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a) 5X-2-32=24-( 28 .24-210.22)
5X-2-9=16-( 28+4-210+2)
5X-2-9=16-( 212-212)
5X-2-9=16-0
5X-2-9=16
5X-2=16+9
5X-2=25
5X-2=52
=>x-2=2
x=2+2
x=4
b)697 :[ ( 15 .x+ 64) :x]=17
k biết
c) 134: ( x-3 )= 35+ 160:5
134: ( x-3 )= 35+32
134: ( x-3 )= 67
x-3=134:67
x-3=2
x=2+3
x=5
d) ( 3. x - 24) .73-2.74
đề thiếu
e) [(10-x).2-5 ] : 3-2=3
[(10-x).2-5 ] : 3=3+2
[(10-x).2-5 ] : 3=5
(10-x).2-5=5x3
(10-x).2-5=15
(10-x).2=15+5
(10-x).2=20
10-x=20:2
10-x=10
x=10-10
x=0
Dãy số có 2 chữ số chia hết cho 3 là:[12,15,....,99]
Khoảng cách của từng số hạng là 3
Số số hạng là: (99-12):3+1=30(số)
Vậy có 30 số có 2 chữ số chia hết cho 3
a) \(93+3\left(x-5\right)=3.5^2=75\\ =>3\left(x-5\right)=75-93=-18\\ =>x-5=\dfrac{-18}{3}=-6\\ =>x=-6+5=-1\)
b, \(\left(5x^3+2^2.11\right):3^2=5\\ < =>\left(5x^3+44\right):9=5\\ =>5x^3+44=5.9=45\\ =>5x^3=45-44=1\\ =>x^3=\dfrac{1}{5}\\ =>x=\sqrt[3]{\dfrac{1}{5}}\)
Bài 1 tự làm!
Bài 2:
a, \(\left(3x-4\right)\left(x-1\right)^3=0\Rightarrow\left[{}\begin{matrix}3x-4=0\\\left(x-1\right)^3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=1\end{matrix}\right.\)
b, \(2^{2x-1}:4=8^3\Rightarrow2^{2x-1}:2^2=2^9\)
\(\Rightarrow2x-1-2=9\Rightarrow2x-3=9\Rightarrow2x-12\Rightarrow x=6\)
c, Đề chưa rõ
d, \(\left(x+2\right)^5=2^{10}\Rightarrow\left(x+2\right)^5=4^5\Rightarrow x+2=4\Rightarrow x=2\)
e, \(\left(3x-2^4\right).7^3=2.7^4\Rightarrow3x-2^4=2.7^4:7^3\Rightarrow3x-16=2.7=14\)
\(\Rightarrow3x=14+16=30\Rightarrow x=\dfrac{30}{3}=10\)
f, \(\left(x+1\right)^2=\left(x+1\right)^0\Rightarrow\left(x+1\right)^2=1\) (vì x0 = 1)
\(\Rightarrow x+1=1\Rightarrow x=0\)
a) 135 - 5(x + 4) = 35
<=> 135 - 5x - 20 = 35
<=> 115 - 5x = 35
<=> 5x = 115 - 35
<=> 5x = 80
<=> x = 16
b) 25 + 3 (x - 8) = 106
=> 3 ( x - 8) = 106 - 25
=> 3 ( x - 8) = 81
=> ( x - 8) = 81: 3
=> x - 8 = 27
=> x = 27 + 8
=> x = .......
a) 2(x-51) = 2^0.2^4 + 5.2^2
2(x-51) = 2^2(2^2+5)
2(x-51) = 36
x-51 = 18
x = 69
Vậy: x = 69
b) 225 : (x-19) = 25
x-19 = 9
x = 28
Vậy: x = 28
c) 4. (x-3)= 7^2-1^0
4. (x-3)= 48
x-3 = 12
x = 15
Vậy: x = 15
d) 3^3(x+4) - 3.5^2= 15.2^2
27 (x+4) - 75 = 60
27 (x+4) = 135
x+4 = 5
x = 1
Vậy: x = 1
e) 2x-7^2 = 5.3^2
2x - 49 = 45
2x = 94
x = 47
Vậy: x = 47
f) 2^3.5^2-(2x+6) = 4^3
200 - 2x - 6 = 64
194 - 2x = 64
2x = 130
x = 65
Vậy: x = 65
g) 135 - 5(x+4) = 35
5(x+4) = 100
x + 4 = 20
x = 16
Vậy: x = 16
h) 75 + 9(x-8) = 318
9(x-8) = 243
x-8 = 27
x = 35
Vậy: x = 35
a) (x : 3 - 4) . 5 = 15
x : 3 - 4 = 15 : 5
x : 3 - 4 = 3
x : 3 = 3 + 4
x : 3 = 7
x = 7 . 3
x = 21.
