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a) \(10^n+1-6\cdot10^n=\left(1-6\right)10^n+1=-5\cdot10^n+1\)
b) \(90\cdot10^n-10^2-2+10^n+1=\left(90-1+1\right)\cdot10^n-2+1=90\cdot10^n-1\)
c) \(2,5\cdot56^n-3=\frac{5}{2}\cdot56^n-3\)
Ta có:\(5^n.2,5-30.5^n-6.5^n-1=5^n.\left(25-30-6\right)-1=5^n.\left(-11\right)-1\)-1
10n + 1 - 6.10n
= 10n . 10 - 6.10n
= 10n . (10 - 6)
= 4.10n
|5x - 10 |-x - 6 TH1 : 5x - 10 > 0 \(\Leftrightarrow\) 5x >10 \(\Leftrightarrow\)x >2 \(\Rightarrow\)|5x - 10 |-x - 6 = 5x - 10 -x -6 = 4x -16 = 4 ( x-4 ) TH2 : 5x - 10 < 0 \(\Leftrightarrow\) 5x < 10 \(\Leftrightarrow\) x< 2 \(\Rightarrow\)|5x -10|-x-6 = -5x +10-x-6 = -6x +4
a) 2^n (2^3 + 2^2 -2^1+1)=2^n(8+4-2+1)
=2^n * 11
b)10^n ( 90 -10^2 + 10 )=10^N * 0
= 0
\(\frac{3^{10}+6^2}{5\cdot3^8+20}\)
\(=\frac{3^{10}+\left(3\cdot2\right)^2}{5\left(3^8+4\right)}\)
\(=\frac{3^{10}+3^2\cdot2^2}{5\left(3^8+4\right)}\)
\(=\frac{3^2\left(3^8+4\right)}{5\left(3^8+4\right)}\)
\(=\frac{9}{5}\)
\(^{10^{n+1}-6.10^n}\)=\(^{10^n-10^n-6.10^n}\)
=\(^{4.10^n}\)
=>rút gọn thành 4.10^n
10^N+1-6-10^N
=10^N.10^N-6-10^N
=4.10^N
=4.10^N