
\(\frac{1}{3.4}-\frac{1}{4.5}-...-\frac{1}{9.10}\)
= \(-\left(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)
= \(-\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)\)
= \(-\left(\frac{1}{3}-\frac{1}{10}\right)\)
= \(-\frac{7}{30}\)
\(\frac{4^2\times4^3}{2^{10}}=\frac{\left(2^2\right)^2\times\left(2^2\right)^3}{2^{10}}=\frac{2^4\times2^6}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2\times3\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2\right)^5\times3^5}{\left(0,2\right)^6}=\frac{3^5}{0,2}=\frac{243}{0,2}=243:\left(0,2\right)=243\times5=1215\)
\(\frac{2^7\times9^3}{6^5\times8^2}=\frac{2^7\times\left(3^2\right)^3}{\left(2\times3\right)^5\times\left(2^3\right)^2}=\frac{2^7\times3^6}{2^5\times3^5\times2^6}=\frac{3}{2^4}=\frac{3}{16}\)
\(\frac{6^3+3\times6^2+3^3}{-13}=\frac{\left(2\times3\right)^3+3\times6^2+3^3}{-13}=\frac{3\left(2^3\times3^2+6^2+3^2\right)}{-13}=\frac{3\times117}{-13}=\frac{351}{-13}=-27\)
\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}=\frac{2^{15}.3^8}{2^{15}.3^6}=\frac{3^8}{3^6}=3^2=9\)