Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
a)-84:4+3^9:3^7+5^0
=-21+(3^9:3^7)+1
=-21+3^2+1
=-21+9+1
=-12+1
=-11
b)295-(31-2^5.5)^2
=295-(31-32.5)^2
=295-(-129)^2
=295+129^2
=295-16641
=-16346
tick cho mk nha bạn
a) -84 : 4 + 3^ 9 : 3 ^ 7 + 5 ^0
=-84:4+3^2+1
=-84:4+9+1
=-21+9+1
=-12+1
=-11
b) 295 - ( 31 - 2^ 5. 5) ^2
= 295 - ( 31 -32. 5)^2
= 295 - (-129)^2
=295-16641
=-16346
a,\(2^4\cdot3^5:6^4\)
\(=\frac{2^4\cdot3^6}{\left(2\cdot3\right)^4}\)
\(=\frac{2^4\cdot3^6}{2^4\cdot3^4}\)
\(=3^2\)
Bài 2
\(a,5^3\cdot8=5^3\cdot2^3=10^3=1000\)
\(b,2^5-2019^0=32-1=31\)
\(c,3^3+2^5-1^{10}=27+32-1=58\).
\(d,9^2\cdot33-81\cdot23+5^2=81\cdot33-81\cdot23+25\)
\(=81\cdot\left(33-23\right)+25\)
\(=810+25=835\)
\(g,\left[2^2+6^2\right]:5+11^2\)
\(=\left[4+36\right]:5+121\)
\(=40:5+121=8+121\)
\(=129\)
\(d,\frac{14\cdot3^{10}-5\cdot3^{10}}{3^{12}}\)
\(=\frac{3^{10}\cdot\left(14-5\right)}{3^{12}}\)
\(=\frac{3^{10}\cdot9}{3^{12}}\)
\(=\frac{3^{10}\cdot3^2}{3^{12}}=\frac{3^{12}}{3^{12}}\)
\(=1\)
a,\(\dfrac{3^6.5^7.7^{11}}{3^4.5^7.7^{10}}=\dfrac{3^4.3^2.5^7.7^{10}.7}{3^4.5^7.7^{10}}\) \(=9.7=63\)
b,\(\dfrac{2^{43}+2^4}{2^{39}+1}=\dfrac{2^{39}.2^4+2^4}{2^{39}+1}\) \(=\dfrac{2^4\left(2^{39}+1\right)}{2^{39}+1}=16\)
a)\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{-5}{9}\)
b)\(\frac{\left(-11\right)^5.13^7}{11^5.13^8}=-\frac{1}{13}\)
c)\(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.3^9\left(3-1\right)}{2^9.3^{10}}=2\)
d(\(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.7^{11}\left(7+1\right)}{5^{11}.7^{11}\left(35+9\right)}=\frac{1}{6}\)