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19 tháng 9 2018

A = 6x4 - 5x3 + 4x2 + 2x - 1

   = 6x4 + 3x3 - 8x3 - 4x2 + 8x2 + 4x - 2x - 1

   = 3x3. ( 2x + 1 ) - 4x2 ( 2x + 1 ) + 4x ( 2x + 1 ) - ( 2x + 1 )

   = ( 2x + 1 ) ( 3x3 - 4x2 + 4x - 1 )

    = ( 2x + 1 ) ( 3x3 - x2 - 3x2 + x + 3x - 1 )

     = ( 2x + 1 ) [ x2 ( 3x - 1 ) - x ( 3x - 1 ) + ( 3x - 1 ) ]

     = ( 2x + 1 ) ( 3x - 1 ) ( x2 - x + 1 )

B = 4x4 + 4x3 + 5x2 + 8x - 6

    = 4x4 - 2x3 + 6x3 - 3x2 + 8x2 - 4x + 12x - 6

     = 2x3 ( 2x - 1 ) + 3x( 2x - 1 ) + 4x ( 2x - 1 ) + 6 ( 2x - 1 )

     = ( 2x - 1 ) ( 2x3 + 3x2 + 4x + 6 )

     = ( 2x - 1 ) [ x2 ( 2x + 3 ) + 2 ( 2x + 3 ) ]

      = ( 2x - 1 ) ( 2x + 3 ) ( x2 + 2 )

C = x4 + x3 - 5x2 + x - 6

   = x4 - 2x3 + 3x3 - 6x2 + x2 - 2x + 3x - 6 

   = x3 ( x - 2 ) + 3x2 ( x - 2 ) + x ( x - 2 ) + 3 ( x - 2 )

   = ( x - 2 ) ( x3 + 3x2 + x + 3 )

    = ( x - 2 ) [ x2 ( x + 3 ) + ( x + 3 ) ]

    = ( x - 2 ) ( x + 3 ) ( x2 + 1 ) 

15 tháng 7 2016

a)x^2-(a+b)x+ab

= x^2 - ax - bx + ab

= (x^2 - ax) - (bx - ab)

= x(x-a) - b(x-a)

= (x-b)(x-a) 

b)7x^3-3xyz-21x^2+9z

c)4x+4y-x^2(x+y)

= 4(x + y) - x^2(x+y)

= (4-x^2) (x+y)

= (2-x)(2+x)(x+y)

d) y^2+y-x^2+x

= (y^2 - x^2) + (x+y)

= (y-x)(y+x)+ (x+y)

= (y-x+1) (x+y)

e)4x^2-2x-y^2-y

= [(2x)^2 - y^2] - (2x +y)

= (2x-y)(2x+y) - (2x+y)

= (2x -y -1)(2x+y)

f)9x^2-25y^2-6x+10y

31 tháng 8 2021

ko biết làm

 

2: =(2x+1)^2-y^2

=(2x+1+y)(2x+1-y)

3: =x^2(x^2+2x+1)

=x^2(x+1)^2

4: =x^2+6x-x-6

=(x+6)(x-1)

5: =-6x^2+3x+4x-2

=-3x(2x-1)+2(2x-1)

=(2x-1)(-3x+2)

6: =5x(x+y)-(x+y)

=(x+y)(5x-1)

7: =2x^2+5x-2x-5

=(2x+5)(x-1)

8: =(x^2-1)*(x^2-4)

=(x-1)(x+1)(x-2)(x+2)

9: =x^2(x-5)-9(x-5)

=(x-5)(x-3)(x+3)

23 tháng 9 2017

. Ai đó giúp tôi đi mà ._.

28 tháng 9 2017

bài khó quá bạn ạ

3 tháng 7 2021

\(1.\)

\(4x^2-4x-3\)

\(=4x^2-2x+6x-3\)

\(=2x\left(2x-1\right)+3\left(2x-1\right)\)

\(=\left(2x+3\right)\left(2x-1\right)\)

\(2.\)

\(2x^2-5x-3\)

\(=2x^2-6x+x-3\)

\(=2x\left(x-3\right)+\left(x-3\right)\)

\(=\left(2x+1\right)\left(x-3\right)\)

\(3.\)

\(3x^2-5x-2\)

\(=3x^2+x-6x-2\)

\(=x\left(3x+1\right)-2\left(3x+1\right)\)

\(=\left(3x+1\right)\left(x-2\right)\)

\(4.\)

\(2x^2+5x+2\)

\(=2x^2+4x+x+2\)

\(=2x\left(x+2\right)+\left(x+2\right)\)

\(=\left(2x+1\right)\left(x+2\right)\)

3 tháng 7 2021

\(5.\)

\(6x^2-x-1\)

\(=6x^2-3x+2x-1\)

\(=2x\left(3x+1\right)-\left(3x+1\right)\)

\(=\left(2x-1\right)\left(3x+1\right)\)

