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Ta có: \(\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{8\cdot9}+\dfrac{1}{9\cdot10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Leftrightarrow100\cdot\dfrac{9}{10}-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Leftrightarrow\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=1\)
\(\Leftrightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=2\)
\(\Leftrightarrow x=-\dfrac{81}{100}\)
Đề sai nhá bạn
Đề P = 1.2 + 2.3 + 3.4 + ...... + 19.20 (đúng)
Ta có ; P = 1.2 + 2.3 + 3.4 + ...... + 19.20
=> 3P = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ....... + 19.20.21
=> 3P = 19.20.21
=> P = 19.20.21 /3
=> P = 2660
3/2 . x + ( 5/3 - 3/2) : 2/3 = 5/3
3/2.x + 1/6 : 2/3 = 5/3
3/2.x + 1/4 = 5/3
3/2.x = 5/3 - 1/4
3/2.x=17/12
x= 17/12 : 3/2
x= 17/18
Vậy...
Bài 2:
4/5x7 + 4/7x9 + 4/9x11 +...+4/17x19
= 2(2/5.7 + 2/7.9 + 2/9.11+...+ 2/17/19)
= 2( 1/5 - 1/7 + 1/7 -1/9 + 1/9 -1/11 +...+ 1/17 - 1/19)
= 2( 1/5- 1/19)
= 2 . 14/95
= 28/95
Trả lời:
Bài 1
\(\frac{3}{2}\times x+\left(\frac{5}{3}-\frac{3}{2}\right)\div\frac{2}{3}=\frac{5}{3}\)
\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{6}\div\frac{2}{3}=\frac{5}{3}\)
\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{6}\times\frac{3}{2}=\frac{5}{3}\)
\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{4}=\frac{5}{3}\)
\(\Leftrightarrow\frac{1}{6}\times x=\frac{17}{12}\)
\(\Leftrightarrow x=\frac{17}{2}\)
Vậy \(x=\frac{17}{2}\)
a. \(\left(a^5\right)^7=a^{5.7}=a^{35}\)
b. \(\left(a^6\right)^4:a^{12}=a^{6.4}:a^{12}=a^{24}:a^{12}=a^{24-12}=a^{12}\)
c.\(\left(2^3\right)^5:\left(2^3\right)^3=2^{3.5}:2^{3.3}=2^{15}:2^9=2^{15-9}=2^6=64\)
d. \(\left(3^2\right)^4:\left(3^3\right)^2=3^{2.4}:3^{3.2}=3^8:3^6=3^{8-6}=3^2=9\)
\(\text{Ta thấy:}\text{ }\)
\(2^5-2^4-2^3-2^2-2-2=0\)
\(\Rightarrow\text{ Giá trị của biểu thức trên là 0}\)