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- 6x2+13x+6
=6x2+9x+4x+6
=3x(2x+3)+2(2x+3)
=(2x+3)(3x+2)
2. 6x2-15x+6
=6x2-12x-3x+6
=6x(x-2)-3(x-2)
=(x-2).3(2x-1)
3. 8x2 -2x-3
= 8x2-6x+4x-3
=2x(4x-3)+(4x-3)
=(4x-3)(2x+1)
4. 8x2-10x-3
=8x2+12x-2x-3
=4x(2x+3)-(2x+3)
=(2x+3)(4x-1)
5. -10x2+4x+6
=-10x2+10x-6x+6
=-10x(x-1)-6(x-1)
=(x-1).(-2)(5x+3)
6. 10x2-28x-6
=10x2-30x+2x-6
=10x(x-3)+2(x-3)
=(x-3).2(5x+1)
6x2 + 13x + 6 = 6x2 + 9x + 4x + 6 = 3x( 2x + 3 ) + 2( 2x + 3 ) = ( 2x + 3 )( 3x + 2 )
6x2 - 15x + 6 = 6x2 - 12x - 3x + 6 = 6x( x - 2 ) - 3( x - 2 ) = 3( x - 2 )( 2x - 1 )
10x2 + 17x - 6
\(=10x^2+20x-3x-6\)
\(=10x\left(x+2\right)-3\left(x+2\right)=\left(x+2\right)\left(10x-3\right)\)
- 10x2 - 17x +6
\(=-10x^2-20x+3x+6\)
\(=-10x\left(x+2\right)+3\left(x+2\right)=\left(x+2\right)\left(-10x+3\right)\)
- 10x2 + 28x + 6
\(=-10x^2+30x-2x+6\)
\(=-10x\left(x+3\right)-2\left(x+3\right)=-\left(x+3\right)\left(10x+2\right)\)
10x2 - 28x -6
\(=10x^2-30x+2x-6\)
\(=10x\left(x-3\right)+2\left(x-3\right)=\left(x-3\right)\left(10x+2\right)\)
1) \(6x^2-15x+6\)
\(=6x^2-3x-12x+6\)
\(=3x\left(2x-1\right)-6\left(2x-1\right)\)
\(=\left(3x-6\right)\left(2x-1\right)\)
\(=3\left(x-2\right)\left(2x-1\right)\)
b) \(6x^2-20x+6\)
\(=6x^2-2x-18x+6\)
\(=2x\left(3x-1\right)-6\left(3x-1\right)\)
\(=\left(2x-6\right)\left(3x-1\right)\)
\(=2\left(x-3\right)\left(3x-1\right)\)
c) \(-10x^2-7x+6\)
\(=5x-10x^2+6-12x\)
\(=5x\left(1-2x\right)+6\left(1-2x\right)\)
\(=\left(5x+6\right)\left(1-2x\right)\)
d) \(10x^2-7x-12\)
\(=10x^2-15x+8x-12\)
\(=5x\left(2x-3\right)+4\left(2x-3\right)\)
\(=\left(5x+4\right)\left(2x-3\right)\)
1) 6x^2 - 15x + 6
= 6x^2 - 12x - 3x +6
= 6x (x - 2) - 3 (x - 2)
= (x - 2) (6x - 3)
= 3 (x - 2) (x - 1)
2) 6x^2 - 20x + 6
= 6x^2 - 18x - 2x + 6
= 6x (x - 3) - 2 (x - 3)
= (x - 3) (6x - 2)
= 2 (x - 3) (3x - 1)
3) -10x^2 - 7x + 6
= -10x^2 + 5x - 12x + 6
= 5x (1 - 2x) + 6 (1 - 2x)
= (1 - 2x) (5x + 6)
4) 10x^2 - 7x - 12
= 10x^2 - 15x + 8x - 12
= 5x (2x - 3) + 4 (2x - 3)
= (2x - 3) (5x + 4)
good luck !
\(1.6x\left(x-10\right)-2x+20=0\)
⇔\(6x\left(x-10\right)-2\left(x-10\right)=0\)
⇔ \(2\left(x-10\right)\left(3x-1\right)=0\)
⇔ x = 10 hoặc x = \(\dfrac{1}{3}\)
KL....
\(2.3x^2\left(x-3\right)+3\left(3-x\right)=0\)
⇔ \(3\left(x-3\right)\left(x^2-1\right)=0\)
⇔ \(x=+-1\) hoặc \(x=3\)
KL....
\(3.x^2-8x+16=2\left(x-4\right)\)
⇔ \(\left(x-4\right)^2-2\left(x-4\right)=0\)
⇔ \(\left(x-4\right)\left(x-6\right)=0\)
⇔ \(x=4\) hoặc \(x=6\)
KL.....
\(4.x^2-16+7x\left(x+4\right)=0\)
\(\text{⇔}4\left(x+4\right)\left(2x-1\right)=0\)
⇔ \(x=-4hoacx=\dfrac{1}{2}\)
KL.....
\(5.x^2-13x-14=0\)
⇔ \(x^2+x-14x-14=0\)
\(\text{⇔}\left(x+1\right)\left(x-14\right)=0\)
\(\text{⇔}x=14hoacx=-1\)
KL......
Còn lại tương tự ( dài quá ~ )
\(-10x^2+11x+6\)
\(=-10x^2-4x+15x+6\)
\(=-2x\left(5x+2\right)+3\left(5x+2\right)\)
\(=\left(-2x+3\right)\left(5x+2\right)\)
\(10x^2-4x-6\)
\(=10x^2-10x+6x-6\)
\(=10x\left(x-1\right)+6\left(x-1\right)\)
\(=\left(10x+6\right)\left(x-1\right)\)
\(=2\left(5x+3\right)\left(x-1\right)\)
\(-10x^2+4x+6\)
\(=-2\left(5x^2-2x-3\right)\)
\(=-2\left[5x^2-5x+3x-3\right]\)
\(=-2\left[5x\left(x-1\right)+3\left(x-1\right)\right]\)
\(=-2\left(x-1\right)\left(5x+3\right)\)
\(10x^2+7x-6\)
\(=10x^2+12x-5x-6\)
\(=2x\left(5x+6\right)-\left(5x+6\right)\)
\(=\left(5x+6\right)\left(2x-1\right)\)
Xin lỗi bạn,mk ms học đến phân tích đa thức thành nhân tử nhóm nhiều hạng tử,còn phần này mk ms học còn yếu lắm.
1. \(-10x^2+11x+6\)
\(=-10x^2+15x-4x+6\)
\(=-5x\left(2x-3\right)-2\left(2x-3\right)\)
\(=\left(-5x-2\right)\left(2x-3\right)\)
2.\(10x^2-4x-6\)
\(=2\left(5x^2-2x-3\right)\)
\(=2\left(5x^2+3x-5x-3\right)\)
\(=2\left[x\left(5x+3\right)-\left(5x+3\right)\right]\)
\(=2\left(x-1\right)\left(5x+3\right)\)
3. \(10x^2+7x-6\)
\(=10x^2+12x-5x-6\)
\(=2x\left(5x+6\right)-\left(5x+6\right)\)
\(=\left(2x-1\right)\left(5x+6\right)\)
4. \(10x^2-14x-12\)
\(=2\left(5x^2-7x-6\right)\)
\(=2\left(5x^2+3x-10x-6\right)\)
\(=2\left[x\left(5x+3\right)-2\left(5x+3\right)\right]\)
\(=2\left(x-2\right)\left(5x+3\right)\)