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A = 5 - 52 + 53 - 54 + ... - 598 + 599
<=> 5A = 52 - 53 + 54 - 55 + ... - 599 + 5100
<=> 5A + A = ( 52 - 53 + ...- 599 + 5100 ) + ( 5 - 52 + ... - 598 + 599)
<=> 6A = 5100 + 5
<=> A = 5100 + 5/6
cái cuối là A = \(\frac{5^{100}+5}{6}\)
hộ mình nhé :)
5A = 52 + 53 + 54 +...+ 5^100
=> 4A = 5A - A = 5^100 - 5 = 5(5^99-1)
=> A = 5(5^99-1)/4
A = 5 – 5^2 + 5^3 – 5^4 + …- 5^98 + 5^99 =>5A = 5^2 – 5^3 + 5^4 - …+ 5^98 – 5^99 + 5^100
Tính và rút gọn được 6A = 5 + 5^100
A=(5+5^100):6
Vậy A=(5+5^100):6
a)\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{98.99}+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}\)
\(=\frac{99}{100}\)
b)\(\frac{5}{11.16}+\frac{5}{16.21}+...+\frac{5}{61.66}\)
\(=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+....+\frac{1}{61}-\frac{1}{66}\)
\(=\frac{1}{11}-\frac{1}{66}\)
\(=\frac{5}{66}\)
a,\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{98.99}+\frac{1}{99.100}\)
ta có:
\(\frac{1}{1.2}=\frac{2-1}{1.2}=\frac{2}{1.2}-\frac{1}{1.2}=1-\frac{1}{2}\)
\(\frac{1}{2.3}=\frac{3-2}{2.3}=\frac{3}{2.3}-\frac{2}{2.3}=\frac{1}{2}-\frac{1}{3}\)
...
\(\frac{1}{99.100}=\frac{1}{99}-\frac{1}{100}\)
= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
=\(1-\frac{1}{100}=\frac{99}{100}\)
b,
\(\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.16}+...+\frac{5}{61.66}\)
ta có:
\(\frac{5}{11.16}=\frac{16-11}{11.16}=\frac{16}{11.16}-\frac{11}{11.16}=\frac{1}{11}-\frac{1}{16}\)
\(\frac{5}{16.21}=\frac{21-16}{16.21}=\frac{21}{16.21}-\frac{16}{16.21}=\frac{1}{16}-\frac{1}{21}\)
...
\(\frac{5}{61.66}=\frac{66-61}{61.66}=\frac{66}{61.66}-\frac{61}{61.66}=\frac{1}{61}-\frac{1}{66}\)
= \(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\)
=\(\frac{1}{11}-\frac{1}{66}\)=\(\frac{5}{66}\)
Bài 1
A = 1 + 3 + 32 + 33 + ... + 32014
3A = 3 + 32 + 33 + 34 + ... + 32015
3A - A = (3 + 32 + 33 + 34 + ... + 32015) - (1 + 3 + 32 + 33 + ... + 32014)
2A = 32015 - 1
A = \(\frac{3^{2015}-1}{2}\)
Bài 2
5 + 52 + 53 + 54 + ... + 596 + 597 + 598 + 599
= 5.(1 + 5 + 52) + 54.(1 + 5 + 52) + ... + 597.(1 + 5 + 52)
= 5.31 + 54.31 + ... + 597.31
= 31.(5 + 54 + 597) chia hết cho 31