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\(B=\left(\frac{151515}{161616}+\frac{17^9}{17^{10}}\right)-\left(\frac{1500}{1600}-\frac{176}{187}\right)\)
\(B=\left(\frac{15}{16}+\frac{1}{17}\right)-\left(\frac{15}{16}-\frac{16}{17}\right)\)
\(B=\frac{15}{16}+\frac{1}{17}-\frac{15}{16}+\frac{16}{17}\)
\(B=\left(\frac{15}{16}-\frac{15}{16}\right)+\left(\frac{1}{17}+\frac{16}{17}\right)\)
\(B=0+1=1\)
Vậy: B=1
các bạn vào link này để thi đua cùng mình nha:
https://iostudy.net/ref/132310
ai vào mình tích đúng 5 lần
\(=\dfrac{\dfrac{31}{3}\cdot\left(26+\dfrac{1}{3}-\dfrac{176}{7}\right)-\dfrac{12}{11}\cdot\left(\dfrac{10}{3}-\dfrac{7}{4}\right)}{\left(\dfrac{5}{90.75}\right)\cdot\dfrac{60}{11}-1}\)
\(=\dfrac{\dfrac{31}{3}\cdot\dfrac{25}{21}-\dfrac{12}{11}\cdot\dfrac{19}{12}}{-\dfrac{931}{1331}}\)
\(=\dfrac{7328}{693}:\dfrac{-931}{1331}\simeq-15.118\)
\(B=\left(\frac{15}{16}+\frac{1}{17}\right)-\left(\frac{15}{16}-\frac{16.11}{17.11}\right)\)
\(B=\frac{15}{16}+\frac{1}{17}-\frac{15}{16}+\frac{16}{17}\)
\(B=\frac{1}{17}+\frac{16}{17}=\frac{17}{17}=1\)
Ta có:\(\frac{1}{6}+\frac{1}{66}+\frac{1}{176}+...+\frac{1}{\left(5n+1\right)\left(5n+6\right)}\)
\(=\frac{1}{5}.\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+...+\frac{5}{\left(5n+1\right)\left(5n+6\right)}\right)\)
\(=\frac{1}{5}.\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+...+\frac{1}{5n+1}-\frac{1}{5n+6}\right)\)
\(=\frac{1}{5}.\left(1-\frac{1}{5n+6}\right)\)
\(=\frac{1}{5}.\left(\frac{5n+5}{5n+6}\right)=\frac{n+1}{5n+6}\left(\text{đ}pcm\right)\)
- 482 - ( 176 - 482 ) - [ 2750 - ( 176 + 2750 ) ]
= - 482 - 176 + 482 - ( 2750 - 2926 )
= 482 - 482 - 176 - ( - 176 )
= 0 - 0
= 0