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a) (18+12.3):9-5
=(18+36):9-5
=54:9-5
=6-5
=1
b) 368+42:7-(23+3)
= 368+42:7-(8+3)
= 368+42:7-11
= 368+6-11
=374-11
=363
c) 324 :322+3.4+3560
=324-22+12+1
=32+12+1
=9+12+1
=21+2
=22
d) 210:25-75:25+3.3
=210-5-3+9
=25-3+9
=32-3+9
=29+9
=38
e) 1449-[(216+184):23].32
=1449-(400:8).9
=1449-50.9
=1449-450
=999
f) 600-400:[118.2-2(50.3-9.16)2]
=600-400:[118.2-2(150-144)2]
=600-400:(118.2-2.62)
=600-400:(118.2-2.36)
=600-400:(236-72)
=600-400:164
=600-100/41
=24500/41 (đề sai)
g) 2001.27+2001.63+2001.10
=2001.(27+63+10)
=2001.100
=200100
h) 64.54+47.64-64
=64.(54+47-1)
=64.100
=6400
i) (-17)+15+68+17+(-15)
=(-17+17)+(-15+15)+68
=0+0+68
=68
j) (-17)+|-5|+|10|+(-11)
= (-17)+5+10+(-11)
=-12+10+(-11)
=-2+(-11)
=-13
k) -75+(-9)+4
=-84+4
=-80
l) -100+(-15+10)+|(-48)+(-22)|
=-100+(-5)+|-70|
=-100+(-5)+70
=-105+70
=-35
a) (18+12.3):9-5
=(18+36):9-5
=54:9-5
=6-5
=1
b) 368+42:7-(23+3)
= 368+42:7-(26)
=368+6-64
=374-64
=310
c) 324 :322+3.4+3560
=32+12+1
=9+12+1
=21+1
=22
d) 210:25-75:25+3.3
=25-3+9
=32-3+9
=29+9
=38
e) 1449-[(216+184):23].32
= 1449-[400:8].9
=1449-50.9
=1449-450
=999
f) 600-400:[118.2-2(50.3-9.16)2]
=600-400:[118.2-2.(150-9.16)2]
=600-400:[118.2-2.(150-144)2]
=600-400:[118.2-2.62]
=600-400:[118.2-2.36]
=600-400:[236-72]
=600-400:164
=Đề sai nha bạn
g) 2001.27+2001.63+20010
=2001.(27+63)+20010
=2001.100+20010
=200100+20010
=220110
h) 64.54+47.64-64
=64.(54+47-1)
=64.(101-1)
=64.100
=6400
i) (-17)+115+68+17+(-15)
=98+68+17+(-15)
=166+17+(-15)
=183+(-15)
=168
j) (-17)+|-5-|+|10|+(-11)
=(-17)+5+10+(-11)
=(-12)+5+10+(-11)
=-7+10+(-11)
=3+(-11)
=-8
k) -75+|(-9)+4|
=-75+|-5|
=-75+5
=-70
l) -100+(-15+10)+|(-48)+(-22)|
= -100+(-15+10)+|-70|
= -100+(-15+10)+70
=-100+(-5)+70
=-105+70
=-35
So sánh :
a ) 31^11 và 17^14
31^11 < 32^11= (25)11 = 2^55
=> 31^11 < 2^55
17^14>16^14=(24)14 = 2^56
=>17^14>2^56
=>31^11 < 2^55 < 2^56 < 17^14
=>31^11 < 17^14
b ) 3^500 và 7^300
3^500 = ( 35)100 = 243100
7^300 = ( 73)100 = 343100
=> 243100 < 343100
=> 3^500 < 7^300
Tìm x :
a ) 2x . 4 = 128
=> 2x = 32
=> 2x = 25
=> x = 5
b ) 2x . 22 = ( 23)2 = 64
=> 2x = 64 : 22 = 16
=> 2x = 24
=> x = 4
Bài cuối bạn tham khảo tại : Câu hỏi của Linh Phan - Toán lớp 6 - Học toán với OnlineMath
Link : https://olm.vn/hoi-dap/detail/198524999512.html
\(a.=\left(50-50\right)+\left(2+15\right)-17\)
\(=0+17-17\)
\(=0\)
a, -326-(115-326)=-326-(-326)-115=(-326+326)-115=-115
b,-13-18-(-42)-15=-13-18+42-15=-4
c,(-558+558)+(-50+50)=0+0=0
d,35-12+16=39
e,18.17-3.6.7=18.17-18.7=18.(17-7)=18.10=180
f,21.72-11.72+90.72+49.125.10
=21.72-11.72+90.72+72.1250
=72.(21-11+90+1250)
=72.1350=49.1350
=66150
a) Không thể vì: \(\dfrac{1}{1^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{100^2}=1+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{100^2}>1\)
b) Ta có: \(\dfrac{a}{b}< 1\) thì \(\dfrac{a}{b}>\dfrac{a-m}{b-m}\)
CM: \(\dfrac{a}{b}=\dfrac{a\cdot\left(b-m\right)}{b\cdot\left(b-m\right)}=\dfrac{ab-am}{b^2-bm}\left(1\right)\\ \dfrac{a-m}{b-m}=\dfrac{\left(a-m\right)\cdot b}{\left(b-m\right)\cdot b}=\dfrac{ab-am}{b^2-bm}\left(2\right)\)
Vì \(\dfrac{a}{b}< 1\Rightarrow a< b\Rightarrow am< bm\Rightarrow ab-am>ab-bm\left(3\right)\)
Từ (1), (2), (3) ta có \(\dfrac{a}{b}>\dfrac{a-m}{b-m}\)
Vậy
\(B=\dfrac{17^{19}-1}{17^{20}-1}>\dfrac{17^{19}-1-16}{17^{20}-1-16}=\dfrac{17^{19}-17}{17^{20}-17}=\dfrac{17\cdot\left(17^{18}-1\right)}{17\cdot\left(17^{19}-1\right)}=\dfrac{17^{18}-1}{17^{19}-1}=A\)
Vậy B > A
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