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12 tháng 10 2018

x2-2x-4y2+1

=(x2-2x+12)-(2y)2

=(x-1)2-(2y)2

=(x-1-2y)(x-1+2y)

14 tháng 10 2022

a: \(=\left(x-1\right)^2-4y^2=\left(x-1-2y\right)\left(x-1+2y\right)\)

b: \(=3\left(x^2-4x+4\right)=3\left(x-2\right)^2\)

c: \(=4x^2y^3\left(3y^2-8xyz+7x^2\right)\)

d: \(=x^4+16x^2+64-16x^2=\left(x^2+8\right)^2-16x^2\)

\(=\left(x^2+8-4x\right)\left(x^2+8+4x\right)\)

c: \(=\left(x-y\right)\left(x+y\right)-2z\left(x-y\right)=\left(x-y\right)\left(x+y-2z\right)\)

24 tháng 9 2019

(x - y - z)^2 

= (x - y - z)(x - y - z)

= x^2 - xy - xz - xy + y^2 + zy - zx + zy + z^2

= xY2 + y^2 + z^2  - 2xy - 2xz + 2zy (đpcm)

24 tháng 9 2019

(x-y-z)(x-y-z) nhân phân phối vô 

3 tháng 9 2018

Ta có:

\(\left(x+y+z\right)^2\)

\(=\left[\left(x+y\right)+z\right]^2\)

\(=\left(x+y\right)^2+2\left(x+y\right)z+z^2\)

\(=x^2+2xy+y^2+2xz+2yz+z^2\)

\(=x^2+y^2+z^2+2xy+2xz+2yz\)

3 tháng 9 2018

có đúng ko bạn cho mk còn chép

8 tháng 8 2017

1) 2x2-8xy-5x+20y

=2x(x-4y)-5(x-4y)

=(2x-5)(x-4y)

2) x3-x2y-xy+y2

=x2(x-y)-y(x-y)

=(x2-y)(x-y)

3) x2-2xy-4z2+y2

=(x-y)2-(2z)2

=(x-y-2z)(x-y+2z)

4) a3+a2b-a2c-abc

=a2(a+b)-ac(a+b)

=(a2-ac)(a+b)

=a(a-c)(a+b)

5) x3+y3+3x2y+3xy2-x-y

=(x+y)(x2-xy+y2)+3xy(x+y)-(x+y)

=(x+y)(x2-xy+y2+3xy-1)

=(x+y)[(x+y)2-1)]

=(x+y)(x+y+1)(x+y-1)

6) x3+x2y-x2z-xyz

=x2(x+y)-xz(x+y)

=(x2-xz)(x+y)

=x(x-z)(x+y)

7) =[x(y+z)2-2xyz]+[y(z+x)2-2xyz]+z(x+y)2

=x(y2+z2)+y(z2+x2)+z(x+y)2

=xy(x+y)+z2(x+y)+z(x+y)2

=(x+y)(xy+z2+zx+zy)

=(x+y)(x+z)(y+z)

8) x3(z-y)+y3(x-z)+z3(y-x)

Tách x-z= -[z-y+y-x]

17 tháng 9 2018

a) \(x^2\left(y-z\right)+y^2\left(z-x\right)+z^2\left(x-y\right)\)

\(=x^2\left(y-z\right)-y^2\left[\left(y-z\right)+\left(x-y\right)\right]+z^2\left(x-y\right)\)

\(=x^2\left(y-z\right)-y^2\left(y-z\right)-y^2\left(x-y\right)+z^2\left(x-y\right)\)

\(=\left(y-z\right)\left(x^2-y^2\right)-\left(x-y\right)\left(y^2-z^2\right)\)

\(=\left(y-z\right)\left(x-y\right)\left(x+y\right)-\left(x-y\right)\left(y-z\right)\left(y+z\right)\)

\(=\left(x-y\right)\left(y-z\right)\left(x+y-y-z\right)\)

\(=\left(x-y\right)\left(y-z\right)\left(x-z\right)\)

