Question

[Dương Minh Hằng]

Bài 1 : thực hiên jpheps tính :

A=8/7+4/7.-6/11-4/11.5/11

B= 1/5:1/10-1/3.[6/5-(2-1/2)^2] + (-1/2)^3 

Bài 2 : 

a) 3/4 +1/4 : x =-3

(x-1/3)^2+5/9 =1 

Answer 1

[Akai Haruma]

Bài 1:

\(A=\frac{8}{7}+\frac{4}{11}(\frac{-6}{7}-\frac{5}{11})=\frac{8}{7}+\frac{-404}{847}=\frac{564}{847}\)

\(B=\frac{1}{5}.10-\frac{1}{3}.\frac{-21}{20}-\frac{1}{8}=2+\frac{7}{20}-\frac{1}{8}=\frac{89}{40}\)

Answer 2

[Akai Haruma]

Bài 2:

a.

$\frac{3}{4}+\frac{1}{4}:x=-3$

$\frac{1}{4}:x =-3-\frac{3}{4}=\frac{-15}{4}$
$x=\frac{1}{4}: \frac{-15}{4}=\frac{-1}{15}$

b.

$(x-\frac{1}{3})^2=1-\frac{5}{9}=\frac{4}{9}=(\frac{2}{3})^2=(\frac{-2}{3})^2$
$\Rightarrow x-\frac{1}{3}=\frac{2}{3}$ hoặc $x-\frac{1}{3}=\frac{-2}{3}$

$\Rightarrow x=1$ hoặc $x=\frac{-1}{3}$