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\(=3^2-\left(x-y\right)^2=\left[3-\left(x-y\right)\right]\left[3+\left(x-y\right)\right]=\left(3-x+y\right)\left(3+x-y\right)\)
\(9-x^2+2xy-y^2\)
\(=9-\left(x^2-2xy+y^2\right)\)
\(=3^2-\left(x-y\right)^2\)
\(=\left(3-x+y\right)\left(3-x-y\right)\)
Giải:
a) \(3x^2y-6xy^2\)
\(=3xy\left(x-2y\right)\)
Vậy ...
b) \(\left(2x-a\right)x^2-\left(2x-a\right)y\)
\(=\left(2x-a\right)\left(x^2-y\right)\)
\(=\left(2x-a\right)\left(x-\sqrt{y}\right)\left(x+\sqrt{y}\right)\)
Vậy ...
c) \(25a^2-c^2\)
\(=\left(5a-c\right)\left(5a+c\right)\)
Vậy ...
d) \(4-36x+81x^2\)
\(=2^2-2.2.9x+\left(9x\right)^2\)
\(=\left(2-9x\right)^2\)
Vậy ...
e) \(\left(x+7\right)2-\left(2x-9\right)2\)
\(=2\left[\left(x+7\right)-\left(2x-9\right)\right]\)
\(=2\left(x+7-2x+9\right)\)
\(=2\left(16-x\right)\)
Vậy ...
f) \(x^2-6x+8\)
\(=x^2-6x+9-1\)
\(=\left(x-3\right)^2-1\)
\(=\left(x-4\right)\left(x-2\right)\)
Vậy ...
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
Bài 1:
\(x^2-6x+9-y^2\)
\(=\left(x-3\right)^2-y^2\)
\(=\left(x-3+y\right)\left(x-3-y\right)\)
Bài 2:
\(x^2-x-12=0\)
\(\Leftrightarrow x^2-4x+3x-12=0\)
\(\Leftrightarrow x\left(x-4\right)+3\left(x-4\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x-4\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+3=0\\x-4=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-3\\x=4\end{array}\right.\)
1. x2+6x-9-y2
=-(x2-6x+y2)-32
=-(x-y)2-32
=(-x+y-3)(-x+y+3)
dat y^2+y=z cho gon
\(z^2-9z+20=z^2-4z-5z+20=z\left(z-4\right)-5\left(z-4\right)=\left(z-4\right)\left(z-5\right)\)
\(thaylai:\left(y^2+y-4\right)\left(y^2+y-5\right)\)
x2 - 3x + 3y - y2
= (x2 - y2) - (3x - 3y)
= (x - y)(x + y) - 3(x - y)
= (x - y)(x + y - 3)
= x2 - y2 - 3x+3y = (x-y)(x+y) -3(x-y)
= (x+y+3)(x-y)
nhớ chọn cho mk nha!!!!!!
a) 3x^2 y - 6xy^2 = 3xy ( x - 2y)
b) 9 - ( x- y)^2 = ( 3 )^2 - ( x- y)^2
= ( 3 -x + y )( 3 + x + y )
a/ \(3x^2y-6xy^2\)\(=3xy\left(x-2y\right)\) ( đây là p2 đặt nhân tử chung )
b/9-(x -y )2 =( 3 -x +y ) ( 3 + x+y ) ( dùng hđt số 3 để giải )