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10 tháng 11 2021

a=10 

b=-39

c=4

25+(15-x)=30                          43-(24-x)=20                       24+3(5-x)=27

      (15-x)=25+30=55                   (24-x)=43-20=23                  3(5-x)=27-24=3

            x =55-15=40                           x =24-23=1                      (5-x)=3:3=1

                                                                                                        x =5-1=4

Hok tốt!

@Kaito Kid

18 tháng 7 2015

a)25+(`15-x)=30

15-x=25-30

x=15-5

x=10

b)43-(24-x)=20

24-x=43-20

x=24-23

x=1

c)2.(x-50-17=25

2.(x-5)=25+17

x-5=42:2

x=21+5

x=26

d)3.(x+7)-15=27

3.(x+7)=15+27

x+7=42:3

x=14-7

x=7

`@` `\text {Ans}`

`\downarrow`

`c)`

`( 34 - 2x ) . ( 2x - 6 ) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

`( 2019 - x ) . ( 3x - 12 ) =0` `?`

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy, `x \in {2019; 4}`

`e) `

`57 . ( 9x - 27 ) = 0`

`=>`\(9x-27=0\div57\)

`=> 9x - 27 = 0`

`=> 9x = 27`

`=> x = 27 \div 9`

`=> x = 3`

Vậy, `x = 3`

`f)`

`25 + ( 15 - x ) = 30`

`=> 15 - x = 30 - 25`

`=> 15 - x = 5`

`=> x = 15 -5 `

`=> x = 10`

Vậy, `x = 10`

`g) `

`43 - ( 24 - x ) = 20`

`=> 24 - x = 43 - 20`

`=> 24 - x = 23`

`=> x = 24 - 23`

`=> x = 1`

Vậy, `x = 1`

`h) `

`2 . ( x - 5 ) - 17 = 25`

`=> 2 ( x - 5) = 25+17`

`=> 2 ( x - 5) = 42`

`=> x - 5 = 42 \div 2`

`=> x - 5 = 21`

`=> x = 21 + 5`

`=> x = 26`

Vậy, `x = 26`

`i)`

`3 . ( x + 7 ) - 15 = 27`

`=> 3(x + 7) = 27 + 15`

`=> 3(x + 7) = 42`

`=> x +7 = 42 \div 3`

`=> x + 7 = 14`

`=> x = 14 - 7`

`=> x = 7`

Vậy, `x = 7`

`j)`

`15 + 4 . ( x - 2 ) = 95`

`=> 4(x - 2) = 95 - 15`

`=> 4(x - 2) = 80`

`=> x - 2 = 80 \div 4`

`=> x - 2 = 20`

`=> x = 20 + 2`

`=> x = 22`

Vậy, `x = 22`

`k)`

`20 - ( x + 14 ) = 5`

`=> x + 14 = 20 - 5`

`=> x + 14 = 15`

`=> x = 15 - 14`

`=> x = 1`

Vậy, `x = 1`

`l) `

`14 + 3 . ( 5 - x ) = 27`

`=> 3(5 - x) = 27 - 14`

`=> 3(5 - x) = 13`

`=> 5 - x = 13 \div 3`

`=> 5 - x = 13/3`

`=> x = 5- 13/3`

`=> x = 2/3`

Vậy, `x = 2/3.`

`@` `\text {Kaizuu lv uuu}`

9 tháng 7 2023

nhanh mik tick cho nha

20 tháng 3 2020

a ) \(5.\left(x-7\right)=0\)

\(\Leftrightarrow x-7=5.0\)

\(\Leftrightarrow x-7=0\)

\(\Leftrightarrow x=7\)

b ) \(34.\left(2.x-6\right)=0\)

\(\Leftrightarrow2.x-6=34.0\)

\(\Leftrightarrow2.x-6=0\)

\(\Leftrightarrow2.x=0+6\)

\(\Leftrightarrow2.x=6\)

\(\Leftrightarrow x=6\div2\)

\(\Leftrightarrow x=3\)

c ) \(25+\left(15-x\right)=30\)

\(\Leftrightarrow25+\left(15-x\right)=-\left(x-40\right)\)

\(\Leftrightarrow-\left(x-40\right)=2.3.5\)

\(\Leftrightarrow40-x=30\)

\(\Leftrightarrow-x=-10\)

\(\Leftrightarrow x=10\)

d ) \(43-\left(24-x\right)=20\)

\(\Leftrightarrow24-x=43-20\)

\(\Leftrightarrow24-x=23\)

\(\Leftrightarrow x=24-23\)

\(\Leftrightarrow x=1\)

e ) \(2.\left(x-5\right)-17=25\)

\(\Leftrightarrow2.\left(x-5\right)=25+17\)

\(\Leftrightarrow2.\left(x-5\right)=42\)

\(\Leftrightarrow x-5=42\div2\)

\(\Leftrightarrow x-5=21\)

\(\Leftrightarrow x=21+5\)

\(\Leftrightarrow x=26\)

f ) \(24+3.\left(5-x\right)=27\)

\(\Leftrightarrow3.\left(5-x\right)=27-24\)'

