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\(x^3+5x^2+5x+1\)
\(=\left(x+1\right)\left(x^2+x+1\right)+5x\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2+6x+1\right)\)
\(\left(x^2+5x\right)^2-2\left(x^2+5x\right)-24\\ =\left[\left(x^2+5x\right)^2-6\left(x^2+5x\right)\right]+\left[4\left(x^2+5x\right)-24\right]\\ =\left(x^2+5x\right)\left(x^2+5x-6\right)+4\left(x^2+5x-6\right)\\ =\left(x^2+5x-6\right)\left(x^2+5x+4\right)\\ =\left(x^2-x+6x-6\right)\left(x^2+4x+x+4\right)\\ =\left[x\left(x-1\right)+6\left(x-1\right)\right]+\left[x\left(x+4\right)+\left(x+4\right)\right]\\ =\left(x-1\right)\left(x+1\right)\left(x+4\right)\left(x+6\right)\)
8: \(=\left(x-2y\right)\cdot x\cdot\left(x+3\right)\)
9: \(=\left(5x+2\right)\left(x-3\right)-x\left(x-3\right)\)
\(=\left(x-3\right)\left(4x+2\right)\)
=2(2x+1)(x-3)
3: \(=2\left(x+2\right)\left(25x-15-x\right)\)
\(=2\left(x+2\right)\left(24x-15\right)\)
=6(x+2)(8x-5)
đặt a=x^2-5x
(x^2-5x)^2+10(x^2-5x+24)
=a^2+10(a+24)
=a^2+10a+24
=a^2+6a+4a+24
=a(a+6)+4(a+6)
=(a+6)(a+4)
=(x^2-5x+6)(x^2-5x+4)
=[x^2-3x-2x+6][x^2-x-4x+4]
=[x(x-3)-2(x-3)][x(x-1)+4(x-1)]
=(x-3)(x-2)(x-1)(x+4)
e ko bt phân tích đa thức thành nhân tử nên a tham khảo linh này nha
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\(5x^2-5x-10=5x^2+5x-10x-10=5x\left(x+1\right)-10\left(x+1\right)=\left(5x-10\right)\left(x+1\right)\)
5x2−5x−10=5x2+5x−10x−10=5x(x+1)−10(x+1)=(5x−10)(x+1)