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a) \(x+\frac{4}{5}=\frac{3}{2}\)
\(\Rightarrow x=\frac{3}{2}-\frac{4}{5}\)
\(\Rightarrow x=\frac{7}{10}\)
Vậy \(x=\frac{7}{10}.\)
b) \(x-\frac{3}{2}=\frac{11}{4}\)
\(\Rightarrow x=\frac{11}{4}+\frac{3}{2}\)
\(\Rightarrow x=\frac{17}{4}\)
Vậy \(x=\frac{17}{4}.\)
c) \(\frac{25}{3-x}=\frac{5}{6}\)
\(\Rightarrow\left(3-x\right)5=25.6\)
\(\Rightarrow15-5x=150\)
\(\Rightarrow5x=15-150\)
\(\Rightarrow5x=-135\)
\(\Rightarrow x=-135:5\)
\(\Rightarrow x=-27\)
Vậy \(x=-27.\)
a] 4/12 ; 5/12 ; 11/2 ; 1/4
b] 1 ; 9/12; 12/5 ; 11/3
c] 8/21; 6/11;8/7
d] 2/3 ;2/7 15/2
a]1/3 5/12 11/2 1/4
b]1 3/4 12/5 33/9
c]8/21 6/11 8/7
d]2/3 2/7 15/2
(2+4+...+16+18) x (45 x 3+ 5 x 45 - 90 x 4)
= A x (135 + 225 - 360)
= A x 0
= 0
1a) \(\frac{12}{17}+\frac{19}{17}+\frac{8}{17}\)
\(=\left(\frac{12}{17}+\frac{8}{17}\right)+\frac{19}{17}\)
\(=\frac{20}{17}+\frac{19}{17}\)
\(=\frac{39}{17}\)
b) \(\frac{2}{5}+\frac{7}{12}+\frac{13}{12}\)
\(=\frac{2}{5}+\frac{5}{3}\)
\(=\frac{31}{15}\)
2) \(\frac{25}{3}-x=\frac{5}{6}\)
\(x=\frac{25}{3}-\frac{5}{6}\)
\(x=\frac{45}{6}\)
ủng hộ tớ nha
\(1)\frac{12}{7}\times \frac{7}{4}+\frac{35}{11}:\frac{245}{121}\)
\(=3+\frac{35}{11}\times \frac{121}{245}\)
\(=3+\frac{11}{7}\)
\(= 3\frac{1}{7}(=\frac{22}{7})\)
a) \(11\times\left(x-6\right)=x\times4+11\)
\(11\times x-66=x\times4+11\)
\(\Rightarrow11\times x-x\times4=11+66\)
\(x\times\left(11-4\right)=77\)
\(x\times7=77\)
\(x=77:7\)
\(x=11\)
b) \(12:x+4=3+25:5\)
\(12:x+4=3+5\)
\(12:x+4=8\)
\(12:x=8-4\)
\(12:x=4\)
\(x=12:4\)
\(x=3\)
11 x x - 66 = x x 4 + 11
11 x x - x x 4 = 66 + 11
x x 7 = 77
x = 77 : 7
x = 11
12 : x + 4 = 3 + 5
12 : x + 4 = 8
12 : x = 8 - 4
12 : x = 4
x = 12 : 4
x =3