\(\Leftrightarrow3.\left(5-x\right)=3\)

\(\Leftrightarrow5-x=3\div3\)

\(\Leftrightarrow5-x=1\)

\(\Leftrightarrow x=5-1\)

\(\Leftrightarrow x=4\)

g ) \(15\div x-2=3\)

\(\Leftrightarrow15\div x=3+2\)

\(\Leftrightarrow15\div x=5\)

\(\Leftrightarrow x=15\div5\)

\(\Leftrightarrow x=3\)

h ) \(\left(32-x\div5\right)\div13=2\)

\(\Leftrightarrow32-x\div5=2\times13\)

\(\Leftrightarrow32-x\div5=26\)

\(\Leftrightarrow x\div5=32-26\)

\(\Leftrightarrow x\div5=6\)

\(\Leftrightarrow x=5.6\)

\(\Leftrightarrow x=30\)

g ) \(\left(6-2x\right)\left(x-8\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}6-2x=0\\x-8=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=8\end{matrix}\right.\)

Vậy \(x\in\left\{3;8\right\}\)

Mình làm hết nhaa !!

21 tháng 3 2020

a)5.(x-7)=0

x-7=0:5

x-7=0

x=0+7

x=7

Vậy x=7

b)34.(2x-6)=0

2x-6 =0:34

2x-6 =0

2x=0+6

2x=6

x=6:2

x=3

Vậy x= 3

c)25+(15-x)=30

15-x=30-25

15-x=5

x=15-5

x=10

Vậy x=10

d)43-(24-x)=20

24-x =43-20

24-x=23

x=24-23

x=1

vậy x=1

e)2(x-5)-17=25

2(x-5)=25+17

2(x-5)=42

x-5=42:2

x-5=21

x=21+5

x=26

Vậy x=26

f)24+3(5-x)=27

3(5-x)=27-24

3(5-x)=3

5-x =3:3

5-x=1

x=5-1

x=4

Vậy x=4

g)15:x-2=3

15:x=3+2

15:x=5

x=15:5

x=3

Vậy x=3

h)( 32-x:5):13=2

32-x:5 =2.13

32-x :5=26

x:5= 32-26

x:5=6

x=6.5

x=30

Vậy x=30

k)(6-2x)(x-8)=0

➩6-2x=0 hoặc x-8=0

2x=6-0 x=0+8

2x=6 x=8

x=6:2

x=3

Vậy x=3 hoặc x=8

a) 

5.(12-x)-20=30

⇒60-5x-20=30

⇒-5x=30+20-60

⇒-5x=-10

⇒x=2

b)(17x - 25 ) : 8 + 65 = 92

(17x - 25 ) : 8 + 65 = 81

17x - 25 = 16 x 8 = 128

17x = 128+25=153

x= 153:17 =9

c)

x=23

Giải thích các bước giải:

3x – 10 = 2x + 13

3x-2x=13+10

x=23

d)4(2x+7)-3(3x-2)=24

4.2x+4.7-3.3x+3.2=24

8x+28-9x+6=24

8x-9x=24-28-6=-10

=>(-1)x=-10

        x=-10:(-1)

        x=10

2 tháng 3 2020

a. \(5\cdot\left(12-x\right)-20=30\Leftrightarrow5\left(12-x\right)=50\)

\(\Leftrightarrow12-x=50:5=10\)

\(\Leftrightarrow x=12-10=2\)

b. \(\left(17x-25\right):8+65=9^2\)

\(\Leftrightarrow\left(17x-25\right):8=81-65=16\)

\(\Leftrightarrow17x-25=16:8=2\)

\(\Leftrightarrow17x=2+25=27\Leftrightarrow x=\frac{27}{17}\)

c. \(3x-10=2x+13\)

\(\Leftrightarrow3x-2x=10+13\)

\(\Leftrightarrow x=23\)

d. \(4\cdot\left(2x+7\right)-3\cdot\left(3x-2\right)=24\)

\(\Leftrightarrow8x+28-9x+6=24\)

\(\Leftrightarrow34-x=24\Leftrightarrow x=10\)

8 tháng 7 2023

a) \(5\left(x-7\right)=0\)

\(\Rightarrow x-7=0\)

\(\Rightarrow x=7\)

b) \(25\left(x-4\right)=0\)

\(\Rightarrow x-4=0\)

\(\Rightarrow x=4\)

c) \(\left(34-2x\right)\left(2x-6\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

d) \(\left(2019-x\right)\left(3x-12\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)

e) \(57\left(9x-27\right)=0\)

\(\Rightarrow9x-27=0\)

\(\Rightarrow9\left(x-3\right)=0\)

\(\Rightarrow x-3=0\)

\(\Rightarrow x=3\)