b) 128 - 3 . (x + 4) = 23
3 . (x + 4) = 128 - 23
3 . (x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31.
c) (3x - 24) . 73 = 2 . 74
3x - 24 = 2 . 74 : 73
3x - 24 = 2 . 7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10.
d) 5x + x = 39 - 311 : 39
5x + x = 39 - 32
5x + x = 39 - 9
6x = 30
x = 30 : 6
x = 5.
a) \(\left(\dfrac{x}{3}-4\right).5=15\)
\(\Leftrightarrow\dfrac{x}{3}-4=\dfrac{15}{5}\)
\(\Leftrightarrow\dfrac{x}{3}-4=3\)
\(\Leftrightarrow\dfrac{x}{3}=3+4\)
\(\Leftrightarrow\dfrac{x}{3}=7\)
\(\Leftrightarrow x=7.3\)
\(\Leftrightarrow x=21\)
Vậy \(x=21\)
b) \(128-3\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=128-23\)
\(\Leftrightarrow3\left(x+4\right)=105\)
\(\Leftrightarrow x+4=\dfrac{105}{3}\)
\(\Leftrightarrow x+4=35\)
\(\Leftrightarrow x=35-4\)
\(\Leftrightarrow x=31\)
Vậy \(x=31\)
c) \(\left(3x-2^4\right).7^3=2.7^4\)
\(\Leftrightarrow3x-2^4=\dfrac{2.7^4}{7^3}\)
\(\Leftrightarrow3x-2^4=2.7\)
\(\Leftrightarrow3x-2^4=14\)
\(\Leftrightarrow3x-16=14\)
\(\Leftrightarrow3x=14+16\)
\(\Leftrightarrow3x=30\)
\(\Leftrightarrow x=\dfrac{30}{3}\)
\(\Leftrightarrow x=10\)
Vậy \(x=10\)
d) \(5x+x=39-3^{11}:3^9\)
\(\Leftrightarrow6x=39-3^{11-9}\)
\(\Leftrightarrow6x=39-3^2\)
\(\Leftrightarrow6x=39-9\)
\(\Leftrightarrow6x=30\)
\(\Leftrightarrow x=\dfrac{30}{6}\)
\(\Leftrightarrow x=5\)
Vậy \(x=5\)
Bài 1: Tìm X
a, 32.(x+4)-52=5.22
⇒ 32 .(x+4)-25 =20
⇒9 . (x+4) = 20+25=45
⇒ x+4 = 45: 9 = 5
⇒ x = 5-4 = 1
Vậy x = 1
b,5x+x=39-311:39
⇒ 6x = 39 - 32 =39-9=30
⇒ x = 30 : 6 = 5
Vậy x = 5
c(3x -24 ).73 =2.74
⇒ 3x -24 = 2 . 74 : 73
⇒ 3x - 16 = 2 . 7 = 14
⇒ 3x = 14+16=30
Mà 33=27 , 34 = 81
⇒ x = ∅
Bài 2
a, 66.25+5.66+66.14+33.66
= 66 . ( 25+5+14+33 )
= 66 . 77 = 5082
87 _(321_x ) ÷ 5 = 75
(321 _ x ) ÷ 5 = 87_75
(321 _ x ) ÷5 = 12
(321 _ x) = 12 ×5
321 _ x = 60
X = 321_60
X = 261
2)( 5x _24) × 73 = 2 × 74
(5x _ 24 ) = 2×74÷73
( 5x _ 16) = 2×7
5x _ 16 = 14
5x = 14+ 16
5x = 30
X = 30÷5
X = 6
3)93 + 3×(x_5) = 3×52
93+ 3× ( x _ 5) = 75
3×( x _ 5) = 75_93
3×(x _ 5 ) = _18
(X _ 5) = _18 ÷ 3
X _ 5 = _6
X = _6 + 5
X = _1
Tớ chưa kịp làm tối về giải sau