17 tháng 9 2018

c) \(\left(x+y+z\right)^3-x^3-y^3-z^3\)

\(=\left[\left(x+y\right)+z\right]^3-x^3-y^3-z^3\)

\(=\left(x+y\right)^3+z^3+3z\left(x+y\right)\left(x+y+z\right)-x^3-y^3-z^3\)

\(=\left[\left(x+y\right)^3-x^3-y^3\right]+3z\left(x+y\right)\left(x+y+z\right)\)

\(=3xy\left(x+y\right)+3\left(x+y\right)\left(xz+yz+z^2\right)\)

\(=3\left(x+y\right)\left(xy+xz+yz+z^2\right)\)

\(=3\left(x+y\right)\left[x\left(y+z\right)+z\left(y+z\right)\right]\)

\(=3\left(x+y\right)\left(y+z\right)\left(x+z\right)\)

d) \(\left(x^2+y^2-5\right)^2-4x^2y^2-16xy-16\)

\(=\left(x^2+y^2-5\right)^2-\left(4x^2y^2+16xy+16\right)\)

\(=\left(x^2+y^2-5\right)^2-\left[\left(2xy\right)^2+2.2xy.4+16\right]\)

\(=\left(x^2+y^2-5\right)^2-\left(2xy+4\right)^2\)

\(=\left(x^2+y^2-5-2xy-4\right)\left(x^2+y^2-5+2xy+4\right)\)

\(=\left(x^2-2xy+y^2-9\right)\left(x^2+2xy+y^2-1\right)\)

\(=\left[\left(x-y\right)^2-3^2\right]\left[\left(x+y\right)^2-1\right]\)

\(=\left(x-y-3\right)\left(x-y+3\right)\left(x+y-1\right)\left(x+y+1\right)\)

e) \(\left(x^2+4y^2-5\right)^2-16\left(x^2y^2+2xy+1\right)\)

\(=\left(x^2+4y^2-5\right)^2-4^2\left(xy+1\right)^2\)

\(=\left(x^2+4y^2-5\right)^2-\left[4\left(xy+1\right)\right]^2\)

\(=\left(x^2+4y^2-5\right)-\left(4xy+4\right)^2\)

\(=\left(x^2+4y^2-5-4xy-4\right)\left(x^2+4y^2-5+4xy+4\right)\)

\(=\left(x^2+4y^2-4xy-9\right)\left(x^2+4y^2+4xy-1\right)\)

\(=\left[\left(x-2y\right)^2-3^2\right]\left[\left(x+2y\right)^2-1\right]\)

\(=\left(x-2y-3\right)\left(x-2y+3\right)\left(x+2y-1\right)\left(x+2y+1\right)\)

f) \(\left(x-y+5\right)^2-2\left(x-y+5\right)+1\)

\(=\left(x-y+5-1\right)^2\)

\(=\left(x-y+4\right)^2\)

1, 2x2 - 8xy - 5x + 20y

= (2x2 - 5x) - (8xy - 20y)

= x(2x - 5) - 4y(2x - 5)

= (2x - 5) (x - 4y)

2,  x- x2y - xy + y2

= (x3 - xy) - (x2y - y2)

= x(x2 - y) - y(x2 - y)

= (x2 - y) (x - y)

3, x2 - 2xy - 4z+ y2

= (x2 - 2xy + y2) - 4z2

= (x - y)2 - (2z)2 

= (x - y - 2z) (x - y + 2z)

4, a3 + a2b - a2c - abc

= (a3 - a2c) + (a2b - abc)

= a2(a - c) + ab(a - c)

= (a - c) (a2 + ab)

5, x+ y3 + 3x2y + 3xy- x - y

= (x3 + 3x2y + 3xy2 + y3) - (x + y)

= (x + y) 3 - (x + y)

= (x + y) [(x + y)2 - 1]

= (x + y) (x + y - 1) (x + y + 1)

4 tháng 10 2018

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