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72/180 = 2/5. 135/225 = 3/5. 625/600 = 25/24. 191919/373737 = 19/37.
**** bạn.
\(-\frac{20+44}{56-12}=\frac{-64}{44}=\)\(\frac{-16}{11}\)
\(\frac{-120+70}{30+60}\)=\(\frac{-5}{9}\)
Ta có \(\frac{-16}{11}< \frac{-11}{11}=-1\)
\(\frac{-5}{9}>\frac{-9}{9}=-1\)
nên \(\frac{-5}{9}>-1>\frac{-16}{11}\)
Vậy \(\frac{-5}{9}>\frac{-16}{11}\)
tự kết luận nhé
\(\frac{7.25-49}{7.24+21}=\frac{7.25-7.7}{7.24+7.3}=\frac{7\left(25-7\right)}{7\left(24+3\right)}=\frac{25-7}{24+3}=\frac{18}{27}=\frac{2}{3}\)
\(10A=\frac{10\left(10^{29}+10^{10}\right)}{10^{30}+10^{10}}=\frac{10^{30}+10^{11}}{10^{30}+10^{10}}=1+\frac{10^{11}-10^{10}}{10^{30}+10^{10}}\)
\(10B=\frac{10\left(10^{30}+10^{10}\right)}{10^{31}+10^{10}}=\frac{10^{31}+10^{11}}{10^{31}+10^{10}}=1+\frac{10^{11}-10^{10}}{10^{31}+10^{10}}\)
\(10^{30}+10^{10}< 10^{31}+10^{10}\Rightarrow\frac{10^{11}-10^{10}}{10^{30}+10^{10}}>\frac{10^{11}-10^{10}}{10^{31}+10^{10}}\)
\(\Rightarrow10A=1+\frac{10^{11}-10^{10}}{10^{30}+10^{10}}>10B=1+\frac{10^{11}-10^{10}}{10^{31}+10^{10}}\)
\(\Rightarrow A>B\)
\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)
\(=\frac{15015.37-273.37}{32760.37+1093.37}\)
\(=\frac{14742.37}{33853.37}\)
\(=\frac{14742}{33853}\)
\(\frac{x}{8}=\frac{-15}{30}\)
\(\Rightarrow x=\frac{-15.8}{30}\)
\(\Rightarrow x=-4\)
\(\frac{y}{6}=\frac{15}{-45}\)
\(\Rightarrow y=\frac{15.6}{-45}\)
\(\Rightarrow y=-2\)
A) \(\frac{x}{8}=\frac{-15}{30}\)
\(\Leftrightarrow\)\(x=\frac{\left(-15\right).8}{30}=-4\)
Vậy...
B) \(\frac{y}{6}=\frac{15}{-45}\)
\(\Leftrightarrow\)\(y=\frac{15.6}{-45}=-2\)
Vậy....
\(\frac{373737-10101}{818181-30303}=\frac{363636}{787878}=\frac{36}{78}\)
\(\frac{474}{2054}=\frac{3}{13}\)
Ta có \(\frac{3}{13}=\frac{18}{78}\)
\(\Rightarrow\frac{18}{78}< \frac{36}{78}\)
\(\frac{373737-10101}{818181-30303}\)
=\(\frac{37.10101-10101}{81.10101-10101.3}\)
=\(\frac{10101.\left(37-1\right)}{10101.\left(81-3\right)}\)
=\(\frac{36}{78}\)
=\(\frac{6.6}{6.13}\)
=\(\frac{6}{13}\)
hk tốt nha bn