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a, 9x - 2.3^2 = 3^4
=> 9x - 18 = 81
=> 9x = 99
=> x = 11
b, 10x + 2^2.5 = 10
=> 10x + 20 = 10
=> 10x = -10
=> x = - 1
\(9x-2\cdot3^2=3^4\)
\(\Rightarrow9x-18=81\)
\(\Rightarrow9x=81+18=99\)
\(\Rightarrow x=99:9=11\)
Bài 1 :
\(2^x.8=512\)
\(2^x=512:8\)
\(2^x=64\)
\(2^x=2^6\)
\(\Rightarrow x=6\)
\(b,\left(2x+1\right)^3=125\)
\(\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
\(c,x^{20}=x\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
\(d,\left(x-3\right)^{10}=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
\(5^x+5^{x+2}=650;5^x.26=650;5^x=25;x=2\)
\(2^x+2^{x+3}=144;2^x.9=144;2^x=16;x=4\)
\(3^{x-1}+5.3^{x-1}=162;3^{x-1}.6=162;3^{x-1}=27;x=4\)
\(\left(x-5\right)^4=\left(x-5\right)^6\)
\(\rightarrow x-5=0\&x-5=1\) hoặc x - 5 = - 1
\(x-5=1;x=6;x-5=0;x=5;x-5=-1;x=4\)
\(\left(2^2:4\right).2^n=4;2^n=2^2;n=2\)
\(2.3^x=10.3^{12}+8.27^4\)
\(\Rightarrow2.3^x=10.3^{12}+8.3^{12}\)
\(\Rightarrow2.3^x=3^{12}\left(10+8\right)=3^{12}.18\)
\(\Rightarrow3^x=3^{12}.18:2=3^{12}.3^2=3^{15}\)
\(\Rightarrow x=15\)
2.3^x=10.3^12+8.(3^3)^4
2.3^x=10.3^12+8.3^12
2.3^x=3^12.(10+8)
2.3^x=3^12.18
2.3^x=3^12.9.2
2.3^x=3^14.2
vậy x =14
\(2^{10}.2^{x+4}=64^5\)
\(\Leftrightarrow2^{x+14}=2^{30}\)
\(\Leftrightarrow x+14=30\)
\(\Leftrightarrow x=16\)
\(5^x+5^{x+3}=630\)
\(\Rightarrow5^x.1+5^x.125=630\)
\(\Rightarrow5^x.126=630\)
\(\Rightarrow5^x=5\)
\(\Rightarrow x=1\)
\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+..............+\left(x+100\right)=7450\)
\(\Rightarrow\left(x+x+x+x+.........+x\right)+\left(1+2+3+..........+100\right)=7450\)
\(101x+5050=7450\)
Đến đây tự tính
a) \(\left(x-21\right)^3-7=2^2.5\)
\(\left(x-21\right)^3=4.5+7=27\)
\(\left(x-21\right)^3=3^3\)
\(\Rightarrow x-21=3\Rightarrow x=24\)
Ta có 9 = 32
81 = 34
3n : 3 = 3n-1
suy ra 9 < 3n : 3 < 81
<=> 32 < 3n-1 < 34
=> n - 1 = 3
<=> n = 4
9 < 3n : 3 < 81
Ta có : 9 = 32 ; 81 = 34
=> 9 < 3n : 3 < 81 = 32 < 3n : 3 < 34
=> 3n : 3 = 33
3n = 33 +1 = 34
=> n = 4
\(\left(3-x\right)^{10x}:\left(3-x\right)^{10}=1\)
=> \(\left(3-x\right)^{10x-10}=1\)
=> \(\orbr{\begin{cases}3-x=1\\10x-10=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=1\end{cases}}}\)
Ta có:
(3-x)10x:(3-x)10=1
=> 2 số này bằng nhau
=> x=1
+) TH:
cơ số =1
=> x=2
Vậy x E {1;2}