K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

\(a)\)

\(4x^2-y^2+2x+y\)

\(=\left(4x^2-y^2\right)+\left(2x+y\right)\)

\(=\left(2x-y\right)\left(2x+y\right)+\left(2x+y\right)\)

\(=\left(2x+y\right)\left(2x-y+1\right)\)

\(b)\)

\(x^3+2x^2-6x-27\)

\(=x^3+5x^2+9x-3x^2-15x-27\)

\(=x\left(x^2+5x+9\right)-3\left(x^2+5x-9\right)\)

\(=\left(x-3\right)\left(x^2+5-9\right)\)

\(c)\)

\(12x^3+4x^2-27x-9\)

\(=\left(12x^3+4x^2\right)-\left(27x+9\right)\)

\(=4x^2\left(3x+1\right)-9\left(3x+1\right)\)

\(=\left(3x+1\right)\left(4x^2-9\right)\)

\(=\left(3x+1\right)[\left(2x\right)^2-3^2]\)

\(=\left(3x+1\right)\left(2x-3\right)\left(2x+3\right)\)

\(d)\)

\(16x^2+4x-y^2+y^2\)

\(=16x^2+4x\)

\(4x\left(4x+1\right)\)

16 tháng 7 2018

1)  \(x^6-x^4-9x^3+9x^2\)

\(=x^2\left(x^4-x^2-9x+9\right)\)

\(=x^2\left[x^2\left(x^2-1\right)-9\left(x-1\right)\right]\)

\(=x^2\left(x-1\right)\left[x^2\left(x+1\right)-9\right]\)

\(=x^2\left(x-1\right)\left(x^3+x^2-9\right)\)

2)   \(x^4-4x^3+8x^2-16x+16\)

\(=x^2\left(x^2+4\right)-4x\left(x^2+4\right)+4\left(x^2+4\right)\)

\(=\left(x^2+4\right)\left(x-2\right)^2\)

18 tháng 7 2018

3) \(x^4-25x^2+20x-4=x^4+5x^3-2x^2-5x^3-25x^2+10x+2x^2+10x-4\)

\(=x^2\left(x^2+5x-2\right)-5x\left(x^2+5x-2\right)+2\left(x^2+5x-2\right)\)

\(=\left(x^2+5x-2\right)\left(x^2-5x+2\right)\)

4) \(5x\left(x-2y\right)+2\left(2y-x\right)^2\)\(=5x\left(x-2y\right)+2\left(x-2y\right)^2=\left(x-2y\right)\left(5x+2x-4y\right)=\left(x-2y\right)\left(7x-4y\right)\)

5) \(x^2\left(x^2-6\right)-x^2+9=x^4-7x^2+9\)

\(=x^4+x^3-3x^2-x^3-x^2+3x-3x^2-3x+9\)

\(=x^2\left(x^2+x-3\right)-x\left(x^2+x-3\right)-3\left(x^2+x-3\right)\)

\(=\left(x^2+x-3\right)\left(x^2-x-3\right)\)

6) \(7x\left(y-4\right)^2-\left(4-y\right)^3=7x\left(y-4\right)^2+\left(y-4\right)^3=\left(y-4\right)^2\left(7x+y-4\right)\)

7) \(x^3+2x^2-6x-27=x^3-3x^2+5x^2-15x+9x-27\)

\(=x^2\left(x-3\right)+5x\left(x-3\right)+9\left(x-3\right)=\left(x-3\right)\left(x^2+5x+9\right)\)

11 tháng 10 2017

b)3x^2-18x+27=3x^2-9x-9x+27=3x*(x-3)-9*(x-3)=(x-3)*(3x-9)=(x-3)*3*(x-3)=3*(x-3)^2

c)x^3-4x^2-12x+27=(x+3)*(x^2-3x+9-4)=(x+3)*(x^2-3x+5)

d)27x^3-1/27=(3x-1/3)*(9x^2-x+1/9)   (hang dt)

con a) voi e) mk chiu

7 tháng 10 2019

a) \(x^3+6x^2+12x+8\)

\(=\left(x+2\right)^3\)

b) \(x^3-3x^2+3x-1\)

\(=\left(x-1\right)^3\)

c) \(1-9x+27x^2-27x^3\)

\(=-\left(27x^3-27x^2+9x-1\right)\)

\(=-\left(3x-1\right)^3\)

7 tháng 10 2019

d) \(x^3+\frac{3}{2}x^2+\frac{3}{4}x+\frac{1}{8}\)

\(=\left(x+\frac{1}{2}\right)^3\)

e) \(27x^3-54x^2y+36xy^2-8y^3\)

\(=\left(3x-2y\right)^3\)

28 tháng 7 2015

??                       

