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\(a,\frac{3x+2}{\sqrt{x+2}}=2\sqrt{x+2}\)
\(\Rightarrow3x+2=2\sqrt{x+2}.\sqrt{x+2}\)
\(\Rightarrow3x+2=2\left(x+2\right)\)
\(\Rightarrow3x+2=2x+4\)
\(\Rightarrow3x-2x=4-2\)
\(\Rightarrow x=2\)
\(b,\sqrt{4x^2-1}-2\sqrt{2x+1}=0\)
\(\Rightarrow\sqrt{\left(2x+1\right)\left(2x-1\right)}-2\sqrt{2x+1}=0\)
\(\Rightarrow\sqrt{2x+1}\left(\sqrt{2x-1}-2\right)=0\)
\(\Rightarrow\hept{\begin{cases}\sqrt{2x+1}=0\\\sqrt{2x-1}-2=0\end{cases}\Rightarrow\orbr{\begin{cases}2x+1=0\\\sqrt{2x-1}=2\end{cases}\Rightarrow}\orbr{\begin{cases}2x=-1\\2x-1=4\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{1}{2}\\2x=5\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{1}{2}\\x=\frac{5}{2}\end{cases}}}\)
\(c,\sqrt{x-2}+\sqrt{4x-8}-\frac{2}{5}\sqrt{\frac{25x-50}{4}}=4\)
\(\Rightarrow\sqrt{x-2}+\sqrt{4\left(x-2\right)}-\frac{2}{5}\sqrt{\frac{25\left(x-2\right)}{4}}=4\)
\(\Rightarrow\sqrt{x-2}+2\sqrt{x-2}-\frac{2}{5}.\frac{5\sqrt{x-2}}{2}=4\)
\(\Rightarrow\sqrt{x-2}+2\sqrt{x-2}-\sqrt{x-2}=4\)
\(\Rightarrow2\sqrt{x-2}=4\)
\(\Rightarrow\sqrt{x-2}=2\)
\(\Rightarrow x-2=4\)
\(\Rightarrow x=6\)
\(d,\sqrt{x+4}-\sqrt{1-x}=\sqrt{1-2x}\)
\(\Rightarrow\sqrt{x+4}=\sqrt{1-2x}+\sqrt{1-x}\)
\(\Rightarrow x+4=1-2x+2\sqrt{\left(1-2x\right)\left(1-x\right)}+1-x\)
\(\Rightarrow x+4=2-3x+2\sqrt{1-3x+2x^2}\)
\(\Rightarrow x+4-2+3x=2\sqrt{1-3x+2x^2}\)
\(\Rightarrow4x+2=2\sqrt{1-3x+2x^2}\)
\(\Rightarrow2x+1=\sqrt{1-3x+2x^2}\)
\(\Rightarrow4x^2+4x+1=1-3x+2x^2\)
\(\Rightarrow4x^2-2x^2+4x+3x+1-1=0\)
\(\Rightarrow2x^2+7x=0\)
\(\Rightarrow x\left(2x+7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\2x+7=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{-7}{2}\end{cases}}}\)
\(e,\frac{2x}{\sqrt{5}-\sqrt{3}}-\frac{2x}{\sqrt{3}+1}=\sqrt{5}+1\)
\(\frac{2x\left(\sqrt{5}+\sqrt{3}\right)}{5-3}-\frac{2x\left(\sqrt{3}-1\right)}{3-1}=\sqrt{5}+1\)
\(\Rightarrow x\left(\sqrt{5}+\sqrt{3}\right)-x\left(\sqrt{3}-1\right)=\sqrt{5}+1\)
\(\Rightarrow\sqrt{5}x+\sqrt{3}x-\sqrt{3x}+x=\sqrt{5}+1\)
\(\Rightarrow\sqrt{5}x+x=\sqrt{5}+1\)
\(\Rightarrow x\left(\sqrt{5}+1\right)=\sqrt{5}+1\)
\(\Rightarrow x=1\)
a.\(\sqrt{\left(2x-1\right)^2}-2x+3\)
\(=2x-1-2x+3=2\)(vì x\(\ge\)1/2 nên 2x-1\(\ge\)0)
b.\(B=\sqrt{\frac{\left(3\sqrt{5}+1\right)\left(2\sqrt{5}+3\right)}{\left(2\sqrt{5}-3\right)\left(2\sqrt{5}+3\right)}}\left(\sqrt{10}-\sqrt{2}\right)\)
\(=\sqrt{\frac{33+11\sqrt{5}}{11}}\left(\sqrt{10}-\sqrt{2}\right)=\sqrt{3+\sqrt{5}}.\left(\sqrt{10}-\sqrt{2}\right)\)
\(=\sqrt{6+2\sqrt{5}}\left(\sqrt{5}-1\right)=\sqrt{\left(\sqrt{5}+1\right)^2}\left(\sqrt{5}-1\right)\)
\(=\left(\sqrt{5}-1\right)\left(\sqrt{5}+1\right)=4\)
a) \(\sqrt{x^2-9}-3\sqrt{x-3}=0\\ \Leftrightarrow\sqrt{\left(x-3\right)\left(x+3\right)}-3\sqrt{x-3}=0\\ \Leftrightarrow\sqrt{x-3}\left(\sqrt{x+3}-3\right)=0\\ \Leftrightarrow\left\{{}\begin{matrix}\sqrt{x-3}=0\\\sqrt{x+3}=3\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=3\\x=6\end{matrix}\right.\)
S = (3;6)
b)\(\sqrt{x^2-4}-2\sqrt{x-2}=0\\ \Leftrightarrow\sqrt{x-2}\left(\sqrt{x+2}-2\right)=0\\ \Leftrightarrow\left\{{}\begin{matrix}\sqrt{x-2}=0\\\sqrt{x+2}=2\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=2\\x=2\end{matrix}\right.\) S= (2)
c)\(\sqrt{\frac{2x-3}{x-1}}=2\left(đkxđ:x\ne1\right)\Leftrightarrow2\sqrt{x-1}=\sqrt{2x-3}\\ \Leftrightarrow2x=1\Leftrightarrow x=\frac{1}{2}\) S= (1/2)
d) đkxđ : x khác -1
\(\sqrt{\frac{4x+3}{x+1}}=3\Leftrightarrow4x+3=9x+9\Leftrightarrow x=-\frac{6}{5}\) S = (-6/5)
e) đk x >= 3/2
\(\frac{\sqrt{2x-3}}{\sqrt{x-1}}=2\Leftrightarrow2x-3=4x-4\Leftrightarrow x=\frac{1}{2}\) (loại) vậy pt vô nghiệm
f) đk x >= -3/4
\(\frac{\sqrt{4x+3}}{\sqrt{x+1}}=3\Leftrightarrow4x+3=9x+9\Leftrightarrow x=-\frac{6}{5}\) (loại) vậy pt vô nghiệm
