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18 tháng 9 2017

317.8111/2710.915

=317.(34)11/(33)10.(32)15

=317.344/330.330

=361/360

=3

18 tháng 9 2017

\(\frac{3^{17}.81^{11}}{27^{10}.9^{15}}=\frac{3^{17}.\left(3^4\right)^{11}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\frac{3^{17}.3^{41}}{3^{30}.3^{30}}=\frac{3^{17+41}}{3^{30+30}}=\frac{3^{58}}{3^{60}}=\frac{1}{3^2}=\frac{1}{9}\)

nho k day

\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=3\)

giúp tớ nhé 

tớ bị trừ 41 điểm 

cảm ơn trước

cảm ơn huhuh

8 tháng 9 2016

\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}=\frac{\left(3^4\right)^{11}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\frac{3^{44}.3^{17}}{3^{30}.3^{30}}=\frac{3^{61}}{3^{60}}=\frac{3^1}{1}=3\)

2 tháng 12 2018

\(A=\frac{\left(9^2\right)^{11}.3^{17}}{\left(3^3\right)^{10}.9^{15}}=\frac{9^{22}.3^{17}}{3^{30}.9^{15}}=\frac{9^7}{3^{12}}=9\)

29 tháng 11 2016

3^12.(3^4)^11/(3^3)^10.(3^2)^15=3^12.3^44/3^30.3^30=3^56/3^30

29 tháng 11 2016

=3^17.9^22/3^30.9^15=9^7/3^13=3^14/3^13=3^1=3

giùm nhé bạn

8 tháng 8 2017

\(\frac{2^{15}.9^4}{6^3.8^3}\)=\(\frac{2^{15}.\left(3^2\right)^3}{\left(2.3\right)^3.\left(2^3\right)^3}\)=\(\frac{2^{15}.3^6}{2^3.3^3.2^9}\)=\(\frac{2^{15}.3^6}{2^{12}.3^3}\)=\(2^3.3^3\)=8.27=216

13 tháng 7 2017

f) \(\frac{25^2.20^4}{5^{10}.4^5}=\frac{\left(5^2\right)^5.\left(4.5\right)^4}{5^{10}.4^5}=\frac{5^{10}.5^4.4^4}{5^{10}.4^5}=\frac{5^{14}.4^4}{5^{10}.4^5}=\frac{5^4}{4}\)

i) \(\frac{9^{15}.81^4}{27^8.3^{20}}=\frac{\left(3^2\right)^{15}.\left(3^4\right)^4}{\left(3^3\right)^8.3^{20}}=\frac{3^{30}.3^{16}}{3^{24}.3^{20}}=\frac{3^{46}}{3^{44}}=3^2=9\)

13 tháng 7 2017

f) Ta có: \(\frac{25^2.20^4}{5^{10}.4^5}\)\(\frac{\left(5^2\right)^2.\left(4.5\right)^4}{5^{10}.4^5}\)\(\frac{5^4.4^4.5^4}{5^{10}.4^5}\)\(\frac{5^8.4^4}{5^{10}.4^5}\)\(\frac{1}{5^2.4}\)=\(\frac{1}{100}\).

i) Ta có: \(\frac{9^{15}.81^4}{27^8.3^{20}}\)\(\frac{\left(3^2\right)^{15}.\left(3^4\right)^4}{\left(3^3\right)^8.3^{20}}\)\(\frac{3^{30}.3^8}{3^{24}.3^{20}}\)\(\frac{3^{38}}{3^{44}}\)=\(\frac{1}{3^6}\)\(\frac{1}{729}\)

10 tháng 9 2016

a)

\(\Rightarrow A=\frac{\frac{1}{11}-\frac{1}{13}-\frac{1}{17}}{5\left(\frac{1}{11}-\frac{1}{13}-\frac{1}{17}\right)}+\frac{2\left(\frac{1}{3}-\frac{1}{9}-\frac{1}{27}+\frac{1}{81}\right)}{7\left(\frac{1}{3}-\frac{1}{9}-\frac{1}{27}+\frac{1}{81}\right)}\)

\(\Rightarrow A=\frac{1}{5}+\frac{2}{7}\)

\(\Rightarrow A=\frac{17}{35}\)

b)

\(\Rightarrow B=5\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+....+\frac{1}{56}-\frac{1}{61}\right)\)

\(\Rightarrow B=5\left(\frac{1}{11}-\frac{1}{61}\right)\)

\(\Rightarrow B=5.\frac{50}{671}=\frac{250}{671}\)

c)

\(\Rightarrow C=1-\left(\frac{1}{1.3}+\frac{1}{2.3}+\frac{1}{2.5}+....+\frac{1}{49.25}\right)\)

\(\Rightarrow C=1-2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+....+\frac{1}{49.50}\right)\)

\(\Rightarrow C=1-2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{49}-\frac{1}{50}\right)\)

\(\Rightarrow C=1-1-\frac{1}{25}\)

\(\Rightarrow C=\frac{1}{25}\)