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17.85+15.17-120
= 17(85+15)-120
=17.100-120
=1700-120
=1580
A = 12:{ 390 :[500-(125+35.7)]}
A=12:{ 390 :[500-(125+245)]}
A=12:{ 390 :[500-370]}
A=12:{ 390 :130}
A=12:3
A=4
75 - (3.52-4.23)
= 75 - ( 75 - 32)
= 75 - 43
= 32
B = 10+12+14+...+96+98
Tổng trên có số số hạng là:
(98-10):2+1=45 ( số )
\(\Rightarrow\text{B = 10+12+14+...+96+98}=\frac{\left(98+10\right).45}{2}=2430\)
17 . 85 + 15.17 - 120
= 17 ( 85 + 15 ) - 120
= 17 . 100 - 120
= 1700 - 120 = 1580
A = 12 : { 390 : [ 500 - ( 125 + 35 . 7 )]}
A = 12 : { 390 : [ 500 - ( 125 + 245 )]}
A = 12 : { 390 : [ 500 - 370 ]}
A = 12 : { 390 : 130 }
A = 12 : 3 = 4
75 - ( 3 . 52 - 4. 23 )
= 75 - ( 3 . 25 - 4 . 8 )
= 75 - ( 75 - 32 )
= 75 - 75 + 32
= 0 + 32 = 32
B = 10 + 12 + ... + 96 + 98
B có số số hạng là :
( 98 - 10 ) : 2 + 1 = 45 ( số )
B = ( 98 + 10 ) . 45 : 2 = 2430
a) 463+318+137+22
= (463+137)+(318+22)
= 600+340
= 940
b) 185.32-32.85
= 32.(185-85)
= 32 . 100
= 3200
c) \(15:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)
\(\text{= }15:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)
\(\text{= }15:\left\{390:\left[500-370\right]\right\}\)
\(=15:\left(390:130\right)\)
\(\text{= }15:3\)
\(\text{= }5\)
a)\(463+318+137+22\)
\(=\left(463+137\right)+\left(318+22\right)\)
\(=600+340=940\)
b)\(185.3^2-3^2.85\)
\(=3^2.\left(185-85\right)\)
\(=9.100=900\)
c)\(15:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)
\(=15:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)
\(=15:\left\{390:\left[500-370\right]\right\}\)
\(=15:\left\{390:130\right\}\)
\(=15:3=5\)
\(a)\)
\(\left(-31\right)+\left(50-19\right)-\left(150-31\right)\)
\(=\left(-31\right)+50-19-150+31\)
\(=\left(-150\right)-19\)
\(=-169\)
\(b)\)
\(25.\left(45-17\right)-45.\left(25-17\right)\)
\(=25.45-25.17-45.25+45.17\)
\(=0\)
\(c)\)
\(\frac{-1}{12}+\frac{4}{3}=\frac{5}{4}\)
\(d)\)
\(3+\frac{-5}{20}+\frac{30}{75}+\frac{-7}{4}\)
\(=\left(\frac{3}{5}+\frac{30}{75}\right)-\left(\frac{5}{20}+\frac{7}{4}\right)\)
\(=1-2\)
\(=-1\)
a) (-31)+(50-19)-(150-31)
= (-31)+50+(-19)-150+(-31)
= (-31)+50-150+(-19)-(-31)
= (-31)+(-100)+12
= -119
b) 25(45-17)-45(25-17)
= 25.45-25.17-45.25-45.17
= 25(45-45)-25(17-17)
= 0
c) -1/12 + 4/3
= -1/12 + 16/12
= 15/12
= 5/4
d) 3/5+(-5)/20+30/75+(-7)/4
= 45/75+30/75+(-5)/20+(-35)/20
= 1+(-2)
= -1
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\(-\frac{2}{3}+\frac{1}{5}.\frac{-10}{7}\\ =-\frac{2}{3}+\frac{1.-10}{5.7}\\ =-\frac{2}{3}+\frac{-2}{7}\\ =-\frac{14}{21}+\frac{-6}{21}\\ =-\frac{20}{21}\)
=\(\frac{-2}{3}+\frac{1}{5}.\frac{-10}{7}\)
=\(\frac{-2}{3}+\frac{-2}{7}\)
=\(\frac{-20}{21}\)