8 tháng 7 2023

a) 5.(x-7)=0⇔x-7=0⇔x=7

b) 25(x-4)=0⇔x-4=0⇔x=4

c) (34-2x).(2x-6)=0

⇔ 34-2x=0 hoặc 2x-6=0

⇔2x=34 hoặc 2x=6

⇔ x=17 hoặc x=3

d) (2019-x).(3x-12)=0

⇔ 2019-x=0 hoặc 3x-12=0

⇔ x=2019 hoặc x=4

e) 57.(9x-27)=0

⇔ 9x-27=0

⇔ x=3

f) 25+(15-x)=30

⇔ 15-x=5

⇔ x=10

g) 43-(24-x)=20

⇔ 24-x=23

⇔ x=1

h) 2.(x-5)-17=25

⇔ 2(x-5)=42

⇔x-5=21

⇔ x=26

i) 3(x+7)-15=27

⇔ 3(x+7)=42

⇔ x+7=14

⇔ x=7

j) 15+4(x-2)=95

⇔ 4(x-2)=80

⇔ x-2=20

⇔ x=22

k) 20-(x+14)=5

⇔ x+14=15

⇔ x=1

l) 14+3(5-x)=27

⇔ 3(5-x)=13

⇔ 5-x=13/3

⇔ x=5-13/3

⇔ x=2/3

a) Ta có: \(18-x=58-\left(-30\right)\)

\(\Leftrightarrow18-x=88\)

\(\Leftrightarrow x=18-88=-70\)

Vậy: x=-70

b) Ta có: \(x-27=\left(-43\right)-9\)

\(\Leftrightarrow x-27=-43-9\)

\(\Leftrightarrow x-27=-52\)

\(\Leftrightarrow x=-25\)

Vậy: x=-25

c) Ta có: \(169-\left(x+4\right)=69\)

\(\Leftrightarrow x+4=169-69\)

\(\Leftrightarrow x+4=100\)

\(\Leftrightarrow x=96\)

Vậy: x=96

d) Ta có: \(\left(5x+3\right)-\left(-24+4\right)=33\)

\(\Leftrightarrow5x+3+24-4-33=0\)

\(\Leftrightarrow5x-10=0\)

\(\Leftrightarrow5x=10\)

\(\Leftrightarrow x=2\)

Vậy: x=2

e) Ta có: \(225-\frac{\left(5x+10\right)}{25}+5=-\left(-20\right)\)

\(\Leftrightarrow225-\frac{5x+10}{25}+5-20=0\)

\(-\frac{5x+10}{25}+210=0\)

\(\Leftrightarrow-\frac{5x+10}{25}=-210\)

\(\frac{5x+10}{25}=210\)

\(\Leftrightarrow5x+10=210\cdot25=5250\)

\(\Leftrightarrow5x=5250-10=5240\)

\(\Leftrightarrow x=1048\)

Vậy: x=1048

23 tháng 2 2020

e) 225 - ( 5x +10 ) : 25 +5 =-(-20)

225 - ( 5x +10 ) : 25 +5 = 20

( 5x +10 ) : 25 +5 =225 - 20

( 5x +10 ) : 25 +5= 205

( 5x +10 ) : 25= 205-5

( 5x +10 ) : 25= 200

( 5x +10 ) = 200 x 25

5x +10 = 5000

5x = 5000 - 10

5x = 4990

x = 4990 : 5

x = 998

12 tháng 7 2018

a) 25. (x-4) = 0

=> x -4 =0 

x = 4

b) 43 - (24-x) = 20

43 - 24 + x = 20

19 + x = 20

x = 1

c) 3.(x+7) - 15 = 27

3.x + 21 - 15 = 27

3.x + 6 = 27

3.x = 21

x = 7

d)... bn ghi thiếu đề r

e) (2.x-6).(x-7) = 0

=> 2.x -6 = 0 => 2x = 6 => x = 3

x - 7 = 0 => x  = 7

KL: x = 3 hoặc x = 7

phần d lm tương tự như phần f nha bn!
 

12 tháng 7 2018

a,25(x-4)=0

x-4=0

x=4

b,43-(24-x)=20

43-24+x=20

x=1

c,3(x+7)-15=27

3x+21-15=27

3x=21

x=7

d,(x-4)(x-12)=0

x-4=0=>x=4

x-12=0=>x=12

e,(2x-6)(x-7)=0

2x-6=0=>x=3

x-7=0=>x=7

f,(5x-10)(2x-8)=0

5x-10=0=>x=2

2x-8=0=>x=2

7 tháng 7 2018

a) 5. (x - 7) = 6

           x -7 = 6 : 5

             x   = 1.2 + 7

              x   = 8,2

b) 25 + (15 - x) =20

               15 - x= 20- 25

                      x = 20

c) 25 (x - 4) = 0

         x - 4  =  0 :25

           x    =   4

 d) 43 - (24 - x) = 20

               24 - x= 43 -20

                  x     = 24 - 23

                  x     = 1

6 tháng 7 2018

a) 5(x—7)=6

x—7=6:5

x—7=6/5

x=6/5+7

x=6/5+35/5

x=41/5

b) 25+(15–x)=20

15–x=20–25

15–x=—5

x=15–(—5)

x=20

c) 25(x—4)=0

x—4=0:25

x—4=0

x=0+4

x=4

d) 43–(24–x)=20

24–x=43–20

24–x=23

x=24–23

x=1