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\(\frac{1996\times1995-996}{1000+1996\times1994}\)
\(=\frac{1996\times\left(1994+1\right)-996}{1996\times1994+1000}\)
\(=\frac{1996\times1994+1996\times1-996}{1996\times1994+1000}\)
\(=\frac{1996\times1994+1996-996}{1996\times1994+1000}\)
\(=\frac{1996\times1994+1000}{1996\times1994+1000}=1\)
\(\frac{1,65\times25+117\times1,65+1,65\times108}{150\times0,25+1,4\times150}\)
\(=\frac{\left(25+117+108\right)\times1,65}{150\times\left(0,25+1,4\right)}\)
\(=\frac{250\times1,65}{150\times1,65}\)
\(=\frac{\left(150+100\right)\times1,65}{150\times1,65}\)
\(=\frac{150\times1,65+100\times1,65}{150\times1,65}\)
\(=\frac{150\times1,65+165}{150\times1,65}=\frac{165}{1}=165\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{6.7}+\frac{1}{7.8}\)
\(=\frac{1}{1}-\frac{1}{8}\)
\(=\frac{7}{8}\)'
a) \(\frac{999}{10000}=\frac{99,9}{1000}>\frac{99}{100}\)
=> kết luận
b) \(1-\frac{97}{99}=\frac{2}{99}>1-\frac{98}{100}=\frac{2}{100}\)
\(\Rightarrow\frac{97}{99}< \frac{98}{100}\)
=> kết luận
\(\left(a\right)\frac{9}{8}+\frac{15}{32}=\frac{36}{32}+\frac{15}{32}=\frac{36+15}{32}=\frac{51}{32}\)
\(\left(b\right)4+\frac{35}{45}=\frac{4}{1}+\frac{35}{45}=\frac{180}{45}+\frac{35}{45}=\frac{180+35}{45}=\frac{43}{9}\)
\(\left(c\right)\frac{11}{4}-\frac{15}{16}=\frac{44}{16}-\frac{15}{16}=\frac{44-15}{16}=\frac{29}{16}\)
\(\left(d\right)3-\frac{13}{9}=\frac{3}{1}-\frac{13}{9}=\frac{27}{9}-\frac{13}{9}=\frac{27-13}{9}=\frac{14}{9}\)
\(\left(e\right)\frac{5}{6}-\frac{5}{8}=\frac{20}{24}-\frac{15}{24}=\frac{20-15}{24}=\frac{5}{24}\)
\(\left(g\right)\frac{196}{64}-2=\frac{196}{64}-\frac{2}{1}=\frac{196}{64}-\frac{128}{64}=\frac{196-128}{64}=\frac{17}{16}\)
Mình đảm bảo đúng ! Chúc bạn học tốt!
a) \(\frac{9}{8}+\frac{15}{32}=\frac{36}{32}+\frac{15}{32}=\frac{51}{32}\)
b) \(4+\frac{35}{45}=4+\frac{7}{9}=\frac{36}{9}+\frac{7}{9}=\frac{43}{9}\)
c)\(\frac{11}{4}+\frac{15}{16}=\frac{44}{16}+\frac{15}{16}=\frac{59}{16}\)
d )\(3-\frac{13}{9}=\frac{27}{9}-\frac{13}{9}=\frac{14}{9}\)
e ) \(\frac{5}{6}+\frac{5}{8}=\frac{40}{48}+\frac{30}{48}\)\(=\frac{70}{48}\)
1995x1994-1/1993x1995+1994
=1995x[1993+1]-1/1993x1995+1994
=1995x1993+1x1995 -1/1993x1995+1994
=1995x1993+1995-1/1993x1995+1994
=1995x19931994/1993+1995+1994
=1
\(\frac{1995\times1994-1}{1993\times1995+1994}\)
\(=\frac{3978029}{3978029}\)
\(=3978029:3978029\)
\(=1\)
k mik nha bn
thank you very much
1995x1994-1/1993x1995+1994
=1995x[1993+1]-1/1993x1995+1994
=1995x1993+1995x1-1/1993x1995+1994
=1995x1993+1995-1/1993x1995+1994
=1995x1993+1994/1993x1995+1994
=1