7 tháng 8 2019

a) x3 - x2 - 5x + 125 = ( x\(^3\) + 125 ) - ( x\(^2\) + 5x ) = ( x + 5 ) ( x\(^2\) - 5x + 25 ) - x ( x + 5 )

= ( x + 5 ) ( x\(^2\) - 5x + 25 - x ) = ( x + 5 ) ( x\(^2\) - 6x + 25 )

b) x3 + 2x2 - 6x - 27 = ( x\(^3\) - 27 ) + ( 2x\(^2\) - 6x ) = ( x - 3 ) ( x\(^2\) + 3x + 9 ) + 2x ( x - 3 )

= ( x- 3 ) ( x\(^2\) + 3x + 9 + 2x ) = ( x - 3 ) ( x\(^2\) + 5x + 9 )

c) 12x3 + 4x2 - 27x - 9 = (12x3 + 4x2 ) - ( 27x + 9 ) = 4x\(^2\)( 3x + 1 ) - 9 ( 3x + 1 )

= ( 4x\(^2\) - 9 ) ( 3x -1 ) = ( 2x - 3 ) ( 2x + 3 ) ( 3x - 1 )

i) (x2 + 8x - 34)2 - (3x2 - 8x - 2)2

= (x2 + 8x - 34- 3x\(^2\) + 8x + 2) ( x\(^2\) + 8x - 34+3x2 - 8x - 2)

= ( -2x\(^2\) + 16x - 32 ) ( 4x\(^2\) - 36 )

= ( -2x\(^2\) + 16x - 32 ) ( 2x - 6 ) ( 2x + 6 )

8 tháng 8 2019

a, x3- x2- 5x+ 125

=- (x2+ 5x)+ (x3+125)

=-x(x+5)+ (x+5)(x2- 5x+ 25)

=(x+5)(-x+x2- 5x+ 25)

=(x+ 5)(x2- 6x+ 25)

12 tháng 8 2016

a) x3 - x2 - 5x + 125

=(x3-6x2+25x)+(5x2-30x+125)

=x(x2-6x+25)+5(x2-6x+25)

=(x+5)(x2-6x+25)

b) x3 + 2x2 - 6x - 27

=x3+5x2+9-3x2-15x-27

=x(x2+5x+9)-3(x2+5x+9)

=(x-3)(x2+5x+9)

c) 12x3 + 4x2 - 27x - 9

=4x2(3x+1)-9(3x+1)

=(4x2-9)(3x+1)

=[(2x)2-32](3x+1)

=(2x-3)(2x+3)(3x+1)

 

12 tháng 8 2016

a) \(x^3-x^2-5x+125\)

\(=\left(x^3+125\right)-\left(x^2+5x\right)\)

\(=\left(x+5\right)\left(x^2-5x+25\right)-x\left(x+5\right)\)

\(=\left(x+5\right)\left(x^2-5x+25-x\right)=\left(x+5\right)\left(x^2-6x+25\right)\)

b) \(x^3+2x^2-6x-27\)

\(=\left(x^3-27\right)+\left(2x^2-6x\right)\)

\(=\left(x-3\right)\left(x^2+3x+9\right)+2x\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2+3x+9+2x\right)\)

\(=\left(x-3\right)\left(x^2+5x+9\right)\)

c) \(12x^3+4x^2-27x-9\)

\(=4x^2\left(3x+1\right)-9\left(3x+1\right)\)

\(=\left(3x-1\right)\left(4x^2-9\right)=\left(3x-1\right)\left(2x-3\right)\left(2x+3\right)\)

24 tháng 10 2016

a) \(4x^2-8x+4-9\left(x-y\right)^2\)

\(=4\left(x^2-2x+1\right)-9\left(x-y\right)^2\)

\(=\left[2\left(x-1\right)\right]^2-\left[3\left(x-y\right)\right]^2\)

\(=\left(2x-2+3x-3y\right)\left(2x-2-3x+3y\right)\)

\(=\left(5x-3y-2\right)\left(3y-x-2\right)\)

b) \(x^3-4x^2+12x-27\)

\(=\left(x^3-27\right)-\left(4x^2-12x\right)\)

\(=\left(x-3\right)\left(x^2+3x+9\right)-4x\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2-x+9\right)\)

4 tháng 8 2017

Mình sửa: Bài 1
2)x2+3x-15

20 tháng 5 2018

a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2

b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)

                         = -(52 – 2 . 5 . x – x2) = -(5 – x)2

c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]

                    = (2x - 1/2)(4x2 + x + 1/4) 

d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)