\(6.\)

\(6x^2-6x-3\)

\(=3\left(2x^2-2x-1\right)\)

\(7.\)

\(15x^2-2x-1\)

\(=15x^2+3x-5x-1\)

\(=3x\left(5x+1\right)-1\left(5x+1\right)\)

\(=\left(5x+1\right)\left(3x-1\right)\)

\(8.\)

\(x^4-13x^2+36\)

\(=\left(x-3\right)\left(x^3+3x^2-4x-12\right)\)

\(=\left(x-3\right)\left(x-2\right)\left(x^2+5x+6\right)\)

\(=\left(x-3\right)\left(x-2\right)\left(x+2\right)\left(x+3\right)\)

1 tháng 10 2020

1) \(x^3+2x-3\)

\(=\left(x^3-x^2\right)+\left(x^2-x\right)+\left(3x-3\right)\)

\(=x^2\left(x-1\right)+x\left(x-1\right)+3\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+x+3\right)\)

2) \(x^3-6x+4\)

\(=\left(x^3-2x^2\right)+\left(2x^2-4x\right)-\left(2x-4\right)\)

\(=x^2\left(x-2\right)+2x\left(x-2\right)-2\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2+2x-2\right)\)

1 tháng 10 2020

3) \(x^3-2x^2+1\)

\(=\left(x^3-x^2\right)-\left(x^2-x\right)-\left(x-1\right)\)

\(=x^2\left(x-1\right)-x\left(x-1\right)-\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2-x-1\right)\)

4) \(x^3+5x^2-12\)

\(=\left(x^3+2x^2\right)+\left(3x^2+6x\right)-\left(6x+12\right)\)

\(=x^2\left(x+2\right)+3x\left(x+2\right)-6\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2+3x-6\right)\)

30 tháng 7 2021

a) `x^4+2x^3-4x-4`

`=(x^4-4)+(2x^3-4x)`

`=(x^2-2)(x^2+2)+2x(x^2-2)`

`=(x^2-2)(x^2+2+2x)`

b) `x^3-4x^2+12x-27`

`=(x^3-27)-(4x^2-12x)`

`=(x-3)(x^2+3x+9)-4x(x-3)`

`=(x-3)(x^2+3x+9-4x)`

`=(x-3)(x^2-x+9)`

c) `xy-4y-5x+20`

`=y(x-4)-5(x-4)`

`=(y-5)(x-4)`

a) Ta có: \(x^4+2x^3-4x-4\)

\(=\left(x^4-4\right)+2x^3-4x\)

\(=\left(x^2-2\right)\left(x^2+2\right)+2x\left(x^2-2\right)\)

\(=\left(x^2-2\right)\left(x^2+2x+2\right)\)

b) Ta có: \(x^3-4x^2+12x-27\)

\(=\left(x-3\right)\left(x^2+3x+9\right)-4x\cdot\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2-x+9\right)\)

c) Ta có: \(xy-4y-5x+20\)

\(=y\left(x-4\right)-5\left(x-4\right)\)

\(=\left(x-4\right)\left(y-5\right)\)

22 tháng 8 2021

\(1,2x^3+3x^2-8x+3\)

\(=2x^3-2x^2+5x^2-5x-3x+3\)

\(=2x^2\left(x-1\right)+5x\left(x-1\right)-3\left(x-1\right)\)

\(=\left(2x^2+5x-3\right)\left(x-1\right)\)

\(=\left(2x-1\right)\left(x+3\right)\left(x-1\right)\)

\(2,x^3-5x^2+2x+8\)

\(=x^3+x^2-6x^2-6x+8x+8\)

\(=x^2\left(x+1\right)-6x\left(x+1\right)+8\left(x+1\right)\)

\(=\left(x^2-6x+8\right)\left(x+1\right)\)

\(=\left(x-2\right)\left(x-4\right)\left(x+1\right)\)

\(3,-6x^3+x^2+5x-2\)

\(=-6x^3-6x^2+7x^2+7x-2x-2\)

\(=-6x^2\left(x+1\right)+7x\left(x+1\right)-2\left(x+1\right)\)

\(=\left(-6x^2+7x-2\right)\left(x+1\right)\)

\(=\left(-6x^2-3x-4x-2\right)\left(x+1\right)\)

\(=\left[-3x\left(2x+1\right)-2\left(2x+1\right)\right]\left(x+1\right)\)

\(=\left(-3x-2\right)\left(2x+1\right)\left(x+1\right)\)

\(4,3x^3+19x^2+4x-12\)

\(=3x^3+18x^2+x^2+6x-2x-12\)

\(=3x^2\left(x+6\right)+x\left(x+6\right)-2\left(x+6\right)\)

\(=\left(3x^2+x-2\right)\left(x+6\right)\)

\(=\left(3x-2\right)\left(x+1\right)\left(x+6\right)\)