Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{2}{3}\) + \(\frac{3}{4}\) = \(\frac{8}{12}\) + \(\frac{9}{12}\) = \(\frac{17}{12}\)
\(\frac{5}{6}\) x \(\frac{4}{15}\) = \(\frac{2}{9}\)
\(\frac{4}{5}\) - \(\frac{2}{7}\) = \(\frac{28}{35}\) - \(\frac{10}{35}\) = \(\frac{18}{35}\)
\(\frac{13}{9}\) : \(\frac{5}{6}\) = \(\frac{13}{9}\) x \(\frac{6}{5}\) = \(\frac{26}{15}\)
chúc bạn hok tốt !
\(\frac{2}{3}+\frac{3}{4}=\frac{8}{12}+\frac{9}{12}=\frac{17}{12}\)
\(\frac{5}{6}\) x \(\frac{4}{15}\) \(=\frac{5x6}{6x15}=\frac{1}{3}\)
\(\frac{4}{5}-\frac{2}{7}=\frac{28}{35}-\frac{10}{35}=\frac{18}{35}\)
\(\frac{13}{9}:\frac{5}{6}=\frac{13}{9}x\frac{6}{5}=\frac{13x6}{9x5}=\frac{26}{15}\)
Chúc bạn học tốt !
ta có \(\frac{3}{7}=\frac{3\times3}{7\times3}=\frac{9}{21}\)(quy đồng tử)
So sánh \(\frac{9}{21}\)và \(\frac{9}{17}\)ta có:
\(21>17\Rightarrow\frac{9}{17}>\frac{9}{21}\Rightarrow\frac{9}{17}>\frac{3}{7}\)
VẬY: \(\frac{9}{17}>\frac{3}{7}\)
a) \(\left(x+\frac{7}{4}\right)\times\frac{3}{2}=6\)
\(\Leftrightarrow\left(x+\frac{7}{4}\right)=6\div\frac{3}{2}\)
\(\Leftrightarrow x+\frac{7}{4}=4\)
\(\Leftrightarrow x=4-\frac{7}{4}\)
\(\Leftrightarrow x=\frac{9}{4}\)
b) \(x\div\frac{3}{5}+\frac{2}{5}=\frac{9}{5}\)
\(\Leftrightarrow x\div\frac{3}{5}=\frac{9}{5}-\frac{2}{5}\)
\(\Leftrightarrow x\div\frac{3}{5}=\frac{7}{5}\)
\(\Leftrightarrow x=\frac{7}{5}\times\frac{3}{5}\)
\(\Leftrightarrow x=\frac{21}{25}\)
c) \(\frac{1}{2}\div3+x=\frac{5}{3}\)
\(\Leftrightarrow\frac{1}{6}+x=\frac{5}{3}\)
\(\Leftrightarrow x=\frac{5}{3}-\frac{1}{6}\)
\(\Leftrightarrow x=\frac{3}{2}\)
a)\(\frac{19}{20}+\frac{1}{20}=1\)
\(\frac{20}{21}+\frac{1}{21}=1\)
vi \(\frac{1}{20}>\frac{1}{21}\) nen \(\frac{19}{20}<\frac{20}{21}\)
b) \(\frac{89}{88}-\frac{1}{88}=1\)
\(\frac{90}{89}-\frac{1}{89}=1\)
vi \(\frac{1}{88}>\frac{1}{89}nen\frac{89}{88}>\frac{90}{89}\)
c)\(\frac{2005}{2003}-\frac{2}{2003}=1\)
\(\frac{2003}{2001}-\frac{2}{2001}=1\)
vi \(\frac{2}{2003}<\frac{2}{2001}nen\frac{2005}{2003}<\frac{2003}{2001}\)
a) Ta thấy : 4/5 < 1 ; 15/14 > 1
nên 4/5 < 15/14
b) Ta thấy : 89/88 > 1 ; 100/101 < 1
nên 89/88 > 100/101
c) Ta có : 300/901 < 300/900 = 1/3
nên 300/901 < 1/3
d) Ta có : 5/10 = 1/2 = 1000/2000
Ta thấy 1000/2000 < 1001/2000
nên 5/10 < 1001/2000