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\(x^2-y^2+4x+4\)
\(=\left(x+2\right)^2-y^2\)
\(=\left(x+2+y\right)\left(x+2-y\right)\)
\(4x^2-y^2+8\left(y-2\right)\)
\(=4x^2-\left(y^2-8y+16\right)\)
\(=4x^2-\left(y-4\right)^2\)
\(=\left(2x+y-4\right)\left(2x-y+4\right)\)
a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
x2-7x+12
=x2-3x-4x+12
=x(x-3)-4(x-3)
=(x-3)(x-4)
x4-4x2+4x-1
=x4-1-4x2+4x
=(x2-1)(x2+1)-4x(x-1)
=(x-1)(x+1)(x2+1)-4x(x-1)
=(x-1)[(x+1)(x2+1)-4x]
=(x-1)(x3+x2+x+1-4x)
=(x-1)(x3+x2-3x+1)
6x4-11x2+3
=6x4-2x2-9x2+3
=2x2(3x2-1)-3(3x2-1)
=(3x2-1)(2x2-3)
a x2 - 7x - 6 = x2 -6x-x-6
= x(x-6)+(x-6)
= (x+1)(x+6)
b x3 + 4x2 - 7x -10
=x3 - 2x2 + 6x2 -12x+5x-10
= x2(x-2) + 6x(x-2) + 5(x-2)
= (x2 +6x+5)(x-2)
=(x2 +x+5x+5)(x-2)
=[x(x+1)+5(x+1)](x-2)
=(x+5)(x+1)(x-2)
c x3 +x2-2
=x3-x2+2x2-2x+2x-2
=x2(x-1)+2x(x-1)+2(x-1)
=(x2+2x+2)(x-1)
d x2 +5x+6
=x2 +2x+3x+6
=x(x+2)+3(x+2)
=(x+3)(x-2)
Con 1 y e nhung luoi lam
mk chỉnh lại đề
\(x^2-7x+6\)
\(=x^2-x-6x+6\)
\(=x\left(x-1\right)-6\left(x-1\right)\)
\(=\left(x-1\right)\left(x-6\right)\)
\(x^2+y^2-1-2xy\)
\(=\left(x-y\right)^2-1\)
\(=\left(x-y+1\right)\left(x-y-1\right)\)
a) x^2- 4x + 4 -y^2 = (x-2)^2 - y^2 = (x+y-2)(x-y-2)
b) x^2 - 7x + 10 = x^2 - 5x - 2x + 10 = x(x-5) - 2(x-5) = (x-2)